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std::vector<bool> is a specialized version of vector, which is used for elements of type bool and optimizes for space. It behaves like the unspecialized version of vector and the storage is not necessarily an array of bool values, but the library implementation may optimize storage so that each value is stored in a single bit.
A pointer can be implicitly converted to a bool. A nonzero pointer converts to true and zero valued pointer converts to false.
For what values of the expression is an ifstatement block not executed?
The ifstatement block is only not executed when the expression evaluates to 0. its just syntactic sugar for a branchifzero instruction.
What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int f(int p, int q)
{
if (p > q)
return p;
else
return q;
}
main()
{
int a = 5, b = 10;
int k;
bool x = true;
bool y = f(a, b);
k =((a * b) + (x + y));
cout << k;
}
In this question, value of x = true and value of y will be also true as f(a,b) will return a nonzero value. Now when adding these values with integers, the implicit type conversion takes place hence converting both x and y to 1(integer equivalent of bool true value). So expression (a*b) + (x+y) is evaluated to 52.
The given expression is equivalent to
[( false AND True) OR false OR true] This is OR or three values so if any of them will be true then the whole exp will be true and as we have last value as true so the answer of expression will be TRUE.
C++ has bool as a fundamental data type.
The given number is a double not an integer, so the function returns 0 which is boolean false.
Boolean can be used as a return value of a function.
Which of the two operators ++ and — work for the bool data type in C++?
Due to the history of using integer values as booleans, if an integer is used as a boolean, then incrementing will mean that whatever its truth value before the operation, it will have a truthvalue of true after it. However, it is not possible to predict the result of — given knowledge only of the truth value of x, as it could result in false.
What is the value of p in the following C++ code?
#include <iostream>
using namespace std;
int main()
{
int p;
bool a = true;
bool b = false;
int x = 10;
int y = 5;
p = ((x  y) + (a + b));
cout << p;
return 0;
}
 means bitwise OR operation so x  y (0101  1010) will be evaluated to 1111 which is integer 15 and as a is true and b is false so a+b(1 + 0) = 1. So final value of expression in line #10 will be 15 + 1 = 16.
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