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If the abscissa of a point is y and the ordinate is x then the coordinates of the point are ……..
the distance of the point (5, 6) from y axis is 5 units.
In general, the distance of the point (x,y) from xaxis is y and from yaxis is x.
If (2, 2p + 2) is the midpoint of (3p, 4) and (2, 2q), then the value of p and q are
we have,
2 = (3p  2)/2 and 2p + 2 = (2q + 4)/2
3p = 6 and 2p = q
p = 2
and q = 2p = 4
Point P(x,y) is a point in the third quadrant of the Cartesian plane. Then
"The distance between the origin and the coordinates (2, 3) is
Square root of (2 – 0)^2 + (3 – 0)^2
Square root of 2^2 + 3^2
Square root of 4 + 9
Square root of 25
Hence 5 will be the total distance between the coordinates and origin.
In case of xaxis we will only consider the value of y coordinate that is 3.
For a line whose equation is 2x + y = 5, which one of the following points lies on it ?
Option C is correct answer.
For the given point (2,1)
x = 2 and y = 1
Putting value in 2x + y = 5
2 (2) +1 = 5
5 = 5
So point (2,1) lies on the line 2x + y = 5
The distance of a point from the y axis is always the value of it's xcoordinate
That is , the distance of point p(2,3 ) from y axis is 2 units.
The perpendicular distance of a point Q(4, 7) from yaxis is
Distance of point from yaxis is x coordinate of given point,
So,since,value of xcoordinate is 4
so, distance = 4 unit
The coordinates of a point on the y axis of the form are …….
This is because if it will be not 0 at then the point will fall somewhre else on the graph instead of y axis.So the coordinatemust be (0,Y) to fall on y axis.
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