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Test Level 3: Table - CAT MCQ


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15 Questions MCQ Test Level-wise Tests for CAT - Test Level 3: Table

Test Level 3: Table for CAT 2024 is part of Level-wise Tests for CAT preparation. The Test Level 3: Table questions and answers have been prepared according to the CAT exam syllabus.The Test Level 3: Table MCQs are made for CAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test Level 3: Table below.
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Test Level 3: Table - Question 1
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Directions: Answer the question based on the data provided in the tables given below.
The following tables give the information about the number of persons who went to see the movie on two different days of the week in different multiplexes of a city:
DAY 1

DAY 2

(Assume that income earned by multiplexes is only in the form of tickets.)

Total income earned by multiplex G on day 1 and day 2 was what percent more than the income earned by multiplex H on day 1?

Detailed Solution for Test Level 3: Table - Question 1

Total income earned by multiplex G on day 1 and day 2 = {(156 - 41) + 45 + 41} x 125 + {(264 - 23) + 62 + 23} x 150
= 201 x 125 + 326 x 150 = 25,125 + 48,900 = Rs. 74,025
Income earned by multiplex H on day 1 = {(137 - 10) + 32 + 10} x 225 = 169 x 225 = Rs. 38,025
Required percent = ((74,025 - 38,025)/38,025) x 100 = 94.67%

Test Level 3: Table - Question 2
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Directions: Answer the question based on the data provided in the tables given below.
The following tables give the information about the number of persons who went to see the movie on two different days of the week in different multiplexes of a city:
DAY 1

DAY 2

(Assume that income earned by multiplexes is only in the form of tickets.)

If the persons aged 18 years and below were given a discount of 15% and the persons above 55 years of age were given a discount of 21% by all the multiplexes, then what was the total revenue earned by multiplex G on day 1 and day 2, and multiplex H on day 1?

Detailed Solution for Test Level 3: Table - Question 2

Income earned by multiplex G on day 1
= 45 x 0.85 x 125 + 115 x 125 + 41 x 0.79 x 125
= 4781.25 + 14,375 + 4048.75
= Rs. 23,205
Income earned by multiplex G on day 2
= 62 x 0.85 x 150 + 241 x 150 + 23 x 0.79 x 150
= 7905 + 36,150 + 2725.5
= Rs. 46,780.5
Income earned by multiplex H on day 1
= 32 x 0.85 x 225 + 127 x 225 + 10 x 0.79 x 225
= 6120 + 28,575 + 1777.5 = Rs. 36,472.5
Total = 23,205 + 46,780.5 + 36,472.5 = Rs. 1,06,458

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Test Level 3: Table - Question 3
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Directions: Answer the question based on the data provided in the tables given below.
The following tables give the information about the number of persons who went to see the movie on two different days of the week in different multiplexes of a city:
DAY 1

DAY 2

(Assume that income earned by multiplexes is only in the form of tickets.)

Out of the number of persons who went to all the multiplexes on day 1 and day 2, what percent were less than 55 years of age, if only 27 persons aged 55 years went to each of the five multiplexes on each day?

Detailed Solution for Test Level 3: Table - Question 3

Total number of persons who went to all the multiplexes on day 1 and day 2 = 156 + 45 + 234 + 68 + 168 + 35 + 421 + 41 + 137 + 32 + 264 + 62 + 420 + 75 + 368 + 89 + 159 + 31 + 196 + 22 = 3023
Total number of persons who went to all the multiplexes on day 1 and day 2 aged 0-55 years = 3023 - 41 - 36 - 55 - 32 - 10 - 23 - 23 - 56 - 36 - 10 = 2701
Total number of persons who went to all the multiplexes on day 1 and day 2 aged less than 55 years = 2701 - 27 x 5 - 27 x 5 = 2431 (Subtracting the 27 persons aged 55 years who visited each of the 5 multiplexes on day 1 and day 2)
Required percent = $\frac{2431}{3023}$ x 100 = 80.42%.

