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# Miscellaneous Test: Number Series- 4

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## 25 Questions MCQ Test Logical Reasoning (LR) and Data Interpretation (DI) | Miscellaneous Test: Number Series- 4

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Miscellaneous Test: Number Series- 4 - Question 1

### Directions to Solve: Choose the correct alternative that will continue the same pattern and replace the question mark in the given series. Question. 120, 99, 80, 63, 48, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 1

1st term = 120
2nd term = 120-21 = 99
3rd term = 99-19 = 80
4th term = 80 - 17 = 63
5th term = 63 - 15 = 48

⇒ For every next term , preious term is substracteed in the order: -21, -19, -17, -15, -13,.....

So, missing term = 48 - 13 = 35

Miscellaneous Test: Number Series- 4 - Question 2

### Directions to Solve: Choose the correct alternative that will continue the same pattern and replace the question mark in the given series. Question: 589654237, 89654237, 8965423, 965423, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 2

The digits are removed one by one from the beginning and the end in order alternately.

So, as to obtain the subsequent terms of the series.
1st term = 589654237
2nd term = 89654237
3rd term = 8965423
4th term = 965423
5th term = 96542

Miscellaneous Test: Number Series- 4 - Question 3

### Directions to Solve: Choose the correct alternative that will continue the same pattern and replace the question mark in the given series. Question: 3, 10, 101,?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 3

Each term in the series is obtained by adding 1 to the square of the preceding term.

So, missing term = (101)2 + 1 = 10202.

Miscellaneous Test: Number Series- 4 - Question 4

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: In series 2, 6, 18, 54, ...... what will be the 8th term ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 4

1st term = 2 x 3 = 6
2nd term = 6 x 3 = 18
3rd term = 18 x 3 = 54,.....
⇒ Series is a G.P. in which a = 2, r = 3.

∴ 8th term = ar8-1 = ar7 = 2 x 37 = (2 x 2187) = 4374.

Miscellaneous Test: Number Series- 4 - Question 5

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 125, 80, 45, 20,?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 5

1st term = 125
2nd term = 125 - 45 = 80
3rd term = 80 - 35 = 45
4th term = 45- 25 = 20

⇒ For every next term, preious term is substracteed in the order: - 45, - 35, - 25, .....

So, missing term = 20 - 15 = 5

Miscellaneous Test: Number Series- 4 - Question 6

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 1, 1, 4, 8, 9, 27, 16, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 6

The series consists of squares and cubes of consecutive natural numbers i.e. 12, 13, 22, 23, 32, 33, 42, .....

So, missing term = 43 = 64.

Miscellaneous Test: Number Series- 4 - Question 7

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 1, 2, 3, 6, 9, 18, ?, 54

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 7

1st term = 1
2nd term = 1 * 2 = 2
3rd term = 2 * 3/2 = 3
4th term = 3 * 2 = 6
5th term = 6 * 3/2 = 9
6th term = 9 * 2 =18
7th term = ?
8th term = 54

⇒ For every even position term, the previous term is multiplied by 2 and for the odd positioned term, the previous term is multiplied by 3/2

So, missing term = 18 x 3/2 = 27.

Miscellaneous Test: Number Series- 4 - Question 8

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 6, 13, 25, 51, 101, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 8

1st term = 6
2nd term = (6 * 2) + 1 = 13
3rd term = (13 * 2) -1 = 25
4th term = (25 * 2) +1 = 51
5th term = (51 * 2) - 1 = 101
6th term = ?

⇒ For every even position term, the previous term is multiplied by 2 and then  1 is added and for the odd positioned term, the previous term is multiplied by 2 and 1 is substracted

So, missing term = (101 * 2) + 1 = 203.

