Olympiad Test: Mensuration - Class 6 MCQ

# Olympiad Test: Mensuration - Class 6 MCQ

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## 20 Questions MCQ Test Mathematics (Maths) Class 6 - Olympiad Test: Mensuration

Olympiad Test: Mensuration for Class 6 2024 is part of Mathematics (Maths) Class 6 preparation. The Olympiad Test: Mensuration questions and answers have been prepared according to the Class 6 exam syllabus.The Olympiad Test: Mensuration MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Mensuration below.
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Olympiad Test: Mensuration - Question 1

### What is the perimeter of a rectangle of length l and breadth b?

Detailed Solution for Olympiad Test: Mensuration - Question 1

Perimeter of the rectangle
= sum of all sides
= 2 x (length + breadth)
= 2(l+b)

Olympiad Test: Mensuration - Question 2

### What is the perimeter of a square of side s units?

Detailed Solution for Olympiad Test: Mensuration - Question 2

The perimeter (P) of a square is given by the formula:

P = 4s

where s is the length of one side of the square in units. This formula indicates that the perimeter of a square is four times the length of one of its sides.

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Olympiad Test: Mensuration - Question 3

### What is the perimeter of an equilateral triangle of side a units?

Detailed Solution for Olympiad Test: Mensuration - Question 3

• Perimeter of an equilateral triangle: The perimeter of any polygon is the sum of the lengths of all its sides. In an equilateral triangle, all three sides are equal in length.

• Given: The side length of the equilateral triangle is 'a' units.

• Formula for perimeter: Since all sides of an equilateral triangle are equal, the perimeter P can be calculated as P = a + a + a = 3a units.

• Therefore, the correct answer is: B: 3a units.

Olympiad Test: Mensuration - Question 4

What do you call the total boundary length of a closed figure?

Detailed Solution for Olympiad Test: Mensuration - Question 4
Perimeter:

• Definition: The total boundary length of a closed figure is called the perimeter.

• Calculation: To find the perimeter of a closed figure, you simply add up the lengths of all its sides.

• Units: Perimeter is typically measured in units such as inches, feet, meters, etc.

• Importance: Perimeter helps us understand the outer boundary of a shape and is crucial in determining the amount of fencing needed for a garden, the length of a race track, etc.

• Examples: For a square with side length 5 units, the perimeter would be 4 * 5 = 20 units. For a rectangle with lengths 6 units and 4 units, the perimeter would be 2 * (6 + 4) = 20 units.

Olympiad Test: Mensuration - Question 5

What is the amount of surface enclosed by a closed figure called?

Detailed Solution for Olympiad Test: Mensuration - Question 5
Surface Area Calculation

• Definition: The amount of surface enclosed by a closed figure is called the area.

• Measurement: Area is measured in square units such as square meters (m²) or square centimeters (cm²).

• Formula: The formula to calculate the area of different shapes varies. For example, the area of a square is side * side, while the area of a circle is π * radius².

• Importance: Knowing the surface area of a closed figure is crucial in various fields such as construction, architecture, and geometry.

• Applications: Area calculation is used to determine the amount of material needed to cover a surface, calculate land area, and solve real-world problems.

Olympiad Test: Mensuration - Question 6

The perimeter of a rectangle is 170 m and its length is 50 m. What is its breadth?

Detailed Solution for Olympiad Test: Mensuration - Question 6

2(l+b) = 170
2(50+b) = 170
50 + b = 170/2 = 85
b = 85−50 = 35m

Olympiad Test: Mensuration - Question 7

The area of a rectangle is 630 sq. cm and its breadth is 15 cm. What is its length?

Detailed Solution for Olympiad Test: Mensuration - Question 7

= 630/15

length = 42 cm

Olympiad Test: Mensuration - Question 8

Samuel wanted to erect some vertical stones along the boundary of his plot at a distance of 10 m each. If the length of the plot is 30 m and the breadth is 15 m how many stones are required?

Detailed Solution for Olympiad Test: Mensuration - Question 8

Perimeter of plot = 2(l+b) = 2(30+15) = 90m

Distance between two stones = 10m

Therefore, number of stones = 90/10 = 9

Olympiad Test: Mensuration - Question 9

The length and breadth of a rectangle are 3.2 m and 150 cm. What is its area?

Detailed Solution for Olympiad Test: Mensuration - Question 9

We know that,

Area=l∗b

l=3.2m
b=1.5m
l×b=3.2×1.5 =4.80 sq m
to apply point - first count the no of digit after decimal in the numbers
like here one here in 3.2 and one in 1.5 so a total of 2
now apply decimal from back to 2 decimal place

Olympiad Test: Mensuration - Question 10

80 students of the same height stand with both hands stretched all along the sides of a rectangular garden, each student covering a length of 1.75 m. What is the perimeter of the garden?

