31 Year NEET Previous Year Questions: Thermal Properties of Matter - NEET MCQ

# 31 Year NEET Previous Year Questions: Thermal Properties of Matter - NEET MCQ

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## 30 Questions MCQ Test Physics Class 11 - 31 Year NEET Previous Year Questions: Thermal Properties of Matter

31 Year NEET Previous Year Questions: Thermal Properties of Matter for NEET 2024 is part of Physics Class 11 preparation. The 31 Year NEET Previous Year Questions: Thermal Properties of Matter questions and answers have been prepared according to the NEET exam syllabus.The 31 Year NEET Previous Year Questions: Thermal Properties of Matter MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for 31 Year NEET Previous Year Questions: Thermal Properties of Matter below.
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31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 1

### N molecules each of mass m of a gas  A and 2N molecules each of mass 2m of gas B are contained in the same vessel which is maintained at temperature T. The mean square velocity of molecules of B type is v2 and the mean square rectangular component of the velocity of A type is denoted by ω2. Then ω2/v2 [1991]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 1

Mean kinetic energy of the two types of molecules should be equal. The mean square velocity of A type molecules = ω2 + ω2 + ω2 = 3ω2

Therefore,

This gives ω2 / v2 = 2/3

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 2

### 10 gm of  ice  cubes at 0°C are released in a tumbler (water equivalent 55 g) at 40°C.Assuming that negligible heat is taken from the surroundings, the temperature of water in the tumbler becomes nearly (L = 80 cal/g) [1988]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 2

Let the final temperature  be T Heat gained by ice  = mL + m × s × (T – 0) = 10 × 80 + 10 × 1 × T
Heat lost by water = 55 × 1× (40 – T)
By using law of calorimetery, 800 + 10 T = 55 × (40 – T)
⇒ T = 21.54°C = 22°C

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31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 3

### A centigrade and a Fahrenheit thermometer are dipped in boiling water. The water temperature is lowered until the Fahrenheit thermometer registers 140°. What is the fall in temperature as registered by the Centigrade thermometer ?

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 3

Using

Temperature of boiling water = 100°C
We get, fall in temperature = 100 – 60 = 40°C

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 4

Thermal capacity of 40 g of aluminium (s = 0.2 cal /g K) is [1990]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 4

Thermal capacity = ms = 40 × 0.2 = 8 cal/°C = 4.2 × 8 J = 33.6 joules/°C

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 5

Mercury thermometer can be used to measure temperature upto [1992]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 5

Mercury thermometer is based on the principle of change of volume with rise of temperature and can measure temperatures ranging from –30°C to 357°C.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 6

If the temperature of the sun is doubled, the rate of energy  received on earth will be increased by a factor of [1993]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 6

Amount of energy radiated ∝ T4

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 7

A body cools from 50.0°C to 48°C in 5s. How long will it take to cool from 40.0°C to 39°C?Assume the temperature of surroundings to be 30.0°C and Newton's law of cooling to be valid.

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 7

Rate of cooling ∝ temperature difference
between system and surrounding.
As the temperature difference is halved, so the rate of cooling will also be halved.
So time taken will be doubled
t = 2 × 5 sec. = 10 sec.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 8

A beaker full of hot water is kept in a room. If it cools from 80°C to 75°C in t1 minutes, from 75° C to 70°C in t2 minutes and from 70°C to 65°C in t3 minutes, then [1995]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 8

Let θ0 be the temperature of the surrounding.
Then

… (1)

Similarly,  …(2)

and   … (3)
From (1), (2) & (3), it is obvious that

t1 < t2 < t3

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 9

A black body is at temperature of 500 K. It emits energy at rate which is proportional to [1997]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 9

According to Stefan's Law

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 10

The radiant energy from the sun, incident normally at the surface of earth is 20 k cal/m2 min. What would have been the radiant energy, incident normally on the earth, if the sun had a temperature, twice of the present one? [1998]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 10

According to Stefan’s law

E ∝ T4

⇒ E2 = 320 kcal/m2. min.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 11

If 1 g of steam is mixed with 1 g of ice, then the resultant temperature of the mixture is [1999]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 11

