Test: Profit & Loss- 2 - CAT MCQ

Let the cost price of a ball be Rs. x.

So, the CP of 17 balls is Rs. 17x.

The CP of 5 balls is Rs. 5x.

Since Loss = CP - SP

So, 5x = 17x - 720

On solving, we get

12 x = 720

that is, x = 60

So, the cost price of a ball is Rs. 60.

85 : 18700 = 115 : x
⇒ x = (18700*115)/85
x = 25300

So before solving this question we will get the C.P. and S.P. of 1 article to get the gain percent.

C.P. of 1 orange = 350/100 = Rs 3.50
S.P. of one orange = 48/12 = Rs 4 [note: divided by 12 as 1 dozen contains 12 items]
Gain = 4 - 3.50 = Rs 0.50

Profit

The correct answer is A as
 cost price = SPX100/100-loss
=34.80×100/75
=46.40

Let the marked price be Rs. 100.
Successive discounts of 20% and 12% were given.
Sale price = 100 × 80/100 × 88/100 = Rs.704/10
If the sale price is Rs.704/10, the marked price is Rs.100
If the sale price is Rs.704, the marked price is
= 100 × 10 × 704/704 =  Rs.1000
 

CP of the table at which the shopkeeper procured each table = p

It is given that shopkeeper sold the tables to Amal and Asim at a profit of 20% and at a loss of 20%, respectively

The selling price of the tables = 1.2p and 0.8p to Amal and Asim respectively.

Amal sells his table to Bimal at a profit of 30%

So, CP of the table by Bimal (x)= 1.2p*1.3 = 1.56p

Asim sells his table to Barun at a loss of 30%

So, CP of the table by Barun (y)= 0.7*0.8p = 0.56p

(x-y)/p=(1.56p-0.56p)/p=p/p=1

Let the cost of each bicycle= 100b

CP of 10 bicycles = 1000b
It is given that he sold six of these at a profit of 25% and the remaining four at a loss of 25%
SP of 10 bicycles = 125b*6 + 75b*4

= 1050b

Profit = 1050b - 1000b = 50b

50b = 2000

CP = 100b = 4000

Let the number of dozens of candies he bought of each variety be x

Hence total cost = 12x + 15x = 27x

Total selling price = 16.50*2x = 33x

Profit = 33x - 27x = 6x

Given 6x = 150 => x = 25

Hence he bought 50 dozens of candies in total

It is given that a merchant purchases a cloth at a rate of Rs.100 per meter and receives 5 cm length of cloth free for every 100 cm length of cloth purchased by him.

Hence, the cost price of 105 cm clothes is 100 rupees. 

It is also known that he marked the price of 100 cm clothes as 110 rupees, and gave a 5% discount, and he cheated his customers by giving 95 cm length of cloth for every 100 cm length of cloth purchased by the customers.

Hence, the selling price of 95 cm clothes is 110*(19/20) rupees.

Therefore, the selling price of 105 cm clothes is 115.5 rupees.

Hence, the profit is 15.5%

The correct option is C