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Class 3 Exam  >  Class 3 Tests  >  Mathematics Olympiad for Class 3  >  Olympiad Test Level 1: Decimals - Class 3 MCQ

Olympiad Test Level 1: Decimals - Class 3 MCQ


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20 Questions MCQ Test Mathematics Olympiad for Class 3 - Olympiad Test Level 1: Decimals

Olympiad Test Level 1: Decimals for Class 3 2024 is part of Mathematics Olympiad for Class 3 preparation. The Olympiad Test Level 1: Decimals questions and answers have been prepared according to the Class 3 exam syllabus.The Olympiad Test Level 1: Decimals MCQs are made for Class 3 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test Level 1: Decimals below.
Solutions of Olympiad Test Level 1: Decimals questions in English are available as part of our Mathematics Olympiad for Class 3 for Class 3 & Olympiad Test Level 1: Decimals solutions in Hindi for Mathematics Olympiad for Class 3 course. Download more important topics, notes, lectures and mock test series for Class 3 Exam by signing up for free. Attempt Olympiad Test Level 1: Decimals | 20 questions in 40 minutes | Mock test for Class 3 preparation | Free important questions MCQ to study Mathematics Olympiad for Class 3 for Class 3 Exam | Download free PDF with solutions
Olympiad Test Level 1: Decimals - Question 1
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I had ₹ 8.53. My mother and father gave me ₹ 343.35 and ₹ 175.50 respectively. How much total money do I have now ?

Detailed Solution for Olympiad Test Level 1: Decimals - Question 1

Total money
= ₹8.53 + ₹343.35 + ₹175.50
= ₹527.38

Olympiad Test Level 1: Decimals - Question 2
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Wasim bought a pen for ₹ 450.25. If he had ₹ 569.90 with him, how much money was he left with ?

Detailed Solution for Olympiad Test Level 1: Decimals - Question 2

Money left

= Total money – Money spent

= ₹ 569.90 – ₹ 450.25 = ₹ 119.65

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Olympiad Test Level 1: Decimals - Question 3
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Mrs. Sharma needs 0.3 liter lemon juice, 0.25 liter coconut milk and 0.4 liter pineapple juice to make a drink. About how much liquid does she need altogether to make the drink? 

Detailed Solution for Olympiad Test Level 1: Decimals - Question 3

just add them  0.3 + 0.25 + 0.4 = 0.95 litre

Olympiad Test Level 1: Decimals - Question 4
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On converting 356 paise into ₹, weget,
Detailed Solution for Olympiad Test Level 1: Decimals - Question 4

1 ₹ = 100 paise.
To convert 356 paise into ₹, divide 356 by 100:

356 ÷ 100 = 3.56

So, 356 paise is equal to ₹ 3.56.

Answer: Option A ₹ 3.56

Olympiad Test Level 1: Decimals - Question 5
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Which number has 2 in the hundredths place and 6 in the tenths place?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 5

To find the number with 2 in the hundredths place and 6 in the tenths place, we need to look at the digits in the correct positions:

  1. 0.261:

    • Tenths place: 2
    • Hundredths place: 6
    • This does not match the requirement.

  2. 2.06:

    • Tenths place: 0
    • Hundredths place: 6
    • This does not match the requirement.

  3. 6.12:

    • Tenths place: 1
    • Hundredths place: 2
    • This does not match the requirement.

  4. 0.621:

    • Tenths place: 6
    • Hundredths place: 2
    • This matches the requirement.

Thus, the correct number is 0.621.

Olympiad Test Level 1: Decimals - Question 6
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Converting 455 cm into m, we get
Detailed Solution for Olympiad Test Level 1: Decimals - Question 6

455cm = (455/100)m=4.55 m

Olympiad Test Level 1: Decimals - Question 7
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Ram distributed ₹ 680.60 among 6 cousins. Find the share of each.
Detailed Solution for Olympiad Test Level 1: Decimals - Question 7

Share of each cousin

= ₹ (680.60/6) = ₹113.43

Olympiad Test Level 1: Decimals - Question 8
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Sara is carrying 1.45 kg of grapes and 1.23 kg of peaches in her bag. How much weight is she carrying altogether?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 8

To find the total weight, add the weight of the grapes and peaches:

1.45 kg + 1.23 kg = 2.68 kg

So, Sara is carrying 2.68 kg altogether.

