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Assertion & Reason Test: Coordination Compounds - NEET MCQ


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10 Questions MCQ Test Topic-wise MCQ Tests for NEET - Assertion & Reason Test: Coordination Compounds

Assertion & Reason Test: Coordination Compounds for NEET 2024 is part of Topic-wise MCQ Tests for NEET preparation. The Assertion & Reason Test: Coordination Compounds questions and answers have been prepared according to the NEET exam syllabus.The Assertion & Reason Test: Coordination Compounds MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Assertion & Reason Test: Coordination Compounds below.
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Assertion & Reason Test: Coordination Compounds - Question 1

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Toxic metal ions are removed by the chelating ligands.

Reason (R): Chelate complexes tend to be more stable.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 1
When a solution of chelating ligand is added to solution containing toxic metal ligands chelates the metal ions by formation of stable complex.
Assertion & Reason Test: Coordination Compounds - Question 2

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion: A mong [CO(NH3)6]3+ and [CO(en)3]3+, coordination compound [CO(en)3]3+ is a more stable complex.

Reason: Because (en) is a chelating ligand/bidentate ligand.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 2
Since (ethylene diamine-en) is a chelating ligand/bidentate ligand, [CO(en3)]3+ is a more stable complex as compared to the other one.

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Assertion & Reason Test: Coordination Compounds - Question 3

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 are reducing in nature.

Reason (R): Unpaired electrons are present in their d-orbitals.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 3
In the complexes, Co exists as Co2+ and Fe as Fe2+. Both of the complexes become Stable by oxidation of metal ion to Co3+ and Fe3+.
Assertion & Reason Test: Coordination Compounds - Question 4

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Low spin tetrahedral complexes are rarely observed.

Reason (R): Crystal field splitting is less than pairing energy for tetrahedral complexes.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 4
In tetrahedral complexes, the splitting of the d-orbitals is inverted and is smaller in comparison to octahedral complexes. The Crystal field splitting energy is not large enough to force pairing and hence, low spin complexes are rarely observed.
Assertion & Reason Test: Coordination Compounds - Question 5

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Linkage isomerism arises in coordination compounds containing ambidentate ligand.

Reason (R): Ambidentate ligand has two different donor atoms.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 5
Linkage isomerism arises due to two different donor atoms in ambidentate ligand.
Assertion & Reason Test: Coordination Compounds - Question 6

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): [Fe(CN)6]3− ion shows magnetic moment corresponding to two unpaired electrons.

Reason (R): Because it has d2sp3 type hybridisation.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 6

[Fe(CN)6]3− ion shows magnetic moment corresponding to two unpaired electrons.

Assertion & Reason Test: Coordination Compounds - Question 7

Directions: In the following questions, A statement of Assertion (A) is followed by a statement of Reason (R). Mark the correct choice as.

Assertion (A): Complexes of MX6 and MX5L type (X and L are unidentate) do not show geometrical isomerism.

Reason (R): Geometrical isomerism is not shown by complexes of coordination number 6.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 7

In MX& MX5 complexes there are four ligands in the same plane and all are identical ligands linked to the metal atom, so they don't show geometrical isomerism.

Thus, the assertion statement is correct.

Reason: In reason it is given that complexes with coordination number 6 will not show geometrical isomerism. Reason is wrong here as compounds with coordination number 6 have octahedral geometry and they can show geometrical isomerism. 

So, the reason is false.
Hence, assertion is true but reason is false.

Assertion & Reason Test: Coordination Compounds - Question 8

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

Assertion : NF3 is a weaker ligand than N(CH3)3.

Reason : NF3 ionizes to give F ions in aqueous solution.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 8
It is a correct statement that NF3 ​ is a weaker ligand than N(CH3)3, the reason is that fluorine is highly electronegative therefore, it withdraws electrons from the nitrogen atom. Hence, the lone pair of nitrogen atoms cannot be ligated. While N(CH3)3​ is a strong ligand because CH3​ has an electron releasing group.
Assertion & Reason Test: Coordination Compounds - Question 9

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

Assertion : [Ti(H2O)6]3+ is coloured while [Sc(H2O)6]3+ is colourless.

Reason : d-d transition is not possible in [Sc(H2O)6]3+.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 9
Ti has the electronic configuration [Ar] 3d2. In [Ti(H2O)6]3+ complex it is present as Ti3+ which has one unpaired electron in 3d orbital.Thus d-d transition is possible only in Ti(H2O)63+ and thereby it shows colour And also it undergoes d2sp3 (octahedral) hybridization to accomodate 6 pairs of water.

So the complex is octahedral in shape, will be coloured and paramagnetic due to presence of one unpaired electron.

Sc has the electronic configuration [Ar]3d1 . Since it is present in the complex [Sc(H2O)6]3+ as Sc3+ it has no unpaired electron. It will also undergo d2sp3 hybridization to accomodate 6 pairs of electrons from water.

So it is also octahedral, colourless and diamagnetic due to absence of unpaired electron.

Assertion & Reason Test: Coordination Compounds - Question 10

Directions: These questions consist of two statements, each printed as Assertion and Reason. While answering these questions, you are required to choose any one of the following four responses.

Assertion : [Fe(CN)6]3– is weakly paramagnetic while [Fe(CN)6]4– is diamagnetic.

Reason : [Fe(CN)6]3– has +3 oxidation state while [Fe(CN)6]4– has +2 oxidation state.

Detailed Solution for Assertion & Reason Test: Coordination Compounds - Question 10
Paramagnetic Character depends on the number of unpaired electrons. In the [Fe(CN)6]3– has 1 unpaired electron, therefore, it is paramagnetic whereas [Fe(CN)6]3– is diamagnetic because it does not have unpaired electrons.
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