Test Level 3: Table - Question 4
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Directions: Answer the question based on the data provided in the tables given below.
The following tables give the information about the number of persons who went to see the movie on two different days of the week in different multiplexes of a city:
DAY 1

DAY 2

(Assume that income earned by multiplexes is only in the form of tickets.)

What was the total income earned by multiplexes G, H and W on day 2, if there was a discount of 12% to persons not above 18 years of age, and 24% to persons above 55 years of age?
Detailed Solution for Test Level 3: Table - Question 4

Total income earned by multiplex G on day 2 = 241 x 150 + 23 x 0.76 x 150 + 62 x 0.88 x 150 = 36,150 + 2622 + 8184 = Rs. 46,956
Total income earned by multiplex H on day 2 = 186 x 200 + 10 x 0.76 x 200 + 22 x 0.88 x 200 = 37,200 + 1520 + 3872 = Rs. 42,592
Total income earned by multiplex W on day 2 = 397 x 180 + 75 x 0.88 x 180 + 23 x 0.76 x 180 = 71,460 + 11,880 + 3146 = Rs. 86,486.4
Total = 46,956 + 42,592 + 86,486.4 = Rs. 1,76,034.4

Test Level 3: Table - Question 5
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Directions: Study the following information and answer the question.
A laptop manufacturing company manufactures laptops of six different brands- Lenovo, SAMSUNG, Acer, Apple, Sony and HCL. The company gives grades to each brand of laptop based on the number of units (N) of each laptop sold in a month. The following table provides information about the grades given in six different months of the year 2012.
Grade A: 125 > N > 99; Grade B: 85 < N < 100; Grade C: 70 < N < 86; Grade D: 50 < N < 71; Grade E: N < 51

If a total of 527 units of Apple were sold in these six months, then how many units of Apple were sold in March?
Detailed Solution for Test Level 3: Table - Question 5


Based on the information given in the table, in order to get the maximum output of 527 units for Apple, it can be concluded that 85 units of Apple were sold in March.

Test Level 3: Table - Question 6
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Directions: Study the following information and answer the question.
A laptop manufacturing company manufactures laptops of six different brands- Lenovo, SAMSUNG, Acer, Apple, Sony and HCL. The company gives grades to each brand of laptop based on the number of units (N) of each laptop sold in a month. The following table provides information about the grades given in six different months of the year 2012.
Grade A: 125 > N > 99; Grade B: 85 < N < 100; Grade C: 70 < N < 86; Grade D: 50 < N < 71; Grade E: N < 51

What could have been the maximum possible difference between the number of units of Lenovo and HCL sold in these six months?
Detailed Solution for Test Level 3: Table - Question 6


Required difference = 587 - 414 = 173

Test Level 3: Table - Question 7
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Directions: Study the following information and answer the question.
A laptop manufacturing company manufactures laptops of six different brands- Lenovo, SAMSUNG, Acer, Apple, Sony and HCL. The company gives grades to each brand of laptop based on the number of units (N) of each laptop sold in a month. The following table provides information about the grades given in six different months of the year 2012.
Grade A: 125 > N > 99; Grade B: 85 < N < 100; Grade C: 70 < N < 86; Grade D: 50 < N < 71; Grade E: N < 51

For which brand of laptop can the difference between the maximum possible total units sold (of all six months) and minimum possible total units sold (of all six months) be the greatest?
Detailed Solution for Test Level 3: Table - Question 7


The required difference is maximum for Sony and is equal to 181.

Test Level 3: Table - Question 8
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Directions: Read the following information and answer the question.
There are 9 districts, 6 factories and 7 depots. The factories are QQ, QR, QS, QT, QU and QV. The depots are PP, PQ, PR, PS, PT, PU and PV, and the districts are PPP, PPQ, PPR, PPS, PPT, PPU, PPV, PPW and PPX.
Table (i) shows the cost (in Rs.) of transporting one unit from factory to depot.
Table (ii) shows the cost (in Rs.) of transporting one unit from depot to districts. 


