Test: Conic Sections - 2 - JEE MCQ

# Test: Conic Sections - 2 - JEE MCQ

Test Description

## 25 Questions MCQ Test Mathematics (Maths) for JEE Main & Advanced - Test: Conic Sections - 2

Test: Conic Sections - 2 for JEE 2024 is part of Mathematics (Maths) for JEE Main & Advanced preparation. The Test: Conic Sections - 2 questions and answers have been prepared according to the JEE exam syllabus.The Test: Conic Sections - 2 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Conic Sections - 2 below.
Solutions of Test: Conic Sections - 2 questions in English are available as part of our Mathematics (Maths) for JEE Main & Advanced for JEE & Test: Conic Sections - 2 solutions in Hindi for Mathematics (Maths) for JEE Main & Advanced course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Test: Conic Sections - 2 | 25 questions in 25 minutes | Mock test for JEE preparation | Free important questions MCQ to study Mathematics (Maths) for JEE Main & Advanced for JEE Exam | Download free PDF with solutions
Test: Conic Sections - 2 - Question 1

### The radius of the circle passing through the foci of the ellipse   and having its centre at (0, 3) is

Detailed Solution for Test: Conic Sections - 2 - Question 1

Test: Conic Sections - 2 - Question 2

### The line y = c is a tangent to the parabola 7/2 if c is equal to

Detailed Solution for Test: Conic Sections - 2 - Question 2

y = x is tangent to the parabola
y=ax2+c
if a= then c=?
y′ =2ax
y’ = 2(7/2)x  =1
x = 1/7
1/7 = 2(1/7)2 + c
c = 1/7 * 2/49
c = 7/2

 1 Crore+ students have signed up on EduRev. Have you?
Test: Conic Sections - 2 - Question 3

### The equation 2x2+3y2−8x−18y+35 = λ Represents

Detailed Solution for Test: Conic Sections - 2 - Question 3

Given the equation is,
2x2+3y2−8x−18y+35=K
Or, 2{x2−4x+4} + 3{y2−6y+9}=K
Or, 2(x−2)2 + 3(y−3)2 =K.
From the above equation it is clear that if K>0 then the given equation will represent an ellipse and for K<0, no geometrical interpretation.
Also if K=0 then the given equation will be reduced to a point and the point will be (2,3).

Test: Conic Sections - 2 - Question 4

The locus of a variable point whose distance from the point (2, 0) is 2/3 times its distance from the line x = 9/2 is

Detailed Solution for Test: Conic Sections - 2 - Question 4

Test: Conic Sections - 2 - Question 5

The axis of the parabola 9y2−16x−12y−57 = 0 is

Test: Conic Sections - 2 - Question 6

A and B are two distinct points, Locus of a point P satisfying |PA| + |PB| = 2k, a constant is

Test: Conic Sections - 2 - Question 7

The eccentricity of the hyperbola x2−y2 = 9 is

Test: Conic Sections - 2 - Question 8

Locus of the point of intersection of the lines x = sec θ + tan θ and y = sec θ – tan θ is

Test: Conic Sections - 2 - Question 9

The line y = m x + c, touches the parabola y2 = 4ax if

Test: Conic Sections - 2 - Question 10

The equations x = at2, y = 4at ; t ∈ R represent

Test: Conic Sections - 2 - Question 11

t ∈ R represents

Detailed Solution for Test: Conic Sections - 2 - Question 11

P(x,y) = [(et + e-t)/2 , (et - e-t)/2]
(et + e-t)/2 = x --------------------------(1)
(e- e-t)/2 = y --------------------------(2)
2e= 2x + 2y
et = x + y
Eq (1) et + e-t = 2x
et + 1/et = 2x
(et)2 + 1 = 2x*et
(x+y)2 + 1 = 2x(x+y)
x2 + y2 + 2xy + 1 = 2x2 + 2xy
x2 + y2 + 1 = 2x2
(x2)/(1)2 - (y2)/(1)2 = 1  {which represents hyperbola equation}

Test: Conic Sections - 2 - Question 12

The vertex of the parabola y2 = 4a(x−a) is

Test: Conic Sections - 2 - Question 13

The two parabolas x2 = 4y and y2 = 4x meet in two distinct points. One of these is the origin and the other is

Test: Conic Sections - 2 - Question 14

The equation of the directrix of the parabola x2 = −4ay is

Test: Conic Sections - 2 - Question 15

The eccentricity ‘e’ of a parabola is

Test: Conic Sections - 2 - Question 16

The ellipse

Test: Conic Sections - 2 - Question 17

The equations x = a cos θ , y = b sin θ, 0 ≤ θ < 2π , a ≠ b, represent

Test: Conic Sections - 2 - Question 18

The graph of the function f(x) i/x i.e. the curve y = 1/x is

Test: Conic Sections - 2 - Question 19

The line y = c touches the parabola y2 = 4ax when

Test: Conic Sections - 2 - Question 20

The parabolas x2 = 4y and y2 = 4x intersect

Test: Conic Sections - 2 - Question 21

The lngth of the common chord of the parabolas y2 = x and x2 = y is

Detailed Solution for Test: Conic Sections - 2 - Question 21

Test: Conic Sections - 2 - Question 22

The number of points on X-axis which are at a distance c units (c < 3) from (2, 3) is

Detailed Solution for Test: Conic Sections - 2 - Question 22

Distance of 'c' units from (2,3)
Let the no: of points be (x,0)
By distance formula
{(2−x)2+(3−0)2}=c
4−4x+x2+9=c
⇒x2−4x+13 = c:c=2,2
There are the points of c,such that when they are applied back to the equations,the number of points will become zero.

Test: Conic Sections - 2 - Question 23

The eccentricity of the conic 9x2 − 16y2 = 144 is

Test: Conic Sections - 2 - Question 24

The eccentricity of 3x2+4y2 = 24 is

Test: Conic Sections - 2 - Question 25

The angle between the tangents drawn from the origin to the circle = (x−7)2+(y+1)2 = 25 is

Detailed Solution for Test: Conic Sections - 2 - Question 25

Let the equation of tangent drawn from (0,0) to the circle be y=mx. Then, p = a ⇒ 7m+1/(m2+1)1/2= 5
⇒24m2 + 14m−24=0
⇒12m2 + 7m−12=0
⇒m1m2 = −12/12 =−1
∴ Required angle = π/2

## Mathematics (Maths) for JEE Main & Advanced

209 videos|443 docs|143 tests
Information about Test: Conic Sections - 2 Page
In this test you can find the Exam questions for Test: Conic Sections - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Conic Sections - 2, EduRev gives you an ample number of Online tests for practice

## Mathematics (Maths) for JEE Main & Advanced

209 videos|443 docs|143 tests