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Case Based Questions Test: Solutions


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15 Questions MCQ Test Chemistry Class 12 | Case Based Questions Test: Solutions

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Case Based Questions Test: Solutions - Question 1

Directions : Read the passage given below and answer the following questions:

The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).


Q. Relative lowering of vapour pressure for the given solution is

Detailed Solution for Case Based Questions Test: Solutions - Question 1

Calculation of relative lowering of vapour pressure .
Vapour pressure of water (pA) = 17.5 mm of Hg .
Lowering of vapour pressure (pA − pA) = 0.061
∴ Relative lowering of vapour pressure,

Case Based Questions Test: Solutions - Question 2

Directions : Read the passage given below and answer the following questions:

The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).


Q. Mole fraction of sugar in the solution is

Case Based Questions Test: Solutions - Question 3

Directions : Read the passage given below and answer the following questions:

The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).


Q.The vapour pressure (mm of Hg) of solution will be

Case Based Questions Test: Solutions - Question 4

Directions : Read the passage given below and answer the following questions:

The properties of the solutions which depend only on the number of solute particles but not on the nature of the solute are called colligative properties. Relative lowering in vapour pressure is also an example of colligative properties.
For an experiment, sugar solution is prepared for which lowering in vapour pressure was found to be 0.061 mm of Hg. (Vapour pressure of water at 200C is 17.5 mm of Hg).

Q. The vapour pressure (mm of Hg) of water at 293K when 25g of glucose is dissolved in 450 g of water is

Detailed Solution for Case Based Questions Test: Solutions - Question 4

Vapour pressure of water, p1° = 17.535 mm of Hg
Mass of glucose, w2 = 25 g
Mass of water, w1 = 450 g
We know that,
Molar mass of glucose (C6H12O6),
M2 = 6 × 12 + 12 × 1 + 6 × 16 = 180 g mol - 1
Molar mass of water, M1 = 18 g mol- 1
Then, number of moles of glucose, n1 = 25/180 = 0.139 mol
And, number of moles of water, n2 =450/18 = 25 mol
Now, we know that,
(p1° - p°) / p1° =  n1 / n2 + n1
⇒ 17.535 - p°  / 17.535 =   0.139 / (0.139+25)
⇒ 17.535 - p1 = 0.097
⇒ p1 = 17.44 mm of Hg
​Hence, the vapour pressure of water is 17.44 mm of Hg.

Case Based Questions Test: Solutions - Question 5

Directions : Read the passage given below and answer the following questions :

Scuba apparatus includes a tank of compressed air toted by the diver on his or her back, a hose for carrying air to a mouthpiece, a face mask that covers the eyes and nose, regulators that control air flow, and gauges that indicate depth and how much air remains in the tank.
A diver who stays down too long, swims too deep, or comes up too fast can end up with a condition called “the bends.” In this case, bubbles of gas in the blood can cause intense pain, even death.

In these following questions  a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. 
Assertion : Scuba divers may face a medical condition called ‘bends’.
Reason : ‘Bends’ can be explained with the help of Henry’s law as it links the partial pressure of gas to that of its mole fraction.
 

Detailed Solution for Case Based Questions Test: Solutions - Question 5

Henry ’s law explains some biological phenomena like the ‘bends’ experienced by the scuba divers. Since mole fraction of a gas in the solution is a measure of its solubility.

Case Based Questions Test: Solutions - Question 6

Directions : Read the passage given below and answer the following questions :

Scuba apparatus includes a tank of compressed air toted by the diver on his or her back, a hose for carrying air to a mouthpiece, a face mask that covers the eyes and nose, regulators that control air flow, and gauges that indicate depth and how much air remains in the tank.
A diver who stays down too long, swims too deep, or comes up too fast can end up with a condition called “the bends.” In this case, bubbles of gas in the blood can cause intense pain, even death.

In these following questions  a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices. 
Assertion : Soft drinks and soda water bottles are sealed under high pressure.
Reason : High pressure maintains the taste and texture of the soft drinks.

Detailed Solution for Case Based Questions Test: Solutions - Question 6

The bottle is sealed under high pressure to increase the solubility of CO2 in soft drinks and soda water.

Case Based Questions Test: Solutions - Question 7

Directions : Read the passage given below and answer the following questions :

Scuba apparatus includes a tank of compressed air toted by the diver on his or her back, a hose for carrying air to a mouthpiece, a face mask that covers the eyes and nose, regulators that control air flow, and gauges that indicate depth and how much air remains in the tank.
A diver who stays down too long, swims too deep, or comes up too fast can end up with a condition called “the bends.” In this case, bubbles of gas in the blood can cause intense pain, even death.

