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Chemistry: CUET Mock Test - 9 - CUET MCQ


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30 Questions MCQ Test CUET Mock Test Series - Chemistry: CUET Mock Test - 9

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Chemistry: CUET Mock Test - 9 - Question 1

Which of the following is not a method to test the type of emulsion?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 1

Coagulation or precipitation is a process of aggregating together the colloidal particles to change them into large-sized particles which ultimately settle as a precipitate. The different methods to test the type of emulsion are-microscopic, conductance and dye method.

Chemistry: CUET Mock Test - 9 - Question 2

Structure of ammonium salt when ethylamine reacts with one mole of HCl ?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 2

When ethylamine reacts with one mole of hydrochloric acid (HCl), the ammonium salt formed is ethylammonium chloride, which has the chemical formula C2H5NH3+Cl-
The reaction between ethylamine and HCl can be represented as follows:

CH3CH2 - NH2 + HCl →

In this reaction, the HCl protonates the ethylamine to form ethylammonium ion (C2H5NH3+) and chloride ion (Cl-), which combine to form the ethylammonium chloride salt.
Conclusion :

Ethylammonium chloride salt is formed when ethylamine reacts with one mole of HCl.

Chemistry: CUET Mock Test - 9 - Question 3

Among the following amines, which one is most basic (in aqueous solution)?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 3

Based on inductive effect, solvation effect, and steric hindrance of the alkyl group in aqueous medium the basic strength order of the amines is:
(C2H5)2NH > (C2H5)3N > C2H5NH2 > NH3

Chemistry: CUET Mock Test - 9 - Question 4

The correct order of basicity of amines in gas phase

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 4

More is the substitution in amine, more is +I effect hence more will be the basic strength. The correct order of basic strength: 3° > 2° > 1°
In the gas phase, where intermolecular forces such as hydrogen bonding do not play a significant role, the basicity of amines is primarily determined by the availability of the lone pair of electrons on the nitrogen atom for bonding with a proton (H+), and by the effect of alkyl groups that can donate electron density to the nitrogen atom, increasing its basicity.
Primary (1°) amines have one alkyl group attached to the nitrogen atom, secondary (2°) amines have two, and tertiary (3°) amines have three. Alkyl groups are electron-donating groups that increase the electron density on the nitrogen atom, making it more basic by enhancing its ability to donate the lone pair of electrons.
Therefore, in the gas phase, without the effects of solvation (like hydrogen bonding in a solvent), the order of basicity is determined by the inductive effect of the alkyl groups. More alkyl groups means a stronger inductive effect, which increases the basicity. The correct order of basicity in the gas phase is:
3° > 2° > 1°

Chemistry: CUET Mock Test - 9 - Question 5

Among the following, which one has the highest pKb value?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 5

The pKb value is an indicator of the basicity of a substance in water; lower pKb values indicate stronger bases, while higher pKb values indicate weaker bases. The basic strength of an amine in water is influenced by factors such as the electron-donating or withdrawing nature of substituents and the ability of the compound to stabilize the conjugate acid formed upon accepting a proton.
C2H5NH2 (ethylamine) is a primary aliphatic amine and is relatively basic due to the electron-donating effect of the ethyl group, increasing the electron density on the nitrogen atom.
C6H5NHCH3 (N-methylaniline) is a secondary amine where the nitrogen is attached to an aromatic ring (phenyl group) and a methyl group. The phenyl group is electron-withdrawing by resonance, reducing the electron density on the nitrogen atom, making it less basic compared to aliphatic amines.
(C2H5)2NH (diethylamine) is a secondary amine with two ethyl groups. It is more basic than primary amines due to the increased electron-donating inductive effect of the two alkyl groups.
C6H5NH2 (aniline) is a primary aromatic amine. The lone pair of electrons on the nitrogen atom is delocalized into the aromatic ring, significantly reducing its availability to bond with a proton. This makes aniline much less basic than aliphatic amines.
The higher is the value of pKb, weaker is the basic strength. Lone pair of electron of nitrogen in amine (aniline) is involved in delocalization and hence its availability for protonation is minimum. It is least basic among the given options hence its pKb is highest.

Chemistry: CUET Mock Test - 9 - Question 6

Among the following, which one has the highest Kb value?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 6

More the basic nature of amine, more will be the Kb value.
Basic nature

(C2H5)2NH > C2H5NH2 > CH3NH2 > C6H5N(CH3)2
Kb : 10–3 10–3.29 10–3.38 10–8.92

Chemistry: CUET Mock Test - 9 - Question 7
Antifertility drug is:
Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 7

The correct answer is novestrol.

