IBPS Clerk Mains Mock Test - 8 - Bank Exams MCQ

Step 1: Those numbers which are immediately followed by a consonant and immediately preceded by a vowel are written at the left end in alphabetical order.

1 S Q A D F W @ E B T R # O % 5 3 U Z C G Y 2 4 & H I M 9 7 $ 8 6 L N ? K

Step 2: After completing step 1, vowels are interchanged with preceding element.

1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

Step 3: After completing step 2, Even numbers which are Perfect Square are written at the left end in ascending order.

4 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 & I H M 9 7 $ 8 6 L N ? K

Step 2: 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

If all the consonants are dropped, the series becomes:

1 A E @ O # % 5 U 3 2 4 & I 9 7 $ 8 6 ?

7th element from the left end is %.

Step 1: Those numbers which are immediately followed by a consonant and immediately preceded by a vowel are written at the left end in alphabetical order.

1 S Q A D F W @ E B T R # O % 5 3 U Z C G Y 2 4 & H I M 9 7 $ 8 6 L N ? K

Step 2: After completing step 1, vowels are interchanged with preceding element.

1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

Step 3: After completing step 2, Even numbers which are Perfect Square are written at the left end in ascending order.

4 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 & I H M 9 7 $ 8 6 L N ? K

Vowels which are immediately preceded by a consonant and followed by a consonant:

Step 2: 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

Step 1: Those numbers which are immediately followed by a consonant and immediately preceded by a vowel are written at the left end in alphabetical order.

1 S Q A D F W @ E B T R # O % 5 3 U Z C G Y 2 4 & H I M 9 7 $ 8 6 L N ? K

Step 2: After completing step 1, vowels are interchanged with preceding element.

1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

Step 3: After completing step 2, Even numbers which are Perfect Square are written at the left end in ascending order.

4 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 & I H M 9 7 $ 8 6 L N ? K

Odd numbers which are followed by a vowel:

Step 3: 4 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 & I H M 9 7 $ 8 6 L N ? K

Step 1: Those numbers which are immediately followed by a consonant and immediately preceded by a vowel are written at the left end in alphabetical order.

1 S Q A D F W @ E B T R # O % 5 3 U Z C G Y 2 4 & H I M 9 7 $ 8 6 L N ? K

Step 2: After completing step 1, vowels are interchanged with preceding element.

1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

Step 3: After completing step 2, Even numbers which are Perfect Square are written at the left end in ascending order.

4 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 & I H M 9 7 $ 8 6 L N ? K

17th from the right - 8th from the right = 9nd from the right

Step 1: Those numbers which are immediately followed by a consonant and immediately preceded by a vowel are written at the left end in alphabetical order.

1 S Q A D F W @ E B T R # O % 5 3 U Z C G Y 2 4 & H I M 9 7 $ 8 6 L N ? K

Step 2: After completing step 1, vowels are interchanged with preceding element.

1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 4 & I H M 9 7 $ 8 6 L N ? K

Step 3: After completing step 2, Even numbers which are Perfect Square are written at the left end in ascending order.

4 1 S A Q D F W E @ B T R O # % 5 U 3 Z C G Y 2 & I H M 9 7 $ 8 6 L N ? K

As, Left + Right = Left

10th from the left + 12th from the right = 22nd from the left

1) The exam that H took was more difficult than at least four exams.

(Implies, H appeared for one of the top four difficult exams i.e. UPSC, CA, CAT, and CGL.)

2) Neither G nor H appeared for either CA or CAT.

(Implies, H appeared for either UPSC or CGL.)

3) F was transferred 13 fewer times than H who was transferred the maximum number of times.

4) The person who appeared for UPSC was transferred 5 fewer times than the person who appeared for MTS.

(Implies, the person appeared for UPSC was not transferred the highest number of times. Hence, H appeared for CGL.)

5) No person appeared for the more difficult exam than F that implies F has appeared for the most difficult exam i.e. UPSC

Now as we know that H appeared for CGL,

H – F = 13

H + F = 43

(Implies, H was transferred 28 times and F was transferred 15 times.)

