Lakhmir Singh & Manjit Kaur Test: Motion - Class 9

Motion of bodies A and B is depicted by the x-t graph. Then which of the following is/are incorrect

A: A has uniform motion.
B: B has less velocity than A initially
C: B crosses A at X
D: A comes to rest at X

The speedometer of a car measures

​ From the x - t graph, one can draw the following conclusions ;

A: v_OA < v_AB
B: v_BC is negative
C: v_CD is the least by magnitude
D: acceleration is uniform

If the displacement-time graph of a particle is parallel to the time axis, the velocity of the particle is

In a uniformly accelerated motion,
A: v - t graph is a straight line not parallel to t or v axis.
B: x - t graph is not a straight line.
C: Slope of v - t graph varies.
D: Slope of x - t graph is constant.

The velocity time graph of a moving particle is shown in Figure, The acceleration of the particle is

If the velocity of a body is reducing, it is said to have

The velocity time (v - t) graph of a moving particle is shown in Figure. The acceleration is maximum for segment

 One can conclude from the given x-t graph that

The numerical ratio of displacement to distance for a moving object is

A body starting at a point, say A, reaches, say B, ahead in a straight line and returns back to A. Then there is

From the given v - t graph, it can be inferred that the object is

A body moves in a circle of radius 5 m with a speed of 5 ms^-1. Then it has
A: an acceleration of 5 ms^-2
B: an acceleration varying with direction alone

Four cars A, B, C and D are moving on a levelled road. Their distance versus time graphs are shown in figure.
Choose the correct statement.

The displacement of the body in 5 seconds from the beginning of the motion is

Suppose a boy is enjoying a ride on a merry go round which is moving with a constant speed of 10 ms^-1. It implies that the boy is

The v-t graph shown here depicts the motion of A and B such that