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IPMAT Mock Test - 4 (New Pattern) - Commerce MCQ


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30 Questions MCQ Test IPMAT Mock Test Series - IPMAT Mock Test - 4 (New Pattern)

IPMAT Mock Test - 4 (New Pattern) for Commerce 2024 is part of IPMAT Mock Test Series preparation. The IPMAT Mock Test - 4 (New Pattern) questions and answers have been prepared according to the Commerce exam syllabus.The IPMAT Mock Test - 4 (New Pattern) MCQs are made for Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for IPMAT Mock Test - 4 (New Pattern) below.
Solutions of IPMAT Mock Test - 4 (New Pattern) questions in English are available as part of our IPMAT Mock Test Series for Commerce & IPMAT Mock Test - 4 (New Pattern) solutions in Hindi for IPMAT Mock Test Series course. Download more important topics, notes, lectures and mock test series for Commerce Exam by signing up for free. Attempt IPMAT Mock Test - 4 (New Pattern) | 100 questions in 90 minutes | Mock test for Commerce preparation | Free important questions MCQ to study IPMAT Mock Test Series for Commerce Exam | Download free PDF with solutions
IPMAT Mock Test - 4 (New Pattern) - Question 1
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The present age of Reva is 75% more than the present age of Vijay. Ajay is 12 years younger than Reva. The present age of Vijay is 20% less than the present age of Ajay. Find the average age of Reva, Ajay and Vijay after seven years.

Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 1
Let the present age of Ajay = x years

Present age of Vijay = = 0.8x years

Present age of Reva = 1.75 x

According to the question,

1.4x – x = 12

So, x = 30

So, the present age of Ajay, Vijay and Reva are 30 years, 24 years and 42 years respectively.

Average age of Ajay, Vijay and Reva after 7 years

Hence, the correct option is (A).

IPMAT Mock Test - 4 (New Pattern) - Question 2
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In a zoo, there are rabbits and pigeons. If their heads are counted, these are 90 while their legs are 224. Find the number of pigeons in the zoo.

Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 2
Let no. of Pigeons = P

no. of Rabbits = R

Then, according to question

P + R = 90 ...(i)

2P + 4R = 224 ...(ii)

Solving these two equation

we get. R = 22, P = 68

Hence the correct option is B.

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IPMAT Mock Test - 4 (New Pattern) - Question 3
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A container contains 40 litres of milk. From this container, 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 3
Amount of milk left after 3 operations

= 29.16 litres.

Hence the correct option is D.

IPMAT Mock Test - 4 (New Pattern) - Question 4
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The average (arithmetic mean) of x and y is 40. If z = 10, then what is the average of x, y and z?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 4

x + y = 980

Average of x, y and z

= 30.

Hence the correct option is B.

IPMAT Mock Test - 4 (New Pattern) - Question 5
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In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 5
Sum of total runs in the first 10 overs

= 10 x 3.2 = 32

Run rate in the remaining 40 overs

282 - 32/40 = 250/40 = 6.25

Hence the correct option is A.

IPMAT Mock Test - 4 (New Pattern) - Question 6
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What is the correct time of a watch between 2 and 6 a.m. when the angle between the minute hand and the hour hand is 1/3 of a right angle?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 6
Solving

IPMAT Mock Test - 4 (New Pattern) - Question 7
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A 25 m long ladder is placed against a vertical wall inside a room such that the foot of the ladder is 7 m from the foot of the wall. If the top of the ladder slides 4 m downwards, then the foot of the ladder will slide by
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 7

AB = 25

⇒ BC = 24

⇒ B′C = 20

AB′ = 25

⇒ A′C = 15

⇒ A′A = 8m

IPMAT Mock Test - 4 (New Pattern) - Question 8
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Suppose it is 3 o’clock. After 20 minutes the angle between the smaller and bigger hands will be
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 8
Degrees at 3 : 20

= 5 min distance distance.

= 30 - 10 = 20 degrees.

Hence the correct option is B.

IPMAT Mock Test - 4 (New Pattern) - Question 9
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The perimeter of a rectangular field is 52 m. If the length of the field is 2m more than thrice the breadth, then what is the breadth of the field?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 9
Given 2x + 2y = 52

and x = 3y + 2

Solving (i) and (ii) we get.

x = 20, y = 6

Hence the correct option is D.