6) D cleared either MTS or CGL.

(As we know that H cleared CGL, implies, D cleared MTS.)

7) The total number of transfers of D and the person who cleared UPSC is 35.

(According to the fourth, sixth and the seventh statement,

D – The person appeared for UPSC = 5

D + The person appeared for UPSC = 35

Implies, D was transferred 20 times and the person who appeared for UPSC was transferred 15 times. It further implies that F appeared for UPSC as F was transferred 15 times.)

8) The difficulty level of the exam which C cleared is just below the difficulty level of the exam which was cleared by F.

(Implies, C cleared CA.)

9) B appeared for the exam which is difficult than the exam for which H appeared and B got 7 fewer transfers than H.

(As we know that F and C cleared UPSC and CA respectively, implies, B appeared for CAT. Also, as H was transferred 28 times, implies, B was transferred 21 times.)

10) A did not appear for either RBI or CHSL.

(Implies, A appeared for NABARD as it is the only possibility left.)

11) The total number of transfers of C is 60% of the total number of transfers of D and also, C was transferred 3 more times than G.

(Implies, C was transferred 12 times because D was transferred 20 times. It further implies that G was transferred 9 times.)

12) The person who cleared RBI was transferred 5 more times than the person who cleared CA.

(Implies, the person who cleared RBI was transferred 17 times because the person who cleared CA i.e. C was transferred 12 times. It further implies that G did not appear for RBI. So, now there is only one possibility i.e. G appeared for CHSL and E appeared for RBI.)

13) The person who cleared NABARD was transferred 4 fewer times than the person who cleared CHSL.

(Implies, A was transferred 5 times.)

Clearly, B cleared CAT exam.

1) The exam that H took was more difficult than at least four exams.

(Implies, H appeared for one of the top four difficult exams i.e. UPSC, CA, CAT, and CGL.)

2) Neither G nor H appeared for either CA or CAT.

(Implies, H appeared for either UPSC or CGL.)

3) F was transferred 13 fewer times than H who was transferred the maximum number of times.

4) The person who appeared for UPSC was transferred 5 fewer times than the person who appeared for MTS.

(Implies, the person appeared for UPSC was not transferred the highest number of times. Hence, H appeared for CGL.)

5) No person appeared for the more difficult exam than F that implies F has appeared for the most difficult exam i.e. UPSC

Now as we know that H appeared for CGL,

H – F = 13

H + F = 43

(Implies, H was transferred 28 times and F was transferred 15 times.)

6) D cleared either MTS or CGL.

(As we know that H cleared CGL, implies, D cleared MTS.)

7) The total number of transfers of D and the person who cleared UPSC is 35.

(According to the fourth, sixth and the seventh statement,

D – The person appeared for UPSC = 5

D + The person appeared for UPSC = 35

Implies, D was transferred 20 times and the person who appeared for UPSC was transferred 15 times. It further implies that F appeared for UPSC as F was transferred 15 times.)

8) The difficulty level of the exam which C cleared is just below the difficulty level of the exam which was cleared by F.

(Implies, C cleared CA.)

9) B appeared for the exam which is difficult than the exam for which H appeared and B got 7 fewer transfers than H.

(As we know that F and C cleared UPSC and CA respectively, implies, B appeared for CAT. Also, as H was transferred 28 times, implies, B was transferred 21 times.)

10) A did not appear for either RBI or CHSL.

(Implies, A appeared for NABARD as it is the only possibility left.)

11) The total number of transfers of C is 60% of the total number of transfers of D and also, C was transferred 3 more times than G.

(Implies, C was transferred 12 times because D was transferred 20 times. It further implies that G was transferred 9 times.)

12) The person who cleared RBI was transferred 5 more times than the person who cleared CA.

(Implies, the person who cleared RBI was transferred 17 times because the person who cleared CA i.e. C was transferred 12 times. It further implies that G did not appear for RBI. So, now there is only one possibility i.e. G appeared for CHSL and E appeared for RBI.)

13) The person who cleared NABARD was transferred 4 fewer times than the person who cleared CHSL.

