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Test: Logarithm- 5


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15 Questions MCQ Test Quantitative Aptitude (Quant) | Test: Logarithm- 5

Test: Logarithm- 5 for CAT 2022 is part of Quantitative Aptitude (Quant) preparation. The Test: Logarithm- 5 questions and answers have been prepared according to the CAT exam syllabus.The Test: Logarithm- 5 MCQs are made for CAT 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Logarithm- 5 below.
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Test: Logarithm- 5 - Question 1

Detailed Solution for Test: Logarithm- 5 - Question 1

Test: Logarithm- 5 - Question 2

If log 2 = .301, find the number of digits in (125)25.

Detailed Solution for Test: Logarithm- 5 - Question 2

logy = 25 log 125

= 25 [log 1000 - 3 log 2]

= 25 x (2.097)

= 52 +
Hence 53 digits.

Test: Logarithm- 5 - Question 3

Detailed Solution for Test: Logarithm- 5 - Question 3

(75/35) x (49/25) x (jc/105) x (25/13) = 1 ⇒ x = 13

Test: Logarithm- 5 - Question 4

Which one of the following is true

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Test: Logarithm- 5 - Question 5

Detailed Solution for Test: Logarithm- 5 - Question 5

x = (16/15) x (255/245) x (813/803) None of these is correct.

Test: Logarithm- 5 - Question 6

Find the value of the logarithmic expression in the questions below.

Detailed Solution for Test: Logarithm- 5 - Question 6

log (anbncn/anbncn) = log 1 = 0

Test: Logarithm- 5 - Question 7

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Test: Logarithm- 5 - Question 8

 log2 (9 - 2X) = 10log (3-x) Solve for x.

Detailed Solution for Test: Logarithm- 5 - Question 8

For x = 0, we have LHS

Log2 8 = 3.
RHS: 10log3 = 3.
We do not get LHS = RHS for either x = 3 or x = 6.

Thus, option (a) is correct.

Test: Logarithm- 5 - Question 9

Which one of the following is true

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Test: Logarithm- 5 - Question 10

log (x - 13) + 3 log 2 = log (3x + 1)

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Test: Logarithm- 5 - Question 11

log . 0867 = ? 

Detailed Solution for Test: Logarithm- 5 - Question 11

Log 0.0867 = log (8.67/100) = log 8.67 - log 100 Log 8.67 - 2

Test: Logarithm- 5 - Question 12

log3x = 1/2

Detailed Solution for Test: Logarithm- 5 - Question 12

x = 31/2 = √3 .

Test: Logarithm- 5 - Question 13

If log10a = b, find the value of 103b in terms of a.

Detailed Solution for Test: Logarithm- 5 - Question 13

log10a = b ⇒ 10b = a ⇒ By definition of logs.

Thus 103b = (10b)3 = a3.

Test: Logarithm- 5 - Question 14

log (x2 - 6x + 6) = 0 

Detailed Solution for Test: Logarithm- 5 - Question 14

Test: Logarithm- 5 - Question 15

 Find x If  logx = log 1.5 + log 12

Detailed Solution for Test: Logarithm- 5 - Question 15

log x = log 18 ⇒ x = 18

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