Miscellaneous Test: Number Series- 4 - Question 9

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 5,6,9, 15, ?, 40

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 9

1st term = 5
2nd term = 5 + 1 = 6
3rd term = 6 + 3 = 6 + (1 + 2) = 9
4th term = 9 + 6 = 9 + (1 + 2 + 3) = 15
5th term = x
6th term = 40

⇒ For every term previous term is added with sumation of it previous position i.e. next term = previous term + ∑ (position -1)

So, missing term = 15 + (1 + 2 + 3 + 4) = 25

Miscellaneous Test: Number Series- 4 - Question 10

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 1, 3, 4, 8, 15, 27, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 10

The sum of any three consecutive terms of the series gives the next term i.e.
► 1 + 3 + 4 = 8
► 3 + 4 + 8 = 15
► 4 + 8 + 15 = 27

∴ Missing number = 8 + 15 + 27 = 50

Miscellaneous Test: Number Series- 4 - Question 11

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 3, 4, 7, 7, 13, 13, 21, 22, 31, 34, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 11

The given sequence is a combination of two series:

• 3, 7, 13, 21, 31, ?
For every next term = previous term + 2 * its position
i.e. 3, 3+2*2, 7 +3*2,  13 + 4*2 ....
• 4, 7, 13, 22, 34
For every next term = previous term + 3 * (its position-1)
i.e. 4, 4+3*1, 7 +3*2,  13 + 3*3 ....

So, missing term = 31 + 2*6 = 43.
As missing term lies in 1st pattern.

Miscellaneous Test: Number Series- 4 - Question 12

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 198, 194, 185, 169, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 12

1st term = 198
2nd term = 198 - 4 = 198 - 22 = 194
3rd term = 194 - 9 = 198 - 32 = 185
4th term = 185 - 16 = 185 - 42 = 169

⇒ For next term, square of its positon is substracted from the previous term

So, missing pattern = 169 - 52 = 169 - 25 = 144.

Miscellaneous Test: Number Series- 4 - Question 13

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 2, 3, 5,7,11,?, 17

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 13

Clearly, the given series consists of prime numbers starting from 2.

So, the missing term is the prime number after 11, which is 13.

Miscellaneous Test: Number Series- 4 - Question 14

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 6, 12, 21, ?, 48

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 14

1st term = 6
2nd term = 6 + 6 = 6 + 2*3 = 12
3rd term = 12 + 9 = 12 + 3*3 = 21
4th term = ?
5th term = 48

⇒ For every next term, thrice its positon is added o the previous term.

So, missing term = 21 + 3*4 = 33.

Miscellaneous Test: Number Series- 4 - Question 15

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: Which term of the series 5, 10, 20, 40, ..... is 1280?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 15

1st term = 5 x 2 = 10
2nd term = 10 x 2 = 20
3rd term = 20 x 2 = 40,.....

⇒ Series is a G.P. in which a = 5 and r = 2.

Let 1280 be the nth term of the series.
⇒ 5 x 2n-1 = 1280
⇒ 2n-1 = 256 = 28
⇒ n - 1 = 8
⇒ n = 9

Miscellaneous Test: Number Series- 4 - Question 16

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 2, 5, 9, ?, 20, 27

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 16

1st term = 2
2nd term = 2 + 3 = 2 + (2+1) = 5
3rd term = 5 + 4 = 5 + (3+1) = 9...

⇒ For next term, its position +1 is added to the previous term

So, missing term = 9 + 5 = 14

Miscellaneous Test: Number Series- 4 - Question 17

Directions to solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question:
2, 3, 3, 5, 10, 13, ?, 43, 172, 177

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 17

1st term = 2
2nd term = 2 + 1 = 3
3rd term = 3 * 1 = 3
4th term = 3 + 2 = 5
5th term = 5 * 2 = 10
6th term = 10 + 3 = 13...

⇒ For every term at even position, previous term is added with half of the position
⇒ For every term at odd position, previous term is multipiled with the same numeber that was added in previous term

So, missing term = 13 x 3 = 39.