(Implies, A was transferred 5 times.)

Clearly, A cleared NABARD and he has been transferred 5 times till now.

1) The exam that H took was more difficult than at least four exams.

(Implies, H appeared for one of the top four difficult exams i.e. UPSC, CA, CAT, and CGL.)

2) Neither G nor H appeared for either CA or CAT.

(Implies, H appeared for either UPSC or CGL.)

3) F was transferred 13 fewer times than H who was transferred the maximum number of times.

4) The person who appeared for UPSC was transferred 5 fewer times than the person who appeared for MTS.

(Implies, the person appeared for UPSC was not transferred the highest number of times. Hence, H appeared for CGL.)

5) No person appeared for the more difficult exam than F that implies F has appeared for the most difficult exam i.e. UPSC

Now as we know that H appeared for CGL,

H – F = 13

H + F = 43

(Implies, H was transferred 28 times and F was transferred 15 times.)

6) D cleared either MTS or CGL.

(As we know that H cleared CGL, implies, D cleared MTS.)

7) The total number of transfers of D and the person who cleared UPSC is 35.

(According to the fourth, sixth and the seventh statement,

D – The person appeared for UPSC = 5

D + The person appeared for UPSC = 35

Implies, D was transferred 20 times and the person who appeared for UPSC was transferred 15 times. It further implies that F appeared for UPSC as F was transferred 15 times.)

8) The difficulty level of the exam which C cleared is just below the difficulty level of the exam which was cleared by F.

(Implies, C cleared CA.)

9) B appeared for the exam which is difficult than the exam for which H appeared and B got 7 fewer transfers than H.

(As we know that F and C cleared UPSC and CA respectively, implies, B appeared for CAT. Also, as H was transferred 28 times, implies, B was transferred 21 times.)

10) A did not appear for either RBI or CHSL.

(Implies, A appeared for NABARD as it is the only possibility left.)

11) The total number of transfers of C is 60% of the total number of transfers of D and also, C was transferred 3 more times than G.

(Implies, C was transferred 12 times because D was transferred 20 times. It further implies that G was transferred 9 times.)

12) The person who cleared RBI was transferred 5 more times than the person who cleared CA.

(Implies, the person who cleared RBI was transferred 17 times because the person who cleared CA i.e. C was transferred 12 times. It further implies that G did not appear for RBI. So, now there is only one possibility i.e. G appeared for CHSL and E appeared for RBI.)

13) The person who cleared NABARD was transferred 4 fewer times than the person who cleared CHSL.

(Implies, A was transferred 5 times.)

Clearly, G cleared CHSL exam.

1) The exam that H took was more difficult than at least four exams.

(Implies, H appeared for one of the top four difficult exams i.e. UPSC, CA, CAT, and CGL.)

2) Neither G nor H appeared for either CA or CAT.

(Implies, H appeared for either UPSC or CGL.)

3) F was transferred 13 fewer times than H who was transferred the maximum number of times.

4) The person who appeared for UPSC was transferred 5 fewer times than the person who appeared for MTS.

(Implies, the person appeared for UPSC was not transferred the highest number of times. Hence, H appeared for CGL.)

5) No person appeared for the more difficult exam than F that implies F has appeared for the most difficult exam i.e. UPSC

Now as we know that H appeared for CGL,

H – F = 13

H + F = 43

(Implies, H was transferred 28 times and F was transferred 15 times.)

6) D cleared either MTS or CGL.

(As we know that H cleared CGL, implies, D cleared MTS.)

7) The total number of transfers of D and the person who cleared UPSC is 35.

(According to the fourth, sixth and the seventh statement,

D – The person appeared for UPSC = 5

D + The person appeared for UPSC = 35

Implies, D was transferred 20 times and the person who appeared for UPSC was transferred 15 times. It further implies that F appeared for UPSC as F was transferred 15 times.)

8) The difficulty level of the exam which C cleared is just below the difficulty level of the exam which was cleared by F.

(Implies, C cleared CA.)

