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CAT Exam  >  CAT Tests  >  Level-wise Tests for CAT  >  Test Level 1: Line Graph - CAT MCQ

Test Level 1: Line Graph - CAT MCQ


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10 Questions MCQ Test Level-wise Tests for CAT - Test Level 1: Line Graph

Test Level 1: Line Graph for CAT 2024 is part of Level-wise Tests for CAT preparation. The Test Level 1: Line Graph questions and answers have been prepared according to the CAT exam syllabus.The Test Level 1: Line Graph MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 1: Line Graph below.
Solutions of Test Level 1: Line Graph questions in English are available as part of our Level-wise Tests for CAT for CAT & Test Level 1: Line Graph solutions in Hindi for Level-wise Tests for CAT course. Download more important topics, notes, lectures and mock test series for CAT Exam by signing up for free. Attempt Test Level 1: Line Graph | 10 questions in 20 minutes | Mock test for CAT preparation | Free important questions MCQ to study Level-wise Tests for CAT for CAT Exam | Download free PDF with solutions
Test Level 1: Line Graph - Question 1
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Directions: Study the following graph and answer the question that follows.

POWER PRODUCTION OF A COMPANY (IN MILLION WATTS)


Q. What is the difference between the peak hydel power production and the least Hydel Power Production ?

Detailed Solution for Test Level 1: Line Graph - Question 1

Difference between the peak hydel power production and the least hydel power production = 180 - 100 = 80 million watts
So, option (4) is correct.

Test Level 1: Line Graph - Question 2
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Directions: Study the following graph and answer the question that follows.

POWER PRODUCTION OF A COMPANY (IN MILLION WATTS)

Q. In which year is the total power production (thermal + hydel) the greatest?

Detailed Solution for Test Level 1: Line Graph - Question 2

Total power production (thermal and hydel) in 1990 = 140 + 140 = 280 million watts
Total power production (thermal and hydel) in 1991 = 140 + 180 = 320 million watts
Total power production (thermal and hydel) in 1992 = 100 + 120 = 220 million watts
Total power production (thermal and hydel) in 1993 = 150 + 130 = 280 million watts
Total power production (thermal and hydel) in 1994 = 155 + 145 = 300 million watts
Total power production (thermal and hydel) in 1995 = 153 + 141 = 294 million watts
Total power production (thermal and hydel) in 1996 = 145 + 145 = 290 million watts
The total power production is the greatest in 1991, i.e. 320 million watt.

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Test Level 1: Line Graph - Question 3
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Directions: Study the following graph and answer the question that follows.

POWER PRODUCTION OF A COMPANY (IN MILLION WATTS)

Q. What is the average thermal power production for the period 1990-1996?

Detailed Solution for Test Level 1: Line Graph - Question 3

Required average = = 141.85 million watts

Hence, option (4) is correct.

Test Level 1: Line Graph - Question 4
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Directions: Study the following graph carefully and answer the question given below.

Q. If the population of a city is 35,000 and the average income of a person in that city is Rs. 25,000 per annum, then what is the total amount of tax paid by all the persons of that city?
Detailed Solution for Test Level 1: Line Graph - Question 4

Tax paid by one person of that city = 8/100 x 25,000 = Rs. 2000

Total tax paid by all the persons of that city = 2000 × 35,000 = Rs. 70,000,000

Test Level 1: Line Graph - Question 5
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Directions: Study the following graph carefully and answer the question given below.

Q. What is the total amount of tax on an income of Rs. 9000 and an income of Rs. 2000?
Detailed Solution for Test Level 1: Line Graph - Question 5

Tax on income of Rs. 2000 = 1% of 2000 = Rs. 20
Tax on income of Rs. 9000 = 2% of 9000 = Rs. 180
Total tax on an income of Rs. 2000 and an income of Rs. 9000 = 20 + 180 = Rs. 200

Test Level 1: Line Graph - Question 6
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Directions: Study the following graph carefully and answer the question given below.

Q. What is the ratio of the tax on an income of Rs. 15,550 to that on an income of Rs. 16,550?
Detailed Solution for Test Level 1: Line Graph - Question 6

Tax on an income of Rs. 15,550 = 3% of 15,550 = 3/100 x 15,550 = 3/2 x 311 = Rs.933/2 

Tax on an income of Rs. 16,550 = 5% of 16,550 = 5/100 x 16.550 = 1655/2

Required ratio = 933/2 : 1655/2 = 933 : 1655

Test Level 1: Line Graph - Question 7
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Directions: Refer to the graph and answer the following question.

The line graph below gives information about the number of applications received by different colleges A, B and C for admission to their MBA programme from 2012 to 2016.

Q. What is the ratio of the number of applications received by colleges A, B and C in 2013 to that in 2016?
Detailed Solution for Test Level 1: Line Graph - Question 7

Number of applications received by colleges A, B and C in 2013 = 1200 + 1500 + 1850 = 4550
Number of applications received by colleges A, B and C in 2016 = 2000 + 1750 + 1500 = 5250
Ratio = 4550 : 5250 = 91 : 105 = 13 : 15

Test Level 1: Line Graph - Question 8
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Directions: Refer to the graph and answer the following question.

The line graph below gives information about the number of applications received by different colleges A, B and C for admission to their MBA programme from 2012 to 2016.

Q.  What is the difference between the number of applications received by college C during 2013-2016 and that received by college A during 2012-2015?
Detailed Solution for Test Level 1: Line Graph - Question 8

Number of applications received by college C during 2013-2016 = 1200 + 1650 + 2300 + 1750 = 6900
Number of applications received by college A during 2012-2015 = 1800 + 1500 + 1350 + 1100 = 5750
Difference = 6900 - 5750 = 1150

Test Level 1: Line Graph - Question 9
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Directions: Refer to the graph and answer the following question.

The line graph below gives information about the number of applications received by different colleges A, B and C for admission to their MBA programme from 2012 to 2016.

Q. Out of total applications received by colleges A, B and C in 2014, 40% were shortlisted by college A, 35% were shortlisted by college B and 60% were shortlisted by college C for further rounds. How many applicants were shortlisted by colleges A, B and C together in 2014?
Detailed Solution for Test Level 1: Line Graph - Question 9

Total number of applicants shortlisted from college A, B and C = 0.4 x 1350 + 0.35 x 2300 + 0.6 x 1650 = 540 + 805 + 990 = 2335

Test Level 1: Line Graph - Question 10
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Directions: Refer to the graph and answer the following question.

The line graph below gives information about the number of applications received by different colleges A, B and C for admission to their MBA programme from 2012 to 2016.

Q. Total applications received by college A in years 2012, 2013 and 2014 are what percent (approximately) of those received by college B in years 2014, 2015 and 2016?
Detailed Solution for Test Level 1: Line Graph - Question 10

Number of applications received by college A in years 2012, 2013 and 2014 = 1800 + 1500 + 1350 = 4650
Number of applications received by college B in years 2014, 2015 and 2016 = 2300 + 1600 + 2000 = 5900
Required percentage = (4650 x 100)/5900 = 78.81%

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