  • Novestrol is also known as ethinylestradiol.
    • It is an antifertility drug that is commonly used in combination with progestin in birth control pills.
    • It is also sometimes used for the diagnosis of menopause as a part of menopausal hormone therapy.
    • The primary function of novestrol is stopping egg ovulation during the menstrual cycle.

Additional Information

  • Aspartame is an artificial non-saccharide sweetener.
    • It is about 200 times sweeter than sucrose.
  • Soframycin is a skin cream that contains Framycetin.
    • It is an antibiotic medicine.
    • It is used for the treatment of various skin conditions caused by or suspected to have a bacterial infection.
  • Prontosil is an antibacterial drug of the sulfonamide group.
    • It has a relatively broad effect against gram-positive cocci but not against enterobacteria.
    • It is one of the earliest antimicrobial drugs and was widely used in the mid-20th century but is little used today because better options now exist.
Chemistry: CUET Mock Test - 9 - Question 8

Select the odd one, from the Common, IUPAC names given below.

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 8

The formula of ethyl alcohol is C2H5OH
In the option, it is given as C2H3OH

Chemistry: CUET Mock Test - 9 - Question 9

Assertion: Aminoacetic acid is less acidic than acetic acid.

Reason: Amino group is electron donating in nature.

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 9

Correct answer: 1)

Concept:

  • The amino group has a negative inductive effect (electron-withdrawing property).
  • It causes the alpha carboxyl group carboxylate ion to become more stable due to the delocalization of electrons on the conjugate base.
  • It increases the acidity of the alpha-carboxyl group.

Explanation:

  • Amino acids are organic compounds containing an amino group and an acidic group as substitutes for alpha carbon.
  • In amino acetic acid, the NH2​ group is electron-repelling in nature.
  • Thus it reduces the tendency to release proton from the Aminoacetic acid.

Conclusion:

Thus, option 1 is correct. If both assertion and reason are true and the reason is the correct explanation of the assertion.

Chemistry: CUET Mock Test - 9 - Question 10

The packing efficiency in simple cubic, body centred cubic and cubic closed packed lattice is respectively :

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 10

Crystal lattice -The crystal lattice is a symmetrical 3-dimensional arrangement of constituent particles (atoms, ions, or molecules) inside a crystalline solid as points.

  • In other words, a crystal lattice is made up of a very large number of unit cells where every lattice point is occupied by one constituent particle (atom, ion, or molecule).

Lattice Point - In a crystal lattice, each atom, ion, or molecule is represented by a single point which is known as a lattice point.​

Unit Cell- It is the smallest part of a crystal lattice.

  • It is the simplest repeating unit in a crystal structure.

Types of unit cell -

1) Primitive Unit Cell - In this unit cell, the constituent particles only occupy the corner position.

2) Centered Unit Cell-

  • Body-Centered Unit Cell - In this unit cell, the constituent particle is present at all corners and at the center of the unit cell.
  • Face-Centered Unit Cell - In this unit cell, the constituent particles are present at the corners and at the center of all the faces of the unit cell.

M11Q5: Types of Unit Cells: Body-Centered Cubic and Face-Centered Cubic –  Chem 103/104 Resource Book

Explanation:
Packing Efficiency- The packing efficiency is the percentage of total space filled by the particles.

  • The fraction of total space filled is known as the packing fraction.
  • Packing efficiency = Volume occupied by spheres × 100 / Total volume of a cube
  • OR Packing efficiency = No. of lattice points in unit cell × volume occupied by one lattice point × 100 / Total volume of a cube

​In Simple cubic lattice:

  • The volume occupied by one sphere = 4/3π r3
  • Let the edge length of a cube be 'a' and the radius of each particle be 'r'
  • a= 2r
  • The volume of the cube = a3 = (8r)3
  • Packing efficiency of Simple cubic lattice = 52.4%

​In Body-Centered Cubic lattice:

  • No. of lattice points in BCC lattice = 2
  • The volume occupied by spheres = 2 ×  π r3
  • Let the edge length of a cube be 'a' and the radius of each particle be 'r'
  • a =
  • The volume of the cube = a3
  • Packing efficiency of Body-Centered Cubic lattice = 68.04%

​In Cubic- Closed lattice:

  • No. of lattice points in FCC lattice = 4
  • The volume occupied by spheres = 4 ×  π r3
  • Let the edge length of a cube be 'a' and the radius of each particle be 'r'
  • a =
  • The volume of the cube = a3
  • Packing efficiency of Face-Centered Cubic lattice = 74%

