Description

This mock test of Test: Trigonometry- 1 for Quant helps you for every Quant entrance exam.
This contains 5 Multiple Choice Questions for Quant Test: Trigonometry- 1 (mcq) to study with solutions a complete question bank.
The solved questions answers in this Test: Trigonometry- 1 quiz give you a good mix of easy questions and tough questions. Quant
students definitely take this Test: Trigonometry- 1 exercise for a better result in the exam. You can find other Test: Trigonometry- 1 extra questions,
long questions & short questions for Quant on EduRev as well by searching above.

QUESTION: 1

If tanØ + sinØ = m, tanØ - sinØ = n, find the value of **m ^{2} - n^{2}.**

Solution:

__Adding the two equations__, tanØ = (m + n) / 2

__Subtracting the two equations__, sinØ = (m - n) / 2

Since, there are no available direct formula for relation between sinØ tanØ.

__But we know that:__ cosec^{2}Ø - cot^{2}Ø = 1

QUESTION: 2

A student is standing with a banner at the top of a 100 m high college building. From a point on the ground, the angle of elevation of the top of the student is 60° and from the same point, the angle of elevation of the top of the tower is 45°. Find the height of the student.

Solution:

Let BC be the height of the tower and DC be the height of the student.

In rt. ΔABC,

AB = BC cot 45° = 100 m

In rt. ΔABD, AB = BD cot 60° = (BC + CD) cot 60° = (10 + CD) * (1 / √3)

∵ AB = 100 m

⇒ (10 + CD) * 1 / √3 = 100

⇒ (10 + CD) = 100√3

⇒ CD = 100√3 - 100 = 100 (1.732 - 1) = 100 x 0.732 = 73.2 m

QUESTION: 3

If Cos x – Sin x = √2 Sin x, find the value of Cos x + Sin x:

Solution:

Cos x – Sin x = √2 Sin x

⇒ Cos x = Sin x + √2 Sin x

⇒ Sin x = (√2 - 1) Cos x

⇒ Sin x = √2 Cos x - Cos x

⇒ Sin x + Cos x = √2 Cos x

QUESTION: 4

If, (1 - Cosx + Sinx) / (1 + Sinx) can be written as:

Solution:

⇒

⇒

⇒

⇒

⇒

QUESTION: 5

If cos A + cos^{2} A = 1 and a sin^{12} A + b sin^{10} A + c sin^{8} A + d sin^{6} A - 1 = 0. Find the value of a+b / c+d

Solution:

Cos A = 1 - Cos^{2}A

⇒ Cos A = Sin^{2}A

⇒ Cos^{2}A = Sin^{4}A

⇒ 1 – Sin^{2}A = Sin^{4}A

⇒ 1 = Sin^{4}A + Sin^{2}A

⇒ 1^{3} = (Sin^{4}A + Sin^{2}A)^{3}

⇒ 1 = Sin^{12}A + Sin^{6}A + 3 Sin^{8}A + 3 Sin^{10}A

⇒ Sin^{12}A + Sin^{6}A + 3 Sin^{8}A + 3 Sin^{10}A – 1 = 0

On comparing,

a = 1, b = 3 , c = 3 , d = 1

⇒ (a+b)/(c+d) = 1

Hence, the answer is 1

### Lecture 1 - Trigonometry

Video | 18:42 min

### Maths test :-Some applications of trigonometry.

Doc | 1 Page

### Examples: Application of Trigonometry- 1

Video | 09:43 min

- Test: Trigonometry- 1
Test | 10 questions | 20 min

- Test: Trigonometry- 1
Test | 5 questions | 5 min

- Test: Inverse Trigonometry- 1
Test | 25 questions | 25 min

- Test: Trigonometry- 2
Test | 15 questions | 15 min

- Test: Trigonometry- 2
Test | 10 questions | 10 min