9) B appeared for the exam which is difficult than the exam for which H appeared and B got 7 fewer transfers than H.

(As we know that F and C cleared UPSC and CA respectively, implies, B appeared for CAT. Also, as H was transferred 28 times, implies, B was transferred 21 times.)

10) A did not appear for either RBI or CHSL.

(Implies, A appeared for NABARD as it is the only possibility left.)

11) The total number of transfers of C is 60% of the total number of transfers of D and also, C was transferred 3 more times than G.

(Implies, C was transferred 12 times because D was transferred 20 times. It further implies that G was transferred 9 times.)

12) The person who cleared RBI was transferred 5 more times than the person who cleared CA.

(Implies, the person who cleared RBI was transferred 17 times because the person who cleared CA i.e. C was transferred 12 times. It further implies that G did not appear for RBI. So, now there is only one possibility i.e. G appeared for CHSL and E appeared for RBI.)

13) The person who cleared NABARD was transferred 4 fewer times than the person who cleared CHSL.

(Implies, A was transferred 5 times.)

Clearly, E appeared for RBI and he has experienced 17 transfers so far.

1) The exam that H took was more difficult than at least four exams.

(Implies, H appeared for one of the top four difficult exams i.e. UPSC, CA, CAT, and CGL.)

2) Neither G nor H appeared for either CA or CAT.

(Implies, H appeared for either UPSC or CGL.)

3) F was transferred 13 fewer times than H who was transferred the maximum number of times.

4) The person who appeared for UPSC was transferred 5 fewer times than the person who appeared for MTS.

(Implies, the person appeared for UPSC was not transferred the highest number of times. Hence, H appeared for CGL.)

5) No person appeared for the more difficult exam than F that implies F has appeared for the most difficult exam i.e. UPSC

Now as we know that H appeared for CGL,

H – F = 13

H + F = 43

(Implies, H was transferred 28 times and F was transferred 15 times.)

6) D cleared either MTS or CGL.

(As we know that H cleared CGL, implies, D cleared MTS.)

7) The total number of transfers of D and the person who cleared UPSC is 35.

(According to the fourth, sixth and the seventh statement,

D – The person appeared for UPSC = 5

D + The person appeared for UPSC = 35

Implies, D was transferred 20 times and the person who appeared for UPSC was transferred 15 times. It further implies that F appeared for UPSC as F was transferred 15 times.)

8) The difficulty level of the exam which C cleared is just below the difficulty level of the exam which was cleared by F.

(Implies, C cleared CA.)

9) B appeared for the exam which is difficult than the exam for which H appeared and B got 7 fewer transfers than H.

(As we know that F and C cleared UPSC and CA respectively, implies, B appeared for CAT. Also, as H was transferred 28 times, implies, B was transferred 21 times.)

10) A did not appear for either RBI or CHSL.

(Implies, A appeared for NABARD as it is the only possibility left.)

11) The total number of transfers of C is 60% of the total number of transfers of D and also, C was transferred 3 more times than G.

(Implies, C was transferred 12 times because D was transferred 20 times. It further implies that G was transferred 9 times.)

12) The person who cleared RBI was transferred 5 more times than the person who cleared CA.

(Implies, the person who cleared RBI was transferred 17 times because the person who cleared CA i.e. C was transferred 12 times. It further implies that G did not appear for RBI. So, now there is only one possibility i.e. G appeared for CHSL and E appeared for RBI.)

13) The person who cleared NABARD was transferred 4 fewer times than the person who cleared CHSL.

(Implies, A was transferred 5 times.)

Clearly, NABARD, CHSL and MTS are the top three easiest exams and the total number of transfers in these three is 34.

On Combining: Y > S = R ≥ Z > T; Y > R > U;

Conclusions:

I. U > Z → False (as R ≥ Z and R > U thus no clear relation between Z and U)

II. S = U → False (as R = S > U)

III. Y > T → True (as Y > S = R ≥ Z > T → Y > T)

IV. U = Z → False (as R ≥ Z and R > U thus no clear relation between Z and U)

EVOLVE → 546345

2) Also, as there are two E's in the word, so both the E will be coded % according to the 2nd condition.

