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Important Questions: Perimeter and Area - Class 7 MCQ


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15 Questions MCQ Test Mathematics (Maths) Class 7 - Important Questions: Perimeter and Area

Important Questions: Perimeter and Area for Class 7 2024 is part of Mathematics (Maths) Class 7 preparation. The Important Questions: Perimeter and Area questions and answers have been prepared according to the Class 7 exam syllabus.The Important Questions: Perimeter and Area MCQs are made for Class 7 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Important Questions: Perimeter and Area below.
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Important Questions: Perimeter and Area - Question 1

The circumference of a circle is 44 m. What is its area?

Detailed Solution for Important Questions: Perimeter and Area - Question 1

Important Questions: Perimeter and Area - Question 2

If the area of a circle is 2464 m2, find its diameter,

Detailed Solution for Important Questions: Perimeter and Area - Question 2

πd2/4 = 2464
22/7xd2=2464x4
d2=2464x4x7
            22
⇒ d =  = 56m

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Important Questions: Perimeter and Area - Question 3

The circular grass lawn of radius 35 mhas a path of width 7 m around it on the outside. What is the area of the path?

Detailed Solution for Important Questions: Perimeter and Area - Question 3


r = 35 m; R = 35+7=42 m
Area of circular path 
= π(R+r)(R−r)
= 22/7(42+35)(42−35) = 1694m2

Important Questions: Perimeter and Area - Question 4

The difference between the circumference and radius of a circle is37 m. What is the circumference of the circle?

Detailed Solution for Important Questions: Perimeter and Area - Question 4

2πr − r = 37 

r = 37/2π−1 = = 7m

Circumference = 2πr = 2 × 22/7 × 7 = 44m

Important Questions: Perimeter and Area - Question 5

How many plants (approximately) will be there in a circular bed whose outer edge measures 30 cm allowing 4 cm2 for each plant?

Detailed Solution for Important Questions: Perimeter and Area - Question 5

Circumference = 30 cm Area 

= C2/4π = =71.64cm2

Number of plants = A/4 = 71.64/4 

Important Questions: Perimeter and Area - Question 6

When the circumference and area of a circle are numerically equal, what is the diameter numerically equal to?

Detailed Solution for Important Questions: Perimeter and Area - Question 6

Area of circle = Circumference of circle
πr= 2πr = 2 ⇒ d = 2 + 2 = 4units

Important Questions: Perimeter and Area - Question 7

If the ratio of circumferences of two circles is 4:9, what is the ratio of their areas?

Detailed Solution for Important Questions: Perimeter and Area - Question 7

2πr1/2πr2 =   4/9
r1/r2 = 4/9
πr12/πr22 = r12/r22 = 16/81

Important Questions: Perimeter and Area - Question 8

What is the breadth of a rectangular sheet of perimeter 100 cm and length 35 cm?

Detailed Solution for Important Questions: Perimeter and Area - Question 8

The perimeter of a rectangular sheet = 100 cm

Length of the rectangular sheet (l) = 35 cm

Let the breadth be 'b' cm

Perimeter of a rectangular sheet = 2 (Length + Breadth)

100 = 2l + 2b

100 = 2 × 35 + 2b

100 = 70 + 2b

2b =100 - 70

b = 30/2

b = 15 cm

Important Questions: Perimeter and Area - Question 9

A wall hanging is in the shape given in the figure. Find its perimeter. 

Detailed Solution for Important Questions: Perimeter and Area - Question 9

The perimeter of the wall hanging is given by the sum of circumferences of the 4 semicircles −4 x diameter. Clearly, the diameter of each semicircle is 14 cm. The required perimeter 

= 2 × circumference of circle of radius 7 cm. 

= 2×2 × 22/7 × 7 = 88cm

Important Questions: Perimeter and Area - Question 10

A wire bent in the form of a circle of radius 42 cm is again bent in the form of a square. What is the ratio of the regions enclosed by the circle and the square?

Detailed Solution for Important Questions: Perimeter and Area - Question 10

Length of wire = 2π × 42 = 84πcm
Let x be the side of the square. We have,  4x = 84π ⇒ x = 21π
Area of the circle: Area of the square 
= π(42)2:(21π)2 
= 4:π = 4:22/7 = 14:11

Important Questions: Perimeter and Area - Question 11

The length and the breadth of a rectangular piece of land are 400 m and 250 m respectively. What is the cost of the land at Rs. 1000 per square metre?

Detailed Solution for Important Questions: Perimeter and Area - Question 11

∴ Area = 400 × 250m2
= 100000 m2
Cost of the land per square metre 
= Rs.1000 
∴  Cost of total land 
100000 × Rs.1000 = Rs.10 crores

Important Questions: Perimeter and Area - Question 12

In the given figure, ABCD is a parallelogram. DL⊥AB and DM⊥BC. If AB = 18cm,BC = 12cm and DM = 10cm,find DL 

Detailed Solution for Important Questions: Perimeter and Area - Question 12

Here we equate the areas, i.e., AB×DL = BC×DM 

⇒ 18×DL = 12×10 
⇒ DL = (12×10)/18 = 20/3 =

Important Questions: Perimeter and Area - Question 13

In the following figure, ABCD is a parallelogram. DL⊥AB and AB =13 cm = AD . If the area of parallelogram is 156 cm2, find AL. 

Detailed Solution for Important Questions: Perimeter and Area - Question 13

We have, area =156 cm2 
⇒ b×h = 156 
AB×DL=156 
DL = 156/AB =156/13 = 12cm
In right ΔADL, AD2=DL2+LA2
AL2=AD2−DL2=132−12= 25
∴ AL = =5cm

Important Questions: Perimeter and Area - Question 14

The length and breadth of a rectangular hall in a model are 0.4 m and 30 cmrespectively. What is the distance between the opposite corners of the wall in the model?

Detailed Solution for Important Questions: Perimeter and Area - Question 14

Distance between two opposite corners 


 = 50cm

Important Questions: Perimeter and Area - Question 15

Find the area of a verandah 2.25 m wide constructed outside a room 5.5 m long and 4 m wide.

Detailed Solution for Important Questions: Perimeter and Area - Question 15

The area of the verandah is 63 m².

  • Outer dimensions: 10 m × 8.5 m = 85 m²
  • Room area: 5.5 m × 4 m = 22 m²
  • Verandah area: 85 m² - 22 m² = 63 m².
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