Answer: Option D 2.68 kg

Olympiad Test Level 1: Decimals - Question 9
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Ram had ₹ 20.65 but the cost of a toy is ₹ 45.75. How much money did he need to buy the toy ?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 9

Money needed

= ₹ 45.75 – ₹ 20.65 = ₹ 25.10

Olympiad Test Level 1: Decimals - Question 10
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Write as a decimal : 5(1/4)       
Detailed Solution for Olympiad Test Level 1: Decimals - Question 10

To convert 5(1/4)​ into a decimal:

  • The fraction 1/4/​ is equal to 0.25.
  • So, 5(1/4)​ becomes 5 + 0.25 = 5.25.

Answer: Option B 5.25

Olympiad Test Level 1: Decimals - Question 11
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I want to buy a toy. My mother gave me ₹ 104.75, father gave me ₹ 110.25 and sister gave me ₹ 70.60. How much money do I have now ?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 11

Total money

= ₹ 104.75 + ₹ 110.25 + ₹ 70.60

= ₹ 285.60

Olympiad Test Level 1: Decimals - Question 12
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Which symbol will make the number sentence true?         
1.3 + 0.6   O   0.5 + 1.3
Detailed Solution for Olympiad Test Level 1: Decimals - Question 12

1.3 + 0.6 = 1.9
where 0.5 + 1.3 = 1.8 so clearly first one is bigger.

Olympiad Test Level 1: Decimals - Question 13
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Evaluate the expression: 
70 + 5 + (30/100) = ?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 13

70 + 5 + (30/100) = 45 + (30/100)

= 75 + 0.30

= 75.30

Olympiad Test Level 1: Decimals - Question 14
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In 538.76, 6 stands in _______ place.
Detailed Solution for Olympiad Test Level 1: Decimals - Question 14

After decimal, the place values are tenths, hundredths, thousandths and so on. Here, 6 is at hundredth place.

Olympiad Test Level 1: Decimals - Question 15
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Which digit in 3.21 is the tenths place?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 15

In the number 3.21, the digit in the tenths place is the first digit to the right of the decimal point. Therefore, the correct answer is: 2

Olympiad Test Level 1: Decimals - Question 16
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Simplify:

22.0625 – [15 + 0.25 × (4.78 – 1.5 × 3.02)]
Detailed Solution for Olympiad Test Level 1: Decimals - Question 16

Given:

22.0625 – [15 + 0.25 × (4.78 – 1.5 × 3.02)]

Formula used:

Standard arithmetic operations

Calculation:

22.0625 – [15 + 0.25 × (4.78 – 1.5 × 3.02)]

⇒ 22.0625 – [15 + 0.25 × (4.78 – 4.53)]

⇒ 22.0625 – [15 + 0.25 × 0.25]

⇒ 22.0625 – [15 + 0.0625]

⇒ 22.0625 – 15.0625

⇒ 7

∴ The correct answer is option (d).

Olympiad Test Level 1: Decimals - Question 17
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Convert 4570 cm into m.
Detailed Solution for Olympiad Test Level 1: Decimals - Question 17

4570cm = (4570/100) m

Olympiad Test Level 1: Decimals - Question 18
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Simplify the given expression.

12.3 - [7 + 0.8 of (5.6 - 3.8 × 1.03)]
Detailed Solution for Olympiad Test Level 1: Decimals - Question 18

Given:

12.3 - [7 + 0.8 of (5.6 - 3.8 × 1.03)]

Formula used:

Order of operations (BODMAS/BIDMAS): Brackets, Orders (i.e. powers and square roots, etc.), Division and Multiplication, Addition and Subtraction

Calculation:

12.3 - [7 + 0.8 of (5.6 - 3.8 × 1.03)]

⇒ 12.3 - [7 + 0.8 of (5.6 - 3.914)]

⇒ 12.3 - [7 + 0.8 of 1.686]

⇒ 12.3 - [7 + 1.3488]

⇒ 12.3 - 8.3488

⇒ 3.9512

∴ The correct answer is option (d).

Olympiad Test Level 1: Decimals - Question 19
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Maya was given 9.5 points for her presentation and Josh was given 6.5 points. How many more points did Maya get?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 19

To find how many more points Maya got, subtract Josh's points from Maya's points:

9.5 − 6.5 = 3

So, Maya got 3 more points than Josh.

Answer: Option B: 3

Olympiad Test Level 1: Decimals - Question 20
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What approximate value should come in place of question mark ‘?’ in the following question?

1132.757 – 2315.996 – 1753.829 + 2 × 2846.639 = ?
Detailed Solution for Olympiad Test Level 1: Decimals - Question 20

1132.757 – 2315.996 – 1753.829 + 2 × 2846.639

= 1133 – 2316 – 1754 + 5694

= (1133 + 5694) – (2316 + 1754 )

= 6827 – 4070

= 2757

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