Therefore, the packing efficiency in Simple cubic lattice = 52.4% , Body-Centered Cubic lattice = 68.04%, Face-Centered Cubic lattice = 74%

π r3​In Simple cubic lat43πr

Chemistry: CUET Mock Test - 9 - Question 11

In a face centred cubic lattice, atom A occupies the corner positions and atom B occupies the face center position. If one atom of B is missing from one of the face centred points, the formula of the compound is

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 11

Face-centred Cubic Unit Cell:-

  • An FCC unit cell has atoms at all four corners of the crystal lattice, as well as in the centre of each of the cube's faces.
  • Only 1/2 of each atom belongs to an individual cell, and the atom present at the face-centred is shared by two adjacent unit cells.
  • A face-centred cubic unit cell structure is made up of atoms arranged in a cube with a fraction of an atom in each corner and six additional whole atoms in the centre of each cube face.
  • Eight other unit cells share the atoms in the corner of the cube.
  • The packing efficiency of FCC lattice is 74%.

Calculation:-

Atom (A) occupies the corner locations in a face-centred cubic lattice.

Each of the eight corner places provides one-eighth of the unit cell. As a result, the total number of (A) atoms per unit cell is calculated.

Total atoms at the corners = 1 / 8 × 8 = 1.

The face centre positions were held by Atom (B).

There are six different face centre positions to choose from.

One of the face-centred points is missing an atom of (B).

As a result, there are five face centre slots that are occupied (B).

Each of these positions adds one-half to the unit cell. As a result, the total number of (B) atoms per unit cell is calculated.

Total atoms at the faces = 1/ 2 × 5 = 2.5.

Thus, the formula will be AB2.5 = A2B5.

Chemistry: CUET Mock Test - 9 - Question 12

Which of the following is an example of an emulsifier?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 12

To obtain a stable emulsion, sometimes, small quantities of certain other substances are added during its preparation. The substances thus added to stabilize the emulsions are called emulsifiers or emulsifying agents.

Chemistry: CUET Mock Test - 9 - Question 13

 What is the process called when the molecules of a substance are retained at the surface of a solid or a liquid?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 13

Adsorption is the process which involves the accumulation of the molecules of a substance in higher concentration on the surface of a solid or a liquid. For example, gasses are adsorbed on the surface of charcoal.

Chemistry: CUET Mock Test - 9 - Question 14

Which of the following can result in a transition from physisorption to chemisorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 14

Physisorption occurs due to Van der Waals forces. On increasing the temperature, the adsorbate can split into atoms and form chemical bonds with the adsorbent and hence, cause chemisorption.

Chemistry: CUET Mock Test - 9 - Question 15

Which of the following statements is true with respect to the types of adsorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 15

Chemisorption is stronger than physisorption. Chemisorption involves the forming of a chemical bond between the adsorbent and the adsorbate whereas in physisorption, the molecules are held together by weak Van der Waal’s forces. Therefore, chemisorption is stronger.

Chemistry: CUET Mock Test - 9 - Question 16

Which of the following statements is not true with respect to chemisorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 16

Chemisorption is a kind of adsorption that involves a chemical reaction between the adsorbent and adsorbate, resulting in the formation of a chemical bond between the two. Since a bond is to be formed, chemisorption is highly dependent on the reactants(adsorbate and adsorbent) and has a large heat of adsorption. Also, since it involves bond formation, it cannot be multi-layered. Chemisorption is favoured to occur at high temperature.

Chemistry: CUET Mock Test - 9 - Question 17

Which of the following is an example of sorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 17

Sorption refers to the process where adsorption and absorption occur at the same time. Cotton dipped in ink is one of the cases where both adsorption and absorption, that is, sorption occurs.

Chemistry: CUET Mock Test - 9 - Question 18

Which of the following statements is incorrect with respect to physisorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 18

Physisorption is reversible as the molecules of the adsorbate are held to the adsorbent by weak Van der Waals forces which can be broken easily. Physisorption is exothermic and so, ΔH is negative. Adsorption is a spontaneous process. In adsorption, the movement of the adsorbed molecule is restricted. As a result the entropy change (ΔS) is negative.

Chemistry: CUET Mock Test - 9 - Question 19

Which of the following statements is true with respect to the extent of physisorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 19

Physisorption is an exothermic process. According to Le-Chatelier’s principle, an exothermic reaction is favoured by a decrease in temperature. Therefore, the extent of physisorption decreases on increasing temperature.

