Class 9 Exam  >  Class 9 Tests  >  Online MCQ Tests for Class 9  >  Test: Parallelograms Basic Properties - Class 9 MCQ

Test: Parallelograms Basic Properties - Class 9 MCQ


Test Description

15 Questions MCQ Test Online MCQ Tests for Class 9 - Test: Parallelograms Basic Properties

Test: Parallelograms Basic Properties for Class 9 2024 is part of Online MCQ Tests for Class 9 preparation. The Test: Parallelograms Basic Properties questions and answers have been prepared according to the Class 9 exam syllabus.The Test: Parallelograms Basic Properties MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Parallelograms Basic Properties below.
Solutions of Test: Parallelograms Basic Properties questions in English are available as part of our Online MCQ Tests for Class 9 for Class 9 & Test: Parallelograms Basic Properties solutions in Hindi for Online MCQ Tests for Class 9 course. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free. Attempt Test: Parallelograms Basic Properties | 15 questions in 15 minutes | Mock test for Class 9 preparation | Free important questions MCQ to study Online MCQ Tests for Class 9 for Class 9 Exam | Download free PDF with solutions
Test: Parallelograms Basic Properties - Question 1

In a parallelogram ABCD, if ∠A = 115°, then ∠B, ∠C and ∠D are

Detailed Solution for Test: Parallelograms Basic Properties - Question 1

In a parallelogram ABCD, ∠D = 115° (Given)

Since, ∠A and ∠D are adjacent angles of parallelogram. 

We know, Adjacent angles of a parallelogram are supplementary. 

∠A + ∠D = 180° 

∠A = 180° – 115°  = 65° 

Measure of ∠A is 65°.

Test: Parallelograms Basic Properties - Question 2

Choose the correct statement

1 Crore+ students have signed up on EduRev. Have you? Download the App
Test: Parallelograms Basic Properties - Question 3

Which of the following is not a parallelogram?

Test: Parallelograms Basic Properties - Question 4

In the figure ABCD is a ||gm in which ∠DAB = 80° and ∠DBC = 60°, then ∠CDB and ∠ADB are equal to

Test: Parallelograms Basic Properties - Question 5

A quadrilateral is a ______ if a pair of opposite sides is equal and parallel

Detailed Solution for Test: Parallelograms Basic Properties - Question 5
Parallelogram because it have pair of opposite sides are equal and parallel
Test: Parallelograms Basic Properties - Question 6

If every pair of adjacent sides of a quadrilateral are equal, then the quadrilateral is a

Test: Parallelograms Basic Properties - Question 7

In a parallelogram ABCD, if ∠A = 60°, then ∠D is equal to:

Test: Parallelograms Basic Properties - Question 8

Each diagonal of a parallelogram divides it into two

Test: Parallelograms Basic Properties - Question 9

Statement 1: AB||DC and AD||BC 

Statement 2: AB = DC and AD=BC or a quadrilateral ABCD to be a parallelogram,__________

Detailed Solution for Test: Parallelograms Basic Properties - Question 9

ABCD is quadrilateral. AB=CD and AD=BC
Since the opposite sides of the quadrilateral are equal and AB parallel to DC. Therefore, the quadrilateral ABCD is a parallelogram.
hence, opposite sides are parallel to each other.
Or, AB∥CD and AD∥BC

Test: Parallelograms Basic Properties - Question 10

Perimeter of a parallelogram is 22 cm. If the longer side, measures 6.5 cm, the measure of the shorter side will be:​

Detailed Solution for Test: Parallelograms Basic Properties - Question 10
Let the length of the shorter side be x cm
length of longer side= 6.5 cm
perimeter= 22 cm
>2[sum of adjacent sides]=22
>2[longer side+shorter side]=22
>2[6.5+x] = 22 = 22/2 =11
>6.5 + x =11 = 11 - 6.5 = 4.5
> x= 4.5
Test: Parallelograms Basic Properties - Question 11

In the figure ABCD is a square. A line segment DX cuts the side BC at X and the diagonal AC at O such that ∠COD = 105° and ∠OXC = y. Then y is equal to

Detailed Solution for Test: Parallelograms Basic Properties - Question 11
Given :In the figure ABCD is a square. A line segment DX cuts the side BC at X and the diagonal AC at O such that COD = 105 degree and OXC = y
To find :y 
Since DX is a line segment, then 
angle COD + angle COX = 180 degrees {Angle sum property}
=> angle COX = 180 -105 = 75 degrees..(1)
Since ABCD is a square and AC is a diagonal , therefore all the angles in a square is 90 degree each and AC bisects the angle in half. {property}
=> angle ACB {  also OCX } = 90 /2 =45 degrees...(2)
In traingle COX 
=> angle OCX + angle COX  + y = 180 degree { sum of angles in a triangle is 180 degree}
=> y = 180 - (45+75) {using eq 1 and 2}
=> y = 60 degrees Answer
Test: Parallelograms Basic Properties - Question 12

Which of the following is not true for a parallelogram?

Test: Parallelograms Basic Properties - Question 13

In a parallelogram, if ∠A = (2x +25)° and ∠B = (3x – 5)°, the value of x is

Test: Parallelograms Basic Properties - Question 14

If an angle of a parallelogram is four-fifths of the adjacent angle, then the angles of the parallelogram are​

Test: Parallelograms Basic Properties - Question 15

In fig., PQRS is a parallelogram in which ∠PSR = 125°, ∠RQT is equal to

5 docs|319 tests
Information about Test: Parallelograms Basic Properties Page
In this test you can find the Exam questions for Test: Parallelograms Basic Properties solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Parallelograms Basic Properties, EduRev gives you an ample number of Online tests for practice

Top Courses for Class 9

Download as PDF

Top Courses for Class 9