Detailed Solution for Olympiad Test: Mensuration - Question 10

Perimeter of garden= covering made by the 80 students
80 × 1.75 m = 140 m

Olympiad Test: Mensuration - Question 11

A table top is covered with 25 squares of equal size. The side of the square is 3 cm. What is the area of the table top?

Detailed Solution for Olympiad Test: Mensuration - Question 11

Area of square
= s × s
= 3×3 = 9 sq. cm
Area of 25 squares
= 25 × 9
= 225 sq.cm

Olympiad Test: Mensuration - Question 12

The length and breadth of a rectangular plot are 900 m and 700 m respectively. If three rounds offence is fixed around the field at the cost of Rs. 8 per metre, what is the total amount spent?

Detailed Solution for Olympiad Test: Mensuration - Question 12

l = 900 m, b = 700 m
Perimeter = 2 (900 + 700) m = 2(1600) m = 3200 m
Perimeter for 3 rounds fence = 3(3200) m = 9600 m
∴  Total amount spent
= 9600×Rs. 8 = Rs. 76,800

Olympiad Test: Mensuration - Question 13

How many sq. cm make a sq. m?

Detailed Solution for Olympiad Test: Mensuration - Question 13

1 sq. m = 10,000 sq. cm

Olympiad Test: Mensuration - Question 14

A wooden plank measures 6 m in length and 3 m in breadth. If five such wooden planks are arranged in order, what is the area occupied by them?

Detailed Solution for Olympiad Test: Mensuration - Question 14

l = 6m; b = 3m
Area of one plank = 6×3 = 18sq.m
Number of wooden planks = 5
Area of 5 wooden planks = 18×5 = 90 m2

Olympiad Test: Mensuration - Question 15

On a wall of dimensions 10.5 m long and 8.5 m wide, a square shaped wall poster is stuck at the centre whose side measure is 2.5 m. If the remaining part of the wall is to be painted with pink colour costing Rs. 12 per sq. m, how much does it cost?

Detailed Solution for Olympiad Test: Mensuration - Question 15

Area of the poster = 2.5 × 2.5 sq. m
= 6.25sq.m Area of the wall
= 10.5×8.5 sq.m
= 89.25sq.m
Area of the wall to be painted =(89.25-6.25) sq.m = 83.00 sq.m
Cost of painting = 83 × Rs. 12 = Rs. 996

Olympiad Test: Mensuration - Question 16

What is the area of the given figure?

Detailed Solution for Olympiad Test: Mensuration - Question 16

10×5 = 50sq.m
6×8 = 48 sq. m
∴ The required area = 50 + 48 = 98 sq. m

Olympiad Test: Mensuration - Question 17

In a square shaped park, whose side measures 28 m, a rectangular pond is located at the centre with dimensions 3 m and 2 m. What is the area of the park excluding the pond?

Detailed Solution for Olympiad Test: Mensuration - Question 17

Area of pond = 3m × 2m = 6 sq m
Area of park = 28 × 28
= 784 sq m
Area of the park excluding the pond
= 784-6
= 778 sq m

Olympiad Test: Mensuration - Question 18

An isosceles triangle has a measure of p units for its equal sides and q units for its unequal side. What is its perimeter?

Detailed Solution for Olympiad Test: Mensuration - Question 18
Explanation:

• Given: An isosceles triangle with equal sides of length p units and an unequal side of length q units.

• Perimeter of a triangle: The perimeter of a triangle is the sum of the lengths of its three sides.

• For an isosceles triangle: In an isosceles triangle, two sides are equal in length and one side is unequal.

• Perimeter of the isosceles triangle: To find the perimeter of the isosceles triangle, we add the lengths of the three sides, which are p, p, and q.

• Perimeter = p + p + q = 2p + q

Olympiad Test: Mensuration - Question 19

What is the resultant of twice the sum of the length and breadth of a rectangle?

Detailed Solution for Olympiad Test: Mensuration - Question 19
Explanation:

• Given: Let the length of the rectangle be L and the breadth be B.

• Twice the sum of length and breadth: 2(L + B)

• Resultant of twice the sum of length and breadth: This is the perimeter of the rectangle, which is given by 2(L + B).

• Therefore, the correct answer is option B: Its perimeter.

Olympiad Test: Mensuration - Question 20

The perimeter of a square is 728 cm. Find the measure of its side.

Detailed Solution for Olympiad Test: Mensuration - Question 20
Steps to find the measure of the side of the square:

• Perimeter of a square: The perimeter of a square is the sum of all its four sides.

• Given information: The perimeter of the square is 728 cm.

• Formula: Let's denote the side of the square as x. Therefore, the perimeter = 4x.

• Equation: 4x = 728

• Solve for x: Divide both sides by 4: x = 728 / 4 = 182

Conclusion:

• Measure of the side: The measure of the side of the square is 182 cm.

By following the steps mentioned above, you can easily find the measure of the side of the square.

## Mathematics (Maths) Class 6

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