IPMAT Mock Test - 4 (New Pattern) - Question 10
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The area of four walls of a room is 120 m2. The length is twice the breadth: If the height of the room is 4 m, find area of the floor.
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 10
Let breadth of the room = b m

Length = 2b m

Height = h = 4m

  1. Area of the four walls of the room = 2 (length+breadth) × h 2(2b + b) × 4 = 120m2

    8 × 3b = 120

    b = 120/(8 × 3)

    b = 5m

    Therefore

    Breadth = b = 5m

    Length = 2b = 2 × 5 = 10m

  2. Area of the floor=length×breadth = 10m × 5m

    = 50m2

IPMAT Mock Test - 4 (New Pattern) - Question 11
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A circular grassy plot of land, 42 m in diameter, has a path 3.5 m wide running around it on the outside. Find the cost gravelling the path at Rs. 4 per square metre.
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 11
Radius = 21

Required area = π(24.52 − 212) = 500.5 cost = 500.5 × 4 = 2002

Hence the correct option is A.

IPMAT Mock Test - 4 (New Pattern) - Question 12
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How many metres of cloth 5 m wide will be required to make a conical tent, the radius of whose base is 7 m and whose height is 24 m? (Take n = 22/7)
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 12

IPMAT Mock Test - 4 (New Pattern) - Question 13
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If x + y > 5 and x - y > 3, then which of the following gives all possible values of x?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 13
x + y > 5

putting x = 0 and y = 6

x + y = 0 + 6 = 6 > 5

therefore putting any value of x,

x + y > 5

x − y > 3

let, x = 0 then y = −3 but, −3 < 3

therefore value of x should be greater than 3 i.e., 4, 5, 6, 7,……

Hence the correct option is B.

IPMAT Mock Test - 4 (New Pattern) - Question 14
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The price for a pair of cufflinks is Re. 1.00. The price for a 5-pair package of cufflinks is 3.40. The 5-pair package is what percent cheaper per pair than 5 pairs purchased separately?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 14
Price of 5 pairs when purchased separatey = 5 Rs.

Price of 5 pair package = 3.40 Rs.

IPMAT Mock Test - 4 (New Pattern) - Question 15
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In an election A got 39% of the total votes and B got 15% of the total votes and C got the remaining votes. If the difference between the votes received by A and C was 56000. Find the total number of votes A received?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 15
Given: In an election A got 39% of the total votes and B got 15% of the total votes and C got the remaining votes. If the difference between the votes received by A and C was 56000.

Let total votes be 100x.

A get = 39x

B = 15x

So, C gets 46x

If A got a% votes and B got b% votes, difference in the votes = (a - b) % of Total votes

As per question,

46x – 39x = 56000

⇒ 7x = 56000

⇒ X = 8000

So, A gets = 39x = 39 × 8000 = 312000

Hence, the correct option is (D)

IPMAT Mock Test - 4 (New Pattern) - Question 16
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If tan2A cosec2B - 1 = tan2A then which one is true:
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 16

IPMAT Mock Test - 4 (New Pattern) - Question 17
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If cot⁡θ = b/a then cos⁡θ − sin⁡θ =?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 17

hypotenuse2 = base2 + perpendicular2

IPMAT Mock Test - 4 (New Pattern) - Question 18
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Direction: Read the following table carefully and Answer the Questions given below:

The number of 5 different players from India and Australia

The Volleyball players from India is how many percent more than the Chess players from Australia.
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 18
Solving

IPMAT Mock Test - 4 (New Pattern) - Question 19
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Direction: Read the following table carefully and Answer the Questions given below:

The number of 5 different players from India and Australia

If the number of Cricket players from India is decreased by 20% then the difference of Cricket players from India to Tennis players from Australia is:
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 19
Cricket players from India after decrement

= 50 x 80/100 = 40

Difference = 40 - 30 = 10

Hence the correct option is C.

IPMAT Mock Test - 4 (New Pattern) - Question 20
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I forgot the last 3 digits of a 7-digit telephone number. If I randomly dial the final 3 digits after correctly dialling the first four, then what is the chance of dialling the correct number?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 20
It is given that the last three digits are randomly dialled.

Then each of the digits can be selected out of 10 digits in 10 ways.

Hence required probability = (1/10)3 = 1/1000

IPMAT Mock Test - 4 (New Pattern) - Question 21
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Monthly incomes of two persons are in the ratio 5 : 4 and their monthly expenditures are in the ratio of 9:7. If each person saves Rs.500 per month, then what are their monthly incomes.
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 21
Let their monthly income be 5x, 4x respectively.