Heat required by ice a t 0° C to reach a temperature of 100°C = mL + mcΔθ = 1 × 80 + 1 × 1 × (100 – 0) = 180 cal
Heat available with 1 g steam to condense into 1 g of water at 100°C = 536 cal.
Obviously the whole steam will not be condensed and ice will attain a temperature of 100°C; so the temperature of mixture = 100°C.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 12

The coefficient of linear expansions of brass and steel are α1 and α2 respectively. When we take a brass rod of length ℓ1 and a steel rod of length ℓ2 at 0ºC, then the difference in their lengths (ℓ2 – ℓ1) will remain the same at all temperatures if [1995, 1999]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 12

Let ΔT be increase in the temperature of brass wire.Then length of brass wire,
Similarly, length of steel wire when temperature is increased by According to question , l' – l'' = l1 – l2

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 13

The presence of gravitational field is required for the heat transfer by [2000]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 13

In convection, the temperature gradient exists in the vertical direction and not in the horizontal direction. So, up and down movement of particles takes place which depends on the weight and gravity.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 14

A black body has maximum wavelength λm at temperature 2000 K. Its corresponding wavelength at temperature 3000 K will be

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 14

According to Wein's displacement law,

λmT = 2.88 × 10–3 When T = 2000 K,
λm (2000) = 2.88 × 10–3 ....(1)
When T = 3000 K, λ'm (3000) = 2.88 × 10–3 ....(2)
Dividing (1) by (2),

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 15

A cylindrical rod having temperature T1 and T2 at its end. The rate of flow of heat is Q1 cal/sec.If all the linear dimensions are doubled keeping temperature constant, then the rate of flow of heat Q2 will be [2001]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 15

Rate of heat flow

Dimensions of area A = [L2], dimensions of distance l = [L]

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 16

Wien's law is concerned with [2002]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 16

According to Wein's displacement law, product of wavelength belonging to maximum intensity and temperature is constant i.e.,  λmT = constant.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 17

Radiation from which of the following sources, approximates black body radiation best? [2002]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 17

This hole in the cavity is also called Fery's black body, it is made such that when light enters the cavity it suffers multiple reflection inside it and since with every reflection some part is absorbed so almost all the radiant light get absorbed.

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 18

Two rods of thermal conductivities K1 and K2, cross-sections A1 and A2 and specific heats S1 and S2 are of equal lengths. The temperatures of two ends of each rod are T1 and T2. The rate of flow of heat at the steady state will be equal if [2002]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 18

Rate of heat flow for one rod

.Rate of heat flow for other rod

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 19

Consider a compound slab consisting of two different materials having equal thicknesses and thermal conductivities K and 2K, respectively.
The equivalent thermal conductivity of the slab is                  [2003]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 19

In series, equivalent thermal conductivity

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 20

If λm denotes the wavelength at which the radiative emission from a black body at a temperature T K is maximum, then [2004]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 20

From Wein’s displacement law

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 21

Which of the following circular rods (given radius r and length l), each made of the same material and whose ends are maintained at the same temperature will conduct most heat? [2005]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 21

We know that

Also, Thermal resistance

Heat flow will be maximum when thermal resistance is minimum.
From given option

It is clear that for option (2) resistance is minimum, hence, heat flow will be maximum. [Alt : (i) Rate of heat flow is directly proportional to area
(ii) inversely proportional to length.

∴ Heat flow will be maximum when r is maximum and ℓ is minimum. ]

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 22

The temperature of in version of a thermocouple is 6200C and the neutral temperature is 3000C. What is the temperature of cold junction ? [2005]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 22

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 23

A black body at 1227°C emits radiations with maximum intensity at a wavelength of 5000Å. If the temperature of the body is increased by 1000°C, the maximum intensity will be observed at

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 23

Applying Wein's displacement law, λmT = constant

= ( 5000 * 1500 ) / 2500 = 3000 Å

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 24

A black body is at 727° C. It emits energy at a rate which is proportional to [2007]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 24

According to Stefan's law, E ∝ T4

∝ (t + 273)4 K              [727°C = (727 + 273)K]
∝ (727 