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CBSE Class 8  >  Class 8 Test  >  Mathematics (Maths)   >  Test: Mensuration- 2 - Class 8 MCQ

Test: Mensuration- 2 - Class 8 MCQ


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10 Questions MCQ Test Mathematics (Maths) Class 8 - Test: Mensuration- 2

Test: Mensuration- 2 for Class 8 2026 is part of Mathematics (Maths) Class 8 preparation. The Test: Mensuration- 2 questions and answers have been prepared according to the Class 8 exam syllabus.The Test: Mensuration- 2 MCQs are made for Class 8 2026 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mensuration- 2 below.
Solutions of Test: Mensuration- 2 questions in English are available as part of our Mathematics (Maths) Class 8 for Class 8 & Test: Mensuration- 2 solutions in Hindi for Mathematics (Maths) Class 8 course. Download more important topics, notes, lectures and mock test series for Class 8 Exam by signing up for free. Attempt Test: Mensuration- 2 | 10 questions in 10 minutes | Mock test for Class 8 preparation | Free important questions MCQ to study Mathematics (Maths) Class 8 for Class 8 Exam | Download free PDF with solutions
Test: Mensuration- 2 - Question 1
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Find the volume of a cuboid whose length is 8 cm, breadth 6 cm and height 3.5 cm. 

Detailed Solution for Test: Mensuration- 2 - Question 1

- Volume Formula: Volume = Length × Breadth × Height
- Given Dimensions:
- Length = 8 cm
- Breadth = 6 cm
- Height = 3.5 cm
- Substituting the given values:
- 8 × 6 × 3.5
- 48 × 3.5 = 168
- Result: The volume of the cuboid is 168 cm³.

Test: Mensuration- 2 - Question 2
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Find the volume of a cuboid whose length is 8 cm, width is 3 cm and height is 5 cm. 

Detailed Solution for Test: Mensuration- 2 - Question 2
Volume of cubiod =l×b×h
=8×3×5
=120cm3 .
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Test: Mensuration- 2 - Question 3
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Find the perimeter of the a square with side 4cm.

Detailed Solution for Test: Mensuration- 2 - Question 3

The perimeter of a square is calculated by multiplying the length of one side by four. Given that each side is 4 cm, the calculation is as follows:

Perimeter = 4 × 4 cm = 16 cm

Thus, the correct answer is A, 16 cm.

Test: Mensuration- 2 - Question 4
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The area of the circle is 2464 cm², and the ratio of the breadth of the rectangle to the radius of the circle is 6:7. If the circumference of the circle is equal to the perimeter of the rectangle, then what is the area of the rectangle?
Detailed Solution for Test: Mensuration- 2 - Question 4
1. Area of the circle = πr2 Given area = 2464 cm², so: 2464 = (22/7) * r2 Solving for radius (r): r2 = (2464 * 7) / 22 = 784 r = √784 = 28 cm 2. Circumference of the circle = 2 * π * r Circumference = 2 * (22/7) * 28 = 176 cm 3. Breadth of the rectangle (b) is in ratio 6:7 with radius (r): b = (6/7) * 28 = 24 cm 4. Perimeter of the rectangle equals circumference of the circle: Perimeter = 2 * (length + breadth) 176 = 2 * (l + 24) l + 24 = 88 → l = 64 cm 5. Area of the rectangle = length * breadth Area = 64 * 24 = 1536 cm² Thus, the area of the rectangle is 1536 cm².
Test: Mensuration- 2 - Question 5
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Top surface of a raised platform is in the shape of regular octagon as shown in the figure. Find the area of the octagonal surface.

Detailed Solution for Test: Mensuration- 2 - Question 5

​

Visually, the area of the octagonal surface will be the sum of the area of two trapezia and the area of rectangular region.

Area of octagon ABCDEFGH = Area of Trapezium ABCH + Area of rectangle HCDG + Area of trapezium EFGD

Side of the regular octagon = 5 cm

Area of trapezium ABCH = Area of trapezium EFGD

Area of trapezium ABCH = 1/2 × (AB + CH) × AI

= 1/2 × (5 m + 11 m) × 4 m

= 1/2 × 16 m × 4 m

= 32 m2

Area of trapezium ABCH = Area of trapezium EFGD = 32 m2

Area of rectangle HCDG = HC × CD = 11 m × 5 m = 55 m2

Area of ABCDEFGH = Area of trapezium ABCH + Area of rectangle HCDG + Area of trapezium EFGD

= 32 m2+ 55 m2+ 32 m2

= 119 m2

Thus the area of the octagonal surface is 119 m2

Test: Mensuration- 2 - Question 6
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If the parallel sides of a parallelogram are 2 cm apart and their sum is 10 cm then its area is:

Detailed Solution for Test: Mensuration- 2 - Question 6

use formula:1/2(sum of of parallel sides)(distance between them)

= 1/2 *(10)*2 = 10 cm2

Test: Mensuration- 2 - Question 7
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If the edge of a cube is 1 cm then which of the following is its total surface area?

Detailed Solution for Test: Mensuration- 2 - Question 7

The total surface of a cube is calculated using the formula: Total Surface Area = 6 x (side length)2

Edge of the cube = 1 cm

substitute the value into the formula: Total Surface Area = 6 x 1 2 = 6 cm 2

Test: Mensuration- 2 - Question 8
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Find the area of a triangle whose base is 4 cm and altitude is 6 cm.

Detailed Solution for Test: Mensuration- 2 - Question 8

We know that area of triangle is equals to 1/2 base × altitude.
Here, base = 4 cm and altitude = 6 cm.
So, area = 1/2 × 4 × 6= 24 /2= 12 cm2.

Test: Mensuration- 2 - Question 9
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The area of a rhombus is 200 cm², and one of its diagonals is 20 cm. The length of the other diagonal is _____

Detailed Solution for Test: Mensuration- 2 - Question 9

Let the length of one diagonal be d1 = 20 cm, and the length of the other diagonal be d2

The formula for the area of a rhombus is:
Area = 1/2 x d1 x d2

Substitute the given values:

200 cm² = 1/2 x 20 x d2

200 cm² = 10 x d2

20cm = d2 

Test: Mensuration- 2 - Question 10
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The length of each side of a cube is 24 cm. The volume of the cube is equal to the volume of a cuboid. If the breadth and the height of the cuboid are 32 cm and 12 cm, respectively, then what will be the length of the cuboid?

Detailed Solution for Test: Mensuration- 2 - Question 10

Given:  
The length of each side of a cube is 24 cm.  
The breadth and the height of the cuboid are 32 cm and 12 cm, respectively.  

Concept used:  
The volume of the cube is equal to the volume of a cuboid.  
Volume of cube = a3  
Volume of cuboid = lbh  

Calculation:  
The volume of the cube is equal to the volume of a cuboid.  
⇒ 243 = l × 32 × 12  
243 = 24 × 24 × 24 = 576 × 24 = 13824
32 × 12 = 384
So,
13824 = l × 384
⇒ l = 13824 ÷ 384
⇒ l = 36  

Correct Option: A
 

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