The minimum cost of transportation from any factory to district PPV is:
Detailed Solution for Test Level 3: Table - Question 8

The transportation cost from depot PS to district PPV = Rs. 0
The transportation cost from factory QR to depot PS = Rs. 50.10
∴ Minimum cost of transportation from any factory to district PPV = Rs. 50.10

Test Level 3: Table - Question 9
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Directions: Read the following information and answer the question.
There are 9 districts, 6 factories and 7 depots. The factories are QQ, QR, QS, QT, QU and QV. The depots are PP, PQ, PR, PS, PT, PU and PV, and the districts are PPP, PPQ, PPR, PPS, PPT, PPU, PPV, PPW and PPX.
Table (i) shows the cost (in Rs.) of transporting one unit from factory to depot.
Table (ii) shows the cost (in Rs.) of transporting one unit from depot to districts. 


The maximum cost of sending one unit from any factory to any district is:
Detailed Solution for Test Level 3: Table - Question 9

The highest cost of transportation from a factory to a depot = Rs. 1,157.70 (QT to PT)
Cost of transportation from PT to PPU takes up the highest charge of Rs. 1,035.30.
∴ Maximum cost = 1157.70 + 1035.30 = Rs. 2,193.00
Thus, option 2 is correct answer.

Test Level 3: Table - Question 10
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Directions: Read the following information and answer the question.
There are 9 districts, 6 factories and 7 depots. The factories are QQ, QR, QS, QT, QU and QV. The depots are PP, PQ, PR, PS, PT, PU and PV, and the districts are PPP, PPQ, PPR, PPS, PPT, PPU, PPV, PPW and PPX.
Table (i) shows the cost (in Rs.) of transporting one unit from factory to depot.
Table (ii) shows the cost (in Rs.) of transporting one unit from depot to districts. 


Find the total possible ways in which we can send one unit from any factory to any district.
Detailed Solution for Test Level 3: Table - Question 10

Number of ways = Six factory × Seven depots × Nine districts  
= 6 x 7 x 9 = 378 
Hence, option 2 is the correct answer.

Test Level 3: Table - Question 11
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Directions: Read the following information and answer the question.
There are 9 districts, 6 factories and 7 depots. The factories are QQ, QR, QS, QT, QU and QV. The depots are PP, PQ, PR, PS, PT, PU and PV, and the districts are PPP, PPQ, PPR, PPS, PPT, PPU, PPV, PPW and PPX.
Table (i) shows the cost (in Rs.) of transporting one unit from factory to depot.
Table (ii) shows the cost (in Rs.) of transporting one unit from depot to districts. 


If we send one unit from any factory to any district, then find the minimum cost (in Rs.) for it.
Detailed Solution for Test Level 3: Table - Question 11

The cost of transporting one unit from factory QS to depot PT is Rs. 0 and the cost of transporting one unit from depot PT to district PPQ is also Rs. 0.
∴ The minimum cost of transporting one unit from any factory to any district is Rs. 0.

Test Level 3: Table - Question 12
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Directions: Read the following to answer the question.
The number of trainees of DCBA Company from Phase 1 to Phase 7 in the years 2017 and 2018 are tabulated below. Trainees get into Phase 1 and get selected/passed only after Phase 7. No new trainees can enter or leave in any other phases.

The following facts are known.
1. Trainees get placed in the next phase in the next year only if he/she secures passing marks.
2. The trainees who fails in the examination stays in the same phase for next year.
3. The number of trainees failing in any phase is a distinct single digit natural number.

In the year 2017, how many phases had passing percentage more than overall passing percentage of the company?
Detailed Solution for Test Level 3: Table - Question 12

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Thus, when the number of trainees failing in Phase 1 is 3, then all conditions are satisfied.
For any other value, number of trainees failing in any phase will become 0 or more than two digit number, which is not possible.
Total number of trainees in 2017 is 359.
Total number of trainees who failed = 31
Thus, total pass percentage of the company in 2017 $%5C%20%3D%20%5Cfrac%7B359-31%7D%7B359%7D%5Ctimes%20100$ = 91.365%
Individual phase percentage.
Phase 1 = 92.5%
Phase 2 = 91.667%
Phase 3 = 96.226%
Phase 4 = 90%
Phase 5 = 96.875%
Phase 6 = 88.636%
Phase 7 = 87.5%
Thus, 4 phases had pass percentage greater than the overall pass percentage of company in 2017.