Miscellaneous Test: Number Series- 4 - Question 18

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 9, 27, 31, 155, 161, 1127, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 18 ⇒ For every term at even position, previous term is multiplied with the position+1
⇒ For every term at odd position, previous term is added with the position+1

So, missing term = 1127 + 8 = 1135.

Miscellaneous Test: Number Series- 4 - Question 19

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 2, 1, 2, 4, 4, 5, 6, 7, 8, 8, 10, 11, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 19

The given sequence is a combination of three series:

• 1st, 4th, 7th, 10th, 13th terms i.e. 2, 4, 6, 8,?
• 2nd, 5th, 8th, 11th terms i.e. 1, 4, 7, 10
• 3rd, 6th, 9th, 12th terms i.e. 2, 5, 8, 11

Clearly, I consist of consecutive even numbers. So, the missing term is 10.

Miscellaneous Test: Number Series- 4 - Question 20

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: Which of the following will not be a number of the series 1, 8, 27, 64, 125,.....?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 20
• The given series consists of cubes of natural numbers only.
• 256 is not the cube of any natural number.
Miscellaneous Test: Number Series- 4 - Question 21

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 13, 32, 24, 43, 35, ?, 46, 65, 57, 76

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 21

The given sequence is a combination of two series:

• 13, 24, 35, 46, 57
• 32, 43, ?, 65, 76

In both series are in A.P. with common difference of 11.

So, missing term = 43 + 11 = 54.

Miscellaneous Test: Number Series- 4 - Question 22

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question -
22, 24, 28, ?, 52, 84

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 22

1st term = 22
2nd term = 22 + 2 = 22 + 2= 24
3rd term = 24 + 4 = 22 + 2= 28
4th term =?
5th term = 52
6th term = 52 + 32 = 52 + 2=84

⇒ For next term, preivous term is add with 2 to the power of the position-1.
i.e. any term = previous term + 2(position - 1)

So, missing term = 28 + 8 = 22 + 2= 36

Miscellaneous Test: Number Series- 4 - Question 23

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 3, 15, ?, 63, 99, 143

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 23

1st term = (22 - 1)
2nd term = (42 - 1)
3rd term= ?
4th term = (82 - 1)
5th term = (102 - 1)
6th term = (122 - 1)

⇒ nth term = (n * 2)2 - 1

So, missing term = (62 - 1) = (36 - 1) = 35

Miscellaneous Test: Number Series- 4 - Question 24

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question -
90, 180, 12, 50, 100, 200, ?, 3, 50, 4, 25, 2, 6, 30, 3

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 24

Clearly the pattern is:

► 90 = 30 x 3,
► 180 = 6 x 30,
► 12 = 2 x 6,
► 50 = 25 x 2,
► 100 = 4 x 25,
► 200 = 50 x 4.

So, missing term = 3 x 50 = 150.

Alternatively,

The pattern is the combination of 2 series:

• 90, 180, 12, 50, 100, 200, ?
• 3, 50, 4, 25, 2, 6, 30, 3

after reversing 2nd series, i.e. 3, 30, 6, 2, 25, 4, 50, 3
on dividing term of the same position would give next term of reversed series.
i.e.

► 90/3 = 30
► 180/30 = 6
► 12/6 = 2
► 50/2 = 25
► 100/25 = 4
► 200/ 4 =50
► ?/50 = 3

So, missing term = 3 x 50 = 150.

Miscellaneous Test: Number Series- 4 - Question 25

Directions to Solve:
Choose the correct alternative that will continue the same pattern and replace the question mark in the given series.

Question: 48, 24, 96, 48, 192, ?

Detailed Solution for Miscellaneous Test: Number Series- 4 - Question 25

1st term = 48
2nd term = 48/2 = 24
3rd term = 24 * 4 = 96
4th term = 96/2 = 48
5th term = 48 * 4 = 192...

⇒ For every term at even position, previous term is divided by 2
⇒ For every term at odd position, previous term is multipiled with 4

So, missing term = 192 ÷ 2 = 96.

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