EVOLVE → 546345 → %4634%

3) Also, as the word starts and ends with a vowel, so the first letter will be coded $ as per the 4th condition.

EVOLVE → 546345 → %4634% → $4634%

Thus, the code for the word EVOLVE is $4634%.

ELECTION → 53532965

2) Also, as there are two E's in the word, hence both the E will be coded % according to the 2nd condition.

ELECTION → 53532965 → %3%32965

3) Also, as the word starts with a vowel and ends with a consonant, hence both these letters will be coded @ according to the last condition.

ELECTION → 53532965 → %3%32965 → @3%3296@

Thus, the code for the word ELECTION is @3%3296@.

MOBILE → 462935

Also, as the word starts with a consonant and ends with a vowel the codes of these two letters will be interchanged as per the 5th condition.

MOBILE → 462935 → 562934

Thus, 562934 is the code for the word MOBILE.

By the given information,

On replacing '0' by '£' and '1' by '¥',

¥ ¥ £ ¥ ¥ ¥ ¥ → 1101111

Binary code for 99:

Clearly, 1100011 is not equal to 1101111.

Binary code for 121:

Clearly, 1111001 is not equal to 1101111.

Binary code for 111:

Clearly, '1101111' is the code for '111'.

We don't need to check further options after this.

By the given information,

To get the binary equivalent of '2157', we use the method of successive division by 2.

By counting the binary number upward we get,

The binary code for '2157' → 100001101101

On replacing '0' by '£' and '1' by '¥',

The code for '2157' → ¥ £ £ £ £ ¥ ¥ £ ¥ ¥ £ ¥

Hence, ¥ £ £ £ £ ¥ ¥ £ ¥ ¥ £ ¥ is the correct answer.

By the given information,

To get the binary equivalent of '1581', we use the method of successive division by 2.

By counting the binary number upward we get,

The binary code for '1581' → 11000101101

On replacing '0' by '£' and '1' by '¥',

The code for '1581' → ¥ ¥ £ £ £ ¥ £ ¥ ¥ £ ¥

By the given information,

On replacing '0' by '£' and '1' by '¥',

¥ £ ¥ £ £ £ ¥ → 1010001

Binary code for 71:

Clearly, 1000111 is not equal to 1010001.

Binary code for 61:

Clearly, 111101 is not equal to 1010001.

Binary code for 81:

Clearly, '1010001' is the code for '81'

Conclusions:

I. M > D – true as M ≥ L > D

II. M = B – false as B > K = M → M < B

III. L = K – false as K = M ≥ L → K ≥ L, thus a clear relation between L and K cannot be determined.

1) Chinmay is sitting immediate left of Debina at a distance of 8.5Km.

2) Only two persons are sitting between Bindu and Chinmay who is sitting 4Km away from Chaitra.

3) Banuis sitting second to right of Amrita who is sitting 5.5Km away from Akash.

4) Distance between Akash and Bindu who is sitting one of the places to left of Banu is 8Km. Case 2 is eliminated because only seven people are sitting in a row.

Case3 is eliminated because distance between Amrita and Akash is 5. 5km but distance between Akash and Bindu who is sitting between Amrita and Akash is 8km.

5. Distance between Banu and the one who is sitting second to left of Chaitra is 7Km.

6. Debina starts to move in East direction, after moving 8Km reached to K, and then she started to walk in south direction to reach G which is 10km from K.

7. The person who is sitting immediate right of Bindu starts to walk for 6Km in south direction and reached T then the person turns to left and starts running for 5Km to reach J.

8. Amrita starts to move in north-east direction, after walking 4Km reached to S.

1) Chinmay is sitting immediate left of Debina at a distance of 8.5Km.

2) Only two persons are sitting between Bindu and Chinmay who is sitting 4Km away from Chaitra.

3) Banuis sitting second to right of Amrita who is sitting 5. 5Km away from Akash.

4) Distance between Akash and Bindu who is sitting one of the places to left of Banu is 8Km. Case 2 is eliminated because only seven people are sitting in a row.