Test Level 3: Table - Question 13
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Directions: Read the following to answer the question.
The number of trainees of DCBA Company from Phase 1 to Phase 7 in the years 2017 and 2018 are tabulated below. Trainees get into Phase 1 and get selected/passed only after Phase 7. No new trainees can enter or leave in any other phases.

The following facts are known.
1. Trainees get placed in the next phase in the next year only if he/she secures passing marks.
2. The trainees who fails in the examination stays in the same phase for next year.
3. The number of trainees failing in any phase is a distinct single digit natural number.

The total number of trainees who failed in the year 2017 in all phases are
Detailed Solution for Test Level 3: Table - Question 13

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Thus, when the number of trainees failing in Phase 1 is 3, then all conditions are satisfied.
For any other value, number of trainees failing in any phase will become 0 or more than a two digit number, which is not possible.
Total number of trainees in 2017 = 359
Number of trainees who failed = 3 + 4 + 2 + 7 + 1 + 5 + 9 = 31

Test Level 3: Table - Question 14
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Directions: Read the following to answer the question.
The number of trainees of DCBA Company from Phase 1 to Phase 7 in the years 2017 and 2018 are tabulated below. Trainees get into Phase 1 and get selected/passed only after Phase 7. No new trainees can enter or leave in any other phases.

The following facts are known.
1. Trainees get placed in the next phase in the next year only if he/she secures passing marks.
2. The trainees who fails in the examination stays in the same phase for next year.
3. The number of trainees failing in any phase is a distinct single digit natural number.

What is the number of new trainees who joined DCBA Company in the year 2018?
Detailed Solution for Test Level 3: Table - Question 14

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Total number of trainees in 2017 = 359
Total number of new trainees from previous phase in 2018 = 47 + 37 + 44 + 51 + 63 + 31 + 39 = 312
Number of trainees who failed = 3 + 4 + 2 + 7 + 1 + 5 + 9 = 31
The number of new trainees who joined DCBA Company in the year 2018 = 359 - 312 = 47
Thus, we can see that 47 new trainees joined DCBA Company in the year 2018.

Test Level 3: Table - Question 15
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Directions: Read the following to answer the question.
The number of trainees of DCBA Company from Phase 1 to Phase 7 in the years 2017 and 2018 are tabulated below. Trainees get into Phase 1 and get selected/passed only after Phase 7. No new trainees can enter or leave in any other phases.

The following facts are known.
1. Trainees get placed in the next phase in the next year only if he/she secures passing marks.
2. The trainees who fails in the examination stays in the same phase for next year.
3. The number of trainees failing in any phase is a distinct single digit natural number.

Find the total number of trainees who passed from DCBA Company in the year 2017.
Detailed Solution for Test Level 3: Table - Question 15

The number of trainees failing in any phase will be a single digit natural number i.e. the number of trainees failing in Phase 1 can be 1 to 9.
If we consider 1 trainee fails in 2017, then following table can be inferred.

While calculating, we found that trainees failing from Phase 3 is 0, which is not possible as it should be a single digit natural number, so this case is not possible.
If we consider 2 trainees are failing in Phase 1 of 2017, we get the following table.

After calculations, we find that trainees failing from Phase 5 in 2017 is 0, which is not possible.
If we consider that 3 trainees fail in Phase 1 in 2017, the following can be tabulated.

Total number of trainees who passed from DCBA Company in the year 2017 = The number of trainees who passed from Phase 7 in 2017.
Number of trainees who failed in Phase 7 = 9
Thus, 72 - 9 = 63 trainees passed in Phase 7 of the year 2017.

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