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If log_{4} 5 = a and log_{5} 6 = b then what is the value of log_{3} 2?
If 2 [log (x + y)  log 5] = logx + logy, then what is the value of x^{2} + y^{2}?
Log 32700 = log 3.27 + log 10000 = log 3.27 + 4
log_{10} 125 = log_{10}( 1000/8) = log. 1000  31og_{2} = 3  3 x 0.301 = 2.097
log_{15}3375 x Log_{4}1024 = 3 log_{15}1 5 x 5 log_{4} 4 = 3 x 5 = 15.
1/2 log_{625} 5 = [1/(2 x 4)] log_{5}5 = 1/8.
3 log 5 + 2 log 4  log 2
= log 125 + log 16  log 2
= log (125 x 16)/2
= log 1000 = 3.
1/10 = 12  x => x = 11.9
x log 2 = 3
log 2 = 3/x.
Therefore, x = 3/log 2
x = log_{5}10 = l/log_{10}5 = 1/log 5.
log x = log (7.2/2.4) = log 3 ⇒ x = 3
log x = log 25 + log 8 = log (25 x 8 ) = log 200.
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