In these following questions  a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion : Anoxia is a condition experienced by climbers which makes them suddenly agile and unable to think clearly.
Reason : At high altitudes the partial pressure of oxygen is less than that at the ground level.

Detailed Solution for Case Based Questions Test: Solutions - Question 7

At high altitudes the partial pressure of oxygen is less than that at the ground level. This leads to low concentrations of oxygen in the blood and tissues of people living at high altitudes or climbers. This leads to a condition called anoxia caused due to low oxygen in blood, making the climbers to become weak and unable to think clearly.

Case Based Questions Test: Solutions - Question 8

Directions : Read the passage given below and answer the following questions :

Scuba apparatus includes a tank of compressed air toted by the diver on his or her back, a hose for carrying air to a mouthpiece, a face mask that covers the eyes and nose, regulators that control air flow, and gauges that indicate depth and how much air remains in the tank.
A diver who stays down too long, swims too deep, or comes up too fast can end up with a condition called “the bends.” In this case, bubbles of gas in the blood can cause intense pain, even death.

In these following questions  a statement of assertion followed by a statement of reason is given. Choose the correct answer out of the following choices.
Assertion : Bends is caused due to formation of nitrogen bubbles in the blood of scuba divers which blocks the capillaries.
Reason : Underwater high pressure increases solubility of gases in blood, while as pressure gradually decreases moving towards the surface, gases are released and nitrogen bubbles are formed in blood.

Detailed Solution for Case Based Questions Test: Solutions - Question 8

Scuba divers must cope with high concentrations of dissolved gases while breathing air at high pressure underwater. Increased pressure increases the solubility of atmospheric gases in blood. When the divers come towards surface, the pressure gradually decreases. This releases the dissolved gases and leads to the formation of bubbles of nitrogen in the blood. This blocks capillaries and creates a medical condition known as bends.

Case Based Questions Test: Solutions - Question 9

Directions : Read the passage given below and answer the following questions:

Raoult’s law states that for a solution of volatile liquids, the partial vapour pressure of each component of the solution is directly proportional to its mole fraction present in solution. Dalton’s law of partial pressure states that the total pressure (ptotal) over the solution phase in the container will be the sum of the partial pressures of the components of the solution and is given as : 
Ptotal = P1 + P2

Q. What type of deviation from Raoult’s law does the above graph represent ?

Case Based Questions Test: Solutions - Question 10

Directions : Read the passage given below and answer the following questions:

Raoult’s law states that for a solution of volatile liquids, the partial vapour pressure of each component of the solution is directly proportional to its mole fraction present in solution. Dalton’s law of partial pressure states that the total pressure (ptotal) over the solution phase in the container will be the sum of the partial pressures of the components of the solution and is given as : 
Ptotal = P1 + P2

Q. A solution of two liquids boils at a temperature more than the boiling point of either of them. What type of deviation will be shown by the solution formed in terms of Raoult’s law ?
 

Detailed Solution for Case Based Questions Test: Solutions - Question 10

Since the Boiling point of the solution is more than the Boiling point of the individual components in the solution, it indicates that the vapour pressure exerted by the solution is less than the expected, as boiling starts when vapour pressure equals the atmospheric pressure. Hence, the solution shows a negative deviation from the Raoult’s law.

Case Based Questions Test: Solutions - Question 11

Directions : Read the passage given below and answer the following questions:

Raoult’s law states that for a solution of volatile liquids, the partial vapour pressure of each component of the solution is directly proportional to its mole fraction present in solution. Dalton’s law of partial pressure states that the total pressure (ptotal) over the solution phase in the container will be the sum of the partial pressures of the components of the solution and is given as : 
Ptotal = P1 + P2

Q. Which of the following aqueous solutions should have the highest boiling point ?

Detailed Solution for Case Based Questions Test: Solutions - Question 11

Na2SO4 will release 3 moles of ions/ moles of Na2SO4 in the aqueous solution, and Boiling point being a colligative property, the Boiling point of this solution will be the highest as other solutions release only 2 ions each.

Case Based Questions Test: Solutions - Question 12

Directions : Read the passage given below and answer the following questions:

Raoult’s law states that for a solution of volatile liquids, the partial vapour pressure of each component of the solution is directly proportional to its mole fraction present in solution. Dalton’s law of partial pressure states that the total pressure (ptotal) over the solution phase in the container will be the sum of the partial pressures of the components of the solution and is given as : 
Ptotal = P1 + P2

Q. In comparison to a 0.01 M solution of glucose, the depression in freezing point of a 0.01 M MgCl2 solution is ________.