Case3 is eliminated because distance between Amrita and Akash is 5.5km but distance between Akash and Bindu who is sitting between Amrita and Akash is 8km.

5. Distance between Banu and the one who is sitting second to left of Chaitra is 7Km.

6. Debina starts to move in East direction, after moving 8Km reached to K, and then she started to walk in south direction to reach G which is 10km from K.

7. The person who is sitting immediate right of Bindu starts to walk for 6Km in south direction and reached T then the person turns to left and starts running for 5Km to reach J.

8. Amrita starts to move in north-east direction, after walking 4Km reached to S.

1) Chinmay is sitting immediate left of Debina at a distance of 8.5Km.

2) Only two persons are sitting between Bindu and Chinmay who is sitting 4Km away from Chaitra.

3) Banuis sitting second to right of Amrita who is sitting 5. 5Km away from Akash.

4) Distance between Akash and Bindu who is sitting one of the places to left of Banu is 8Km. Case 2 is eliminated because only seven people are sitting in a row.

Case3 is eliminated because distance between Amrita and Akash is 5. 5km but distance between Akash and Bindu who is sitting between Amrita and Akash is 8km.

5. Distance between Banu and the one who is sitting second to left of Chaitra is 7Km.

6. Debina starts to move in East direction, after moving 8Km reached to K, and then she started to walk in south direction to reach G which is 10km from K.

7. The person who is sitting immediate right of Bindu starts to walk for 6Km in south direction and reached T then the person turns to left and starts running for 5Km to reach J.

8. Amrita starts to move in north-east direction, after walking 4Km reached to S.

Distance between Chaitra and K = (distance between Chaitra and Chinmay) + (distance between Chinmay and Debina) + (distance between K and Debina)

Distance between Chaitra and K = 4 + 8. 5 + 8 = 20. 5Km.

1) Chinmay is sitting immediate left of Debina at a distance of 8. 5Km.

2) Only two persons are sitting between Bindu and Chinmay who is sitting 4Km away from Chaitra.

3) Banuis sitting second to right of Amrita who is sitting 5. 5Km away from Akash.

4) Distance between Akash and Bindu who is sitting one of the places to left of Banu is 8Km. Case 2 is eliminated because only seven people are sitting in a row.

Case3 is eliminated because distance between Amrita and Akash is 5. 5km but distance between Akash and Bindu who is sitting between Amrita and Akash is 8km.

5. Distance between Banu and the one who is sitting second to left of Chaitra is 7Km.

6. Debina starts to move in East direction, after moving 8Km reached to K, and then she started to walk in south direction to reach G which is 10km from K.

7. The person who is sitting immediate right of Bindu starts to walk for 6Km in south direction and reached T then the person turns to left and starts running for 5Km to reach J.

8. Amrita starts to move in north-east direction, after walking 4Km reached to S.

1) Chinmay is sitting immediate left of Debina at a distance of 8. 5Km.

2) Only two persons are sitting between Bindu and Chinmay who is sitting 4Km away from Chaitra.

3) Banuis sitting second to right of Amrita who is sitting 5. 5Km away from Akash.

4) Distance between Akash and Bindu who is sitting one of the places to left of Banu is 8Km. Case 2 is eliminated because only seven people are sitting in a row.

Case3 is eliminated because distance between Amrita and Akash is 5. 5km but distance between Akash and Bindu who is sitting between Amrita and Akash is 8km.

5. Distance between Banu and the one who is sitting second to left of Chaitra is 7Km.

6. Debina starts to move in East direction, after moving 8Km reached to K, and then she started to walk in south direction to reach G which is 10km from K.

7. The person who is sitting immediate right of Bindu starts to walk for 6Km in south direction and reached T then the person turns to left and starts running for 5Km to reach J.

8. Amrita starts to move in north-east direction, after walking 4Km reached to S.

Distance between S and Bindu = 42 – (2. 5)2 = 16 – 6. 25 = √ 9. 75Km.

Z is heavier than B.

