Test: C++ Structures
10 Questions MCQ Test C++ Programming for Beginners | Test: C++ Structures
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While terminating a structure, a semicolon is used to end this up.
The structure declaration with open and close braces and with a semicolon is also called structure specifier.
What will be the output of the following C++ code?
#include <iostream>
using namespace std;
struct Time
{
int hours;
int minutes;
int seconds;
};
int toSeconds(Time now);
int main()
{
Time t;
t.hours = 5;
t.minutes = 30;
t.seconds = 45;
cout << "Total seconds: " << toSeconds(t) << endl;
return 0;
}
int toSeconds(Time now)
{
return 3600 * now.hours + 60 * now.minutes + now.seconds;
}
using namespace std;
struct Time
{
int hours;
int minutes;
int seconds;
};
int toSeconds(Time now);
int main()
{
Time t;
t.hours = 5;
t.minutes = 30;
t.seconds = 45;
cout << "Total seconds: " << toSeconds(t) << endl;
return 0;
}
int toSeconds(Time now)
{
return 3600 * now.hours + 60 * now.minutes + now.seconds;
}
In this program, we are just converting the given hours and minutes into seconds.
Output:
$ g++ stu1.cpp
$ a.out
Total seconds:19845
What will be the output of the following C++ code?
#include <iostream>
using namespace std;
struct sec
{
int a;
char b;
};
int main()
{
struct sec s ={25,50};
struct sec *ps =(struct sec *)&s;
cout << ps->a << ps->b;
return 0;
}
In this program, We are dividing the values of a and b, printing it.
Output:
$ g++ stu5.cpp
$ a.out
252
Because arrow operator(->) is used to access members of structure pointer whereas dot operator(.) is used to access normal structure variables.
Variables declared inside a class are called as data elements or data members.
While the structure is declared, it will not be initialized, So it will not allocate any memory.
What will be the output of the following C++ code?
#include <iostream>
#include <string.h>
using namespace std;
int main()
{
struct student
{
int num;
char name[25];
};
student stu;
stu.num = 123;
strcpy(stu.name, "John");
cout << stu.num << endl;
cout << stu.name << endl;
return 0;
}
We are copying the value john to the name and then we are printing the values that are in the program.
Output:
$ g++ stu.cpp
$ a.out
123
john
What will be the output of the following C++ code?
#include <iostream>
using namespace std;
int main()
{
struct ShoeType
{
string style;
double price;
};
ShoeType shoe1, shoe2;
shoe1.style = "Adidas";
shoe1.price = 9.99;
cout << shoe1.style << " $ "<< shoe1.price;
shoe2 = shoe1;
shoe2.price = shoe2.price / 9;
cout << shoe2.style << " $ "<< shoe2.price;
return 0;
}
We copied the value of shoe1 into shoe2 and divide the shoe2 value by 9, So this is the output.
Output:
$ g++ stu2.cpp
$ a.out
Adidas $ 9.99
Adidas $ 1.11
option struct {int a;} is not correct because name of structure and ;(after declaration) are missing. In option struct a_struct {int a;} ; is missing. In option struct a_struct int a; {} are missing.
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