Detailed Solution for Case Based Questions Test: Solutions - Question 12

ΔTf =iKf m, where i = 1 for glucose.
ΔTf glucose  = 1 × Kf × 0.01
In case of MgCl2 → Mg2+ + 2Cl, where i = 3,
∅TfMgCl2 =  3 × 0.01 × Kf
⇒ ∅TfMgCl2 = 3  × ΔTf glucose
Hence, the depression in freezing point of MgCl2 is three times that of glucose.

Case Based Questions Test: Solutions - Question 13

Direction: Read the passage given below and answer the following questions:

Boiling point or freezing point of liquid solution would be affected by the dissolved solids in the liquid phase. A soluble solid in solution has the effect of raising its boiling point and depressing its freezing point. The addition of non-volatile substances to a solvent decreases the vapour pressure and the added solute particles affect the formation of pure solvent crystals.
According to many researches the decrease in freezing point directly correlated to the concentration of solutes dissolved in the solvent. This phenomenon is expressed as freezing point depression and it is useful for several applications such as freeze concentration of liquid food and to find the molar mass of an unknown solute in the solution. Freeze concentration is a high quality liquid food concentration method where water is removed by forming ice crystals. This is done by cooling the liquid food below the freezing point of the solution. The freezing point depression is referred as a colligative property and it is proportional to the molar concentration of the solution (m), along with vapour pressure lowering, boiling point elevation, and osmotic pressure. These are physical characteristics of solutions that depend only on the identity of the solvent and the concentration of the solute. The characters are not depending on the solute’s identity. 

Q. When a non volatile solid is added to pure water it will:

Detailed Solution for Case Based Questions Test: Solutions - Question 13

The correct option is B Boils above 100oC and freezes below 0oC
Lowering in vapour pressure results in an elevation in boiling point. Therefore, when a non-volatile solid is added to pure water, it will boil at higher temperature and freeze at lower temperature, i.e. below 0oC.

Case Based Questions Test: Solutions - Question 14

Direction: Read the passage given below and answer the following questions:

Boiling point or freezing point of liquid solution would be affected by the dissolved solids in the liquid phase. A soluble solid in solution has the effect of raising its boiling point and depressing its freezing point. The addition of non-volatile substances to a solvent decreases the vapour pressure and the added solute particles affect the formation of pure solvent crystals.
According to many researches the decrease in freezing point directly correlated to the concentration of solutes dissolved in the solvent. This phenomenon is expressed as freezing point depression and it is useful for several applications such as freeze concentration of liquid food and to find the molar mass of an unknown solute in the solution. Freeze concentration is a high quality liquid food concentration method where water is removed by forming ice crystals. This is done by cooling the liquid food below the freezing point of the solution. The freezing point depression is referred as a colligative property and it is proportional to the molar concentration of the solution (m), along with vapour pressure lowering, boiling point elevation, and osmotic pressure. These are physical characteristics of solutions that depend only on the identity of the solvent and the concentration of the solute. The characters are not depending on the solute’s identity. 

Q. Assume three samples of juices A, B and C have glucose as the only sugar present in them.
The concentration of sample A, B and C are 0.1M, .5M and 0.2 M respectively. Freezing point will be highest for the fruit juice:
 

Case Based Questions Test: Solutions - Question 15

Direction: Read the passage given below and answer the following questions:

Boiling point or freezing point of liquid solution would be affected by the dissolved solids in the liquid phase. A soluble solid in solution has the effect of raising its boiling point and depressing its freezing point. The addition of non-volatile substances to a solvent decreases the vapour pressure and the added solute particles affect the formation of pure solvent crystals.
According to many researches the decrease in freezing point directly correlated to the concentration of solutes dissolved in the solvent. This phenomenon is expressed as freezing point depression and it is useful for several applications such as freeze concentration of liquid food and to find the molar mass of an unknown solute in the solution. Freeze concentration is a high quality liquid food concentration method where water is removed by forming ice crystals. This is done by cooling the liquid food below the freezing point of the solution. The freezing point depression is referred as a colligative property and it is proportional to the molar concentration of the solution (m), along with vapour pressure lowering, boiling point elevation, and osmotic pressure. These are physical characteristics of solutions that depend only on the identity of the solvent and the concentration of the solute. The characters are not depending on the solute’s identity. 

Q. Colligative properties are:

Detailed Solution for Case Based Questions Test: Solutions - Question 15

Colligative properties of solutions are properties that depend upon the concentration of solute molecules or ions, but not upon the identity of the solute. Colligative properties include vapor pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure.

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