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# Important Questions Test: Playing With Numbers

## 20 Questions MCQ Test Mathematics (Maths) Class 6 | Important Questions Test: Playing With Numbers

Description
This mock test of Important Questions Test: Playing With Numbers for Class 6 helps you for every Class 6 entrance exam. This contains 20 Multiple Choice Questions for Class 6 Important Questions Test: Playing With Numbers (mcq) to study with solutions a complete question bank. The solved questions answers in this Important Questions Test: Playing With Numbers quiz give you a good mix of easy questions and tough questions. Class 6 students definitely take this Important Questions Test: Playing With Numbers exercise for a better result in the exam. You can find other Important Questions Test: Playing With Numbers extra questions, long questions & short questions for Class 6 on EduRev as well by searching above.
QUESTION: 1

### If a number is divisible by 5, then which of the following can be its one’s digit?

Solution:

A number is divisible by 5 if the last digit of the number is 0 or 5.

QUESTION: 2

### If a number is divisible two co-prime numbers than it is divisible by their

Solution:

If a number is divisible by each of two or more co-prime numbers then it is divisible by their products.

QUESTION: 3

### _____ is the factor of 68.

Solution:

Factors of 68 are 1, 2, 4, 17, 34, 68

QUESTION: 4

If a number is divisible by 10, then which of the following can be its one’s digit?

Solution:
QUESTION: 5

Which of them is prime number?

Solution:

A prime number is a natural number greater than 1 that cannot be formed by multiplying two smaller natural numbers.

QUESTION: 6

Which of them is composite number?

Solution:

A natural number greater than 1 that is not prime is called a composite number.

QUESTION: 7

Every prime number except ______ is odd.

Solution:

Every prime number is divisible only by itself. 1 and 2 is the smallest even number that is followed by condition that is so it as even prime number.

These numbers have been taken and divisible by 2 so expect 2 all prime numbers are odd. There is no exception and number 2 is prime even number.

QUESTION: 8

______ is the smallest prime number which is even.

Solution:
QUESTION: 9

Number of factors of a given number are _______.

Solution:

Factors of a number are defined as numbers or algebraic expressions that divide a given number/expression evenly. We can also say, factors are the numbers which are multiplied to get the other number. For example, 1, 3 and 9 are the factors of 9, because 1 × 9 = 9 and 3 × 3 = 9.

So the number of factors of a given number are finite.

QUESTION: 10

The number of multiples of a given number is _______.

Solution:

The number of multiples of a given number is infinite. Example : Multiples of 2 = {2,4,6,8,10,...} Multiples of 3 = { 3,6,9,12,15,18,...}

QUESTION: 11

901153 is divisible by ___.

Solution:

Sum of odd digits = 9 + 1 + 5 = 15

Sum of even digits = 0 + 1 + 3 = 4

Difference = 15-4 = 11
Difference is divisible by 11. Therefore, 901153 is divisible by 11.

QUESTION: 12

Every ______ of a number is greater than or equal to that number.

Solution:
QUESTION: 13

Find the HCF of 18, 48.

Solution:

Factors of 18 = 2 x 3 x 3

Factors of 48 = 2 x 2 x 2 x 2 x 3

H.C.F. (18, 48) = 2 x 3 = 6

QUESTION: 14

A number is divisible by 12. By what other numbers will that number be divisible?

Solution:
QUESTION: 15

The exact divisor of number 9 is

Solution:
QUESTION: 16

A number is divisible by 6. By what other numbers will that number be divisible

Solution:
QUESTION: 17

Find the HCF of 27, 63.

Solution:

Factors of 27 = 3 x 3 x 3

Factors of 63 = 3 x 3 x 7

H.C.F. (27, 63) = 3 x 3 = 9

QUESTION: 18

Which number is factor of every number?

Solution:
QUESTION: 19

The HCF of two consecutive numbers is

Solution:

The HCF of two consecutive numbers is always one. The reason behind this is that the two consecutive numbers do not have any common factor other than 1. Hence 1 becomes the highest common factor between two consecutive numbers.

QUESTION: 20

The LCM of two co-prime numbers is

Solution: