Test: Problems on Ages - 4 - CUET Commerce MCQ

Let the son's present age be x years. Then, man's present age = (x + 24) years.

 (x + 24) + 2 = 2(x + 2)

 x + 26 = 2x + 4

 x = 22.

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

 54 - x = 5x - 30

 6x = 84

 x = 14.

 Son's age after 6 years = (x+ 6) = 20 years..

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,

4x + 6 = 26        4x = 20

x = 5.

 Deepak's age = 3x = 15 years.

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

 20x = 80

 x = 4.

 Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.

Mother's age when Ayesha's brother was born = 36 years.

Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.

 Required difference = (42 - 36) years = 6 years.

Given that:

1. The difference of age b/w R and Q = The difference of age b/w Q and T.

2. Sum of age of R and T is 50 i.e. (R + T) = 50.

Question: R - Q = ?.

Explanation:

R - Q = Q - T

(R + T) = 2Q

Now given that, (R + T) = 50

So, 50 = 2Q and therefore Q = 25.

Question is (R - Q) = ?

Here we know the value(age) of Q (25), but we don't know the age of R.

Therefore, (R-Q) cannot be determined.

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10]

 3x + 20 = 2x + 40

 x = 20.

 Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.