Z > B

From statement II:

Y is not as heavy as either A or Z.

A > Y or Z > Y

From statement III:

B is neither the heaviest nor the lightest.

Question cannot be answered with all the statements together.

Conclusions:

I. Some windows are walls → False (it is possible but not definite)

II. Some windows are shadow → False (it is possible but not definite)

III. Some rooms are walls → True (Some walls are room is true in statement, hence some rooms are walls is also true)

Conclusion:

I. Some paper are pencil → False (it is possible but not definite because there is no definite relation between Paper and Pencil)

II. Some bag are book → True (All book are paper and all paper are bag, hence some bag are book is true)

III. All book are bag → True (All book are paper and all paper are bag, hence all book are bag is true)

From statement II: R is 3m to the south of M. S is 5m to the east of T. T is 2m to the south of R. W is 4m to the south of S.

From statement III: U is 7m to the west of N. S is 4m to the west of U. V is 8m to the south of U.

From statement II and III together:

Thus, statement II and III together are required to answer the question..

Therefore, the course of action I follow. The course of action II suggests that minimum passing marks should be brought down after revision so that each student manages to pass comfortably. This devalues the process and defeats the purpose of conducting the examination.

Therefore, the course of action II does not follow.

(Implies, both A and the person who is 39 years old are sitting in the second row. Also, there are only two possibilities i.e. A is sitting either on the 1st seat or the 2nd seat of the second row.)

2) The age of the person sitting right behind A is 1 year less than twice the age of A.

(Let us assume the age of A be X, implies, the age of the person sitting right behind him is 2X – 1.)

3) E is sitting two seats ahead of C whose age is numerically an even number.

4) K is sitting third to the right of E and the sum of their ages is 25 years.

(Implies, E is sitting in the first seat of the first row and K is sitting on the rightmost seat while C is sitting on the first seat of the 4th row. Also, as we know the age of the person sitting right behind A is 1year younger than twice the age of A (which will be numerically an odd number), implies, A is sitting on the 2nd seat in the 2nd row. Also, it means that D is sitting on the rightmost seat in the 2nd row.)

5) The age of K is 1 year less than thrice the age of the person who is sitting immediately behind him.

(Implies, K is 12 years old. Also, according to the 4th statement, the age of E is 13 years.)

6) J is sitting immediately in front of F.

7) H is sitting second to the left of J and H is 21 years younger than J.

(It is only possible if F is sitting on the third seat from the left in the 3rd row and J is sitting immediately in front of him in the 2nd row.)

8) B is sitting to the immediate left of the person who is sitting right in front of D.

(Implies, B is sitting to the immediate left of K as it is the only possibility.)

9) The difference between the ages of A and L is 47 years.

10) L is 15 years older than the person who is sitting second to his left.

(It is only possible if we place L on the rightmost seat in the 3rd row. Also, as the age of the person who is sitting second to the left of L is 2X – 1 years old, implies, the age of L is 2X + 14 years.

Now,

2X + 14 – X = 47 years

X = 33 years

11) The difference between the ages of the two people who are sitting on the extreme ends in the third row is 8 years.

12) The age of H is 45 years less than the person sitting immediately behind him.

(Implies, the age of C is either 72 years or 88 years. Let us assume that C is 88 years old then that would mean H is 43 years old.)

13) The age of B is one third the age of the person who is sitting immediately behind E but half the age of the person who is sitting to his immediate left.

(Clearly, H is sitting immediately behind E. If the age of H is 43 years then the age of B would not be a natural number. Implies, the age of C is 72 years, the age of H is 27 years and the age of B is 9 years. Also, it means that the age of the person who is sitting to the immediate left of B is 18 years.)

14) J is 6 years younger than F but 30 years younger than G.

(As J is 30 years younger than G, implies, G must be in the row that is ahead of J’s row. Hence, G is sitting between E and B in the 1st row and he is 18 years old. Implies, J is 48 years old and F is 54 years old. Also, now that only I is left to be placed, we can safely say that I is sitting between C and F.)

Clearly, H is the youngest person in the 2nd row.