Let their monthly expenditure be 9y,7y respectively.

5x − 9y = 500 ………(1)

4x − 7y = 500 ………(2)

From (1) and ( 2)

5x − 9y = 4x − 7y

y = x/2

From (1),

Or, x = 1000

Their monthly income is 5000 and 4000 respectively.

IPMAT Mock Test - 4 (New Pattern) - Question 22
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Several litres of acid was drawn off a 54-litre vessel full of acid and an equal amount of water added. Again the same volume of the mixture was drawn off and replaced by water. As a result, the vessel contained 24 litres of pure acid. How much of the acid was drawn off initially?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 22
Let x litres of acid was drawn off initially.

Hence remaining acid in 54 -litre vessel full of acid = (54 − x) litres and water added = x litres.

Now out of 54 litres of mixture of acid and water, x litres of mixture is drawn off.

∴ Quantity of acid drawn off vessel

and, buantity of water drawn off

= x2/54, bitres

Vessel contains litres of acid.

⇒ x2 − 108x + 1620 = 0

⇒ x = 90,18

since 90 > 54

x = 90 is ruled out 8x

Hence,x = 18 litres.

IPMAT Mock Test - 4 (New Pattern) - Question 23
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Suppose that a maximum of 25 gm of salt dissolves in 100 gm of water. Any more salt, if added, remains undissolved and sediment falls at the bottom. Now, water is evaporated from 1 kg of a 4% solution at the rate of 28 gm per hour. After how long will it start sedimenting?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 23
4% solution means it has 40 gm of salt and 960gm of water.

40 gm salt needs a minimum of 160gm of water.

It means 800 gm of water is extra which needs approximately 29 hours for evaporating at the rate of 28 gm per hour.

Hence the correct option is B.

IPMAT Mock Test - 4 (New Pattern) - Question 24
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The number of observations in a group is 40. If average of the first 10 is 4.5 and that of the remaining 30 is 3.5 then average of the whole group is
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 24
Total observations = 40

Average of First 10 observations = 4.5 Average of Remaining 30 observations = 3.5

Average of Total observations = (Sum of 10 members + Sum of Remaining 30 members ) / Total observations

Sum of First 10 members = 4.5 × 10 = 45

Sum of Remaining 30 members = 3.5 × 30 = 105

Hence, Average of Total observations = (45 + 105)/40 = 150/40

Average of Total observations =15/4

IPMAT Mock Test - 4 (New Pattern) - Question 25
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Angad was conducting an experiment in which the average of 11 observation came to be 90, while the average of the first five observations was 87, and that of the last five was 84. What is the measure of the 6th observation?
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 25
Sum of 11 observations = 11 × 90 = 990

Sum of 1 st 5 observation = 5 × 87 = 435

Sum of Last 5 observation = 5 × 84 = 420

6th observation = 990 − 435 − 420 = 135

Hence the correct option is D.

IPMAT Mock Test - 4 (New Pattern) - Question 26
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Two isosceles triangles have equal vertical angles and their areas are in the ratio 9 : 16. The ratio of their corresponding heights is
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 26
Given triangles are congruent.

IPMAT Mock Test - 4 (New Pattern) - Question 27
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The area of a field in the shape of a trapezium measures 1440 m. The perpendicular distance between its parallel sides is 24 m. If the ratio of the parallel sides is 5 : 3, the length of the longer parallel side is
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 27

Solving, we get x = 15

and length of longer side = 5 × 15 = 75

Hence the correct option is C.

IPMAT Mock Test - 4 (New Pattern) - Question 28
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The radius of the circumcircle of an equilateral triangle of side 12 cm is
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 28
Circumcentre of a triangle is the point of intersection of the right bisectors of its aides.

IPMAT Mock Test - 4 (New Pattern) - Question 29
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The sides of a triangle are in the ratio of 1/2 : 1/3 : 1/4. If the perimeter is 52 cm then the length of the smallest side is
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 29

∴ 13a = 52

a = 4

smallest side = 3a = 12

Hence the correct option is D.

IPMAT Mock Test - 4 (New Pattern) - Question 30
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A wire is looped in the form of a circle of radius 28cm. It is re-bent into a square form. Determine length of the side of the square
Detailed Solution for IPMAT Mock Test - 4 (New Pattern) - Question 30
Given : R = 28

Circumference = 2π(28) = 176

Side of the square = 176/4 = 44

Hence the correct option is A.

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