Test : Perimeter And Area - 1
10 Questions MCQ Test Mathematics for Class 5: NCERT | Test : Perimeter And Area - 1
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A carpet is laid on the floor of a room 8 m by 5 m, leaving a border 0.5 m wide all round it. What is the perimeter of the carpet?
Number of unit squares = 23
Now, 1 = 1 sq. unit
Area of figure = 23 square units
The figure is made up of 8 identical rectangles, Find the total area of the shaded figure.
After rearranging the given figure, we get the new figure.
Area of 1 small rectangle = 10x5 = 50
sq. cm Number of shaded rectangles ^ 4
Total shaded area = 4x50 = 200 sq. cm
In the given figure, DE = HI = AL = 2 cm and LK = IJ = HG = EF = 5 cm. Find the perimeter of the given figure (in cm).
We have,
BC = AL + KJ + IH + GF + ED
= (2 + 2 + 2 + 2 + 2)cm = 10 cm
Perimeter of the given figure
= (7 +10+7 + 2 +5+ 2 +5+ 2 +5+ 2 +5+ 2)cm 54cm
ACEG is a square. AB is 1/2 of AC. What is the perimeter of the square?
We have, AB = 1/2 x AC
6cm = 1 x AC = > AC = 6 x 2 = 12 cm
Side of square -= 12 cm
So, perimeter of square 12 x 4= 48 cm
Area of 1 small square = (2x2)cm2
= 4 cm2
Number of shaded square ^ 14
Shaded area = 14 x 4 = 56 cm2
The perimeter of a rectangular picture is 160 cm. It is 30 cm wide. How long is it?
Perimeter = 160 cm
Breadth = 30 cm
2(Length + Breadth) = 160 cm
2(Length + 30 cm) = 160 cm
=> Length +30 cm= 80 cm
=> Length = (80 - 30) cm = 50 cm
Find the total shaded area of the figure made up of identical squares.
Area of 1 small square = (3x3)cm2
= 9cm2
Number of shaded squares =19
Shaded area = 19 x 9 = 171cm2
Perimeter of the given figure
=(2+ 3+1+10+5+ 4 +17+ 4 +5+6+ 4 +7)
cm
= 68cm
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