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This mock test of Electric Potential MCQ (With Solution) : Test 2 for Class 12 helps you for every Class 12 entrance exam.
This contains 25 Multiple Choice Questions for Class 12 Electric Potential MCQ (With Solution) : Test 2 (mcq) to study with solutions a complete question bank.
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QUESTION: 1

An electric field is expressed as . Find the potential diference (V_{A}-V_{B}) between two points A and B whose position vectors are given by and

Solution:

QUESTION: 2

The potential function of an electrostatic field is given by V = 2x^{2}. Determine the electric field strength at the point (2 m, 0.3 m).

Solution:

QUESTION: 3

Figure 3.79 shows equipotential surfaces concentric at O, the magnitude of electric field at a distance r measured from O is

Solution:

QUESTION: 4

The electric field in a certain region is A/x^{3}. Then the potential at a point (x,y, z), assuming the potential at infinity to be zero, is

Solution:

⇒

QUESTION: 5

Find the potential V of an electrostatic field , where a is constant.

Solution:

QUESTION: 6

Consider a system of three charge q/3,q/3 and -2q/3 placed at points A,B and C, respectively, as shown in figure. Take O to be the circle of radius R and angle CAB = 60^{°}.

Solution:

QUESTION: 7

Two equal positive charges are kept at points A and B.The electric potential at the points between A and B (excluding these points) is studied while moving from A to B. The potential

Solution:

If we draw a graph of v - r

We can clearly see that V first decreases and then increases.

QUESTION: 8

Figure shows three paths along which we can move positively charged sphere A closer to positively charged sphere B which is fixed in a plane. if W_{1}, W_{2} and W_{3} are the work done along the three respective paths, then

Solution:

As work done is path independent due to conservative nature of electric field. W_{1} = W_{2} = W_{3}

QUESTION: 9

The work done in moving an electron of charge e and mass m from A to B along the circular path (shown in figure) in the vertical plane in the field of charge Q is

Solution:

Work done by electric field will be zero as the semicircle will be equipotential, but we will have to consider the work done against gravity.

F = mg W = F 2r = 2 mgr

QUESTION: 10

Four similar point charges q are located at the vertices of a tetrahedron with an edge a. The energy of the interaction of charges is :

Solution:

There are 6 pairs at gap a each

QUESTION: 11

In the electric field of a point charge q, a certain charge is carried from point A to B, C, D and E. Then the work done

Solution:

The circle will be equipotential so work done will be zero for all paths.

QUESTION: 12

Four equal charges Q are placed at the four corners of a square of each side is a. Work done in removing a charge -Q from its centre of infinity is

Solution:

QUESTION: 13

Ten electrons are equally spaced and fixed around a circle of radius R. Relative to V = 0 at infinity, the electrostatic potential V and the electric field E at the centre C are

Solution:

V is scalar so it will just get added up so , is vector and its vecter sum will be zero.

QUESTION: 14

The displacement of a charge Q in the electric field . The work done is

Solution:

QUESTION: 15

Three charges Q + q and +q are placed at the vertices of a right-angled isosceles triangle as shown. The net electrostatic energy of the configuration is zero if Q is equal to

Solution:

QUESTION: 16

Electric potential at any point is V = - 5x +3y + √15z, then the magnitude of the electric field is

Solution:

V = -5x + 3y + √15z (in question is only over 15,

E = 7

QUESTION: 17

Equipotential surfaces associated with an electric field which is increasing in magnitude along the x-direction are.

Solution:

Eequipotential planes will be normal to field, so they are in y-z plane.

QUESTION: 18

Figure shown three points A,B and C in a region of uniform electric field The line AB is perpendicular and BC is parallel to the field lines. Then which of the following holds good. Where V_{A}, V_{B} and V_{C} represent the electric potential at points A,B and C respectively

Solution:

Electric field is always in direction of decreasing potential.

So V_{A} = V_{B} > V_{C}

QUESTION: 19

A charge +q is fixed at each of the points x = x_{0}, x = 3x_{0}, x = 5x_{0}....... infinite, on the x-axis and a charge -q is fixed at each of the points x = 2x_{0}, x = 4x_{0}, x = 6x_{0}..... infinite. Here x_{0} is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be . Then, the potential at the origin due to the above system of charges is

Solution:

QUESTION: 20

A non-conducting ring of radius 0.5 m carries a total charge of 1.11×10^{-10}C distributed non-uniformly on its circumference producing an electric field everywhere in space. The value of the line integral being centre of the ring) in volts is

Solution:

Point to remembe negative of line intergral of electric field gives us the potential at a point.

QUESTION: 21

A charged particle q is shot towards another charged particle Q which is fixed, with a speed v. It approaches Q upto a closest distance r and then returns. if q were given a speed 2v, the closest distances of approach would be

Solution:

For fixed charge

QUESTION: 22

The electric potential at a point distant r from an electric dipole is proportional to

Solution:

QUESTION: 23

In the electric field of a point charge q shown, a charge is carried from A to B and from A to C. Compare the work done

Solution:

As circle is equi potential V_{B} = V_{C} so work done comes out to be same as ΔV = same.

QUESTION: 24

The potential at a point x (measured in µm) due to some charges situated on the X-axis is given by

The electric field E at x = 4 µm is given by :

Solution:

QUESTION: 25

The electric potential at a point (x,y,z) is given by tential at a point (x,y,z) is given by V = x^{2} y - xz^{3} + 4

The electric field at that point is :

Solution:

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