Chemistry: CUET Mock Test - 9 - Question 20

Which of the following forces is involved in physical adsorption?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 20

In physical adsorption, the molecules of the adsorbate stick to the surface of the adsorbent due to very weak forces which is known as Van der Waals force. Van der Waals force is similar to the forces that cause condensation of gas into liquid.

Chemistry: CUET Mock Test - 9 - Question 21

The rate constant of a reaction is k=3.28 × 10-4 s-1. Find the order of the reaction.

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 21

Given,
k = 3.28 × 10-4 s-1
The general formula to find the units for rate constant, k = (mol L-1)1-ns-1 where n is the order of the reaction. The value of n must be 1 for (mol L-1)1-ns-1 to become s-1.
Therefore,k = 3.28 × 10-4s-1 represents a first order reaction.

Chemistry: CUET Mock Test - 9 - Question 22

What is the concentration of the reactant in a first order reaction when the rate of the reaction is 0.6 s-1 and the rate constant is 0.035?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 22

Given, R=0.6 s-1 and k= 0.035
For a first order reaction R= k [A]

Chemistry: CUET Mock Test - 9 - Question 23

What is the rate law for acid hydrolysis of an ester such as CH3COOC2H5 in aqueous solution?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 23

Acid hydrolysis of ester, CH3COOC2H5 + H2O → CH3COOH + C2H5OH
The order of the reaction may be altered sometimes by taking reactant in excess compared to the other.
The rate law R= k [CH3COOC2H5] [H2O] however water is present in excess.
So, R= k [CH3COOC2H5].

Chemistry: CUET Mock Test - 9 - Question 24

For the reaction A + H2O → products, find the rate of the reaction when [A] = 0.75 M, k= 0.02.

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 24

Given,
[A] = 0.75 M, k= 0.02
The reaction belongs to pseudo first order reaction so, the unit is s-1
R= k [A]= 0.02 × 0.75= 0.015 s-1.

Chemistry: CUET Mock Test - 9 - Question 25

For a reaction A +B → C, the experimental rate law is found to be R=k[A]1[B]1/2. Find the rate of the reaction when [A] = 0.5 M, [B] = 0.1 M and k=0.03.

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 25

Given, [A] = 0.5 M, [B] = 0.1 M and k= 0.03
From the rate law it is evident that the order of the reaction is 1+ 0.5 = 1.5 = 32
Therefore the unit of k= (mol L-1)1-1.5 s-1 = (L/mol)1/2 s-1
R= k[A]1[B]1/2 = 0.03 × 0.5 × 0.11/2 = 4.74 × 10-2(L/mol)1/2 s-1.

Chemistry: CUET Mock Test - 9 - Question 26

How many times will the rate of the elementary reaction 3X + Y → X2Y change if the concentration of the substance X is doubled and that of Y is halved?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 26

Since it is an elementary reaction, its rate law r1= k [A] 3[B]
When the concentrations are changed the new rate will be r2= k (2[A])3([B]/2) = 4k[A]3[B]
So, r2 = 4r1.

Chemistry: CUET Mock Test - 9 - Question 27

What is the rate law for the reaction C2H4 + I2 → C2H4I2?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 27

Fractional order reactions are reaction whose order is a fraction. This reaction is an example of fractional order reaction, where the order of the reaction is 5/2.
The rate law for the reaction is known to be R= [C2H4] [I2]3/2.

Chemistry: CUET Mock Test - 9 - Question 28

What is the method of protection of iron by coating it with zinc called?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 28

Rusting of iron is one of the most common forms of corrosion. To prevent iron from rusting, generally, more active metals are coated on it. The metal which is often used for coating iron is zinc (which is more active) and this process is called galvanization.

Chemistry: CUET Mock Test - 9 - Question 29

Which of the following is not a method of prevention of corrosion?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 29

Galvanization is the process of coating iron with zinc to prevent its oxidation. Anti-rust solutions are alkaline phosphate and alkaline chromate solutions. The alkalinity prevents the availability of hydrogen ions. Cathodic protection is the process of connecting the iron object to be protected to a more active metal either directly or through a wire.

Chemistry: CUET Mock Test - 9 - Question 30

Which of the following is not essential for rusting to take place?

Detailed Solution for Chemistry: CUET Mock Test - 9 - Question 30

Rust is a general term for a series of iron oxides, usually, reddish-brown oxides, formed by the reaction of iron with oxygen in the presence of water or moisture. Water is usually present in the form of water vapour and oxygen is always present in the normal atmosphere. The oxygen needs moisture as a catalyst and reactant to accelerate the reaction, so in the absence of moisture, iron won’t rust.

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