10 Questions MCQ Test CSAT Preparation - Test: Mensuration- 2
Test: Mensuration- 2 for UPSC 2024 is part of CSAT Preparation preparation. The Test: Mensuration- 2 questions and answers have been
prepared according to the UPSC exam syllabus.The Test: Mensuration- 2 MCQs are made for UPSC 2024 Exam. Find important
definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mensuration- 2 below.
Solutions of Test: Mensuration- 2 questions in English are available as part of our CSAT Preparation for UPSC & Test: Mensuration- 2 solutions in
Hindi for CSAT Preparation course. Download more important topics, notes, lectures and mock
test series for UPSC Exam by signing up for free. Attempt Test: Mensuration- 2 | 10 questions in 10 minutes | Mock test for UPSC preparation | Free important questions MCQ to study CSAT Preparation for UPSC Exam | Download free PDF with solutions
A right circular cone has height H and radius R. A small cone is cut off at the top by a plane parallel to the base. At what height above the base the section has been made?
Statement (I): H = 20 cm
Statement (II): Volume of small cone: volume of large cone : 1:15
Detailed Solution for Test: Mensuration- 2 - Question 1
From statement I, we know that the height of the initial cone is 20cm. However, nothing is said about the small cone. Hence, we cannot answer the question using statement A. So, we can eliminate choices (A) and (D).
We are down to choices (A), (B) or (D).
From Statement II, we know that the ratio of the volume of the small cone to that of the large cone is 1 : 15.
(r is the base radius of the smaller cone and h is the height of the smaller cone)
or r2 * h : R2 * H is 1 : 15
From this information, we will not be able to find the answer to h. Hence, we can eliminate choice (A).
Combining the information in the two statements:
When a section is made the two cones are similar triangles. so
Substituting H = 20, we can get the value for h.
Choice (B) is therefore, the correct answer.
Correct Answer: If the question cannot be answered with statement I alone or with statement II alone, but can be answered if both statements are used together.
A sphere of radius r is cut by a plane at a distance of h from its center, thereby breaking this sphere into two different pieces. The cumulative surface area of these two pieces is 25% more than that of the sphere. Find h.
Detailed Solution for Test: Mensuration- 2 - Question 2
Cylindrical cans of cricket balls are to be packed in a box. Each can has a radius of 7 cm and height of 30 cm. Dimension of the box is l = 76 cm, b = 46 cm, h = 45 cm. What is the maximum number of cans that can fit in the box?
Detailed Solution for Test: Mensuration- 2 - Question 4
This question requires a good deal of visualization. Since, both the box and cans are hard solids, simply dividing the volume won’t work because the shape can’t be deformed.
Each cylindrical can has a diameter of 14 cm and while they are kept erect in the box will occupy height of 30 cm
Number of such cans that can be placed in a row
Number of such rows that can be placed
Thus 5 x 3 = 15 cans can be placed in an erect position.
However, height of box = 45cm and only 30 cm has been utilized so far
Remaining height = 15 cm > 14 cm (Diameter of the can)
So, some cans can be placed horizontally on the base.
Number of cans in horizontal row
Number of such rows
∴ 2 x 3 = 6 cans can be placed horizontally
An inverted right circular cone has a radius of 9 cm. This cone is partly filled with oil which is dipping from a hole in the tip at a rate of 1cm2/hour. Currently the level of oil 3 cm from top and surface area is 36π cm2. How long will it take the cone to be completely empty?
Detailed Solution for Test: Mensuration- 2 - Question 8
A spherical shaped sweet is placed inside a cube of side 5 cm such that the sweet just fits the cube. A fly is sitting on one of the vertices of the cube. What is the shortest distance the fly must travel to reach the sweet?
Detailed Solution for Test: Mensuration- 2 - Question 10
The question demands visualization. The shortest distance required to be travelled by the fly would be diagonally and be given by:-
In this test you can find the Exam questions for Test: Mensuration- 2 solved & explained in the simplest way possible.
Besides giving Questions and answers for Test: Mensuration- 2, EduRev gives you an ample number of Online tests for practice
Find all the important questions for Mensuration- 2 at EduRev.Get fully prepared for Mensuration- 2 with EduRev's comprehensive question bank and test resources.
Our platform offers a diverse range of question papers covering various topics within the Mensuration- 2 syllabus.
Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered.
The questions are designed to challenge you and help you gain confidence in tackling the actual exam.
Maximize your chances of success by utilizing EduRev's extensive collection of Mensuration- 2 resources.
Mensuration- 2 MCQs with Answers
Prepare for the Mensuration- 2 within the UPSC exam with comprehensive MCQs and answers at EduRev.
Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus.
Access the best books, study materials, and notes curated by toppers to enhance your preparation.
Stay updated with the exam date and receive expert preparation tips and paper analysis.
Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.
Online Tests for Mensuration- 2 CSAT Preparation
Practice with a wide array of question papers that follow the exam pattern and syllabus.
Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement.
Access detailed solutions and explanations for each test to enhance your understanding of concepts.
With EduRev's Online Tests, you can build confidence, boost your performance, and ace Mensuration- 2 with ease.
Join thousands of successful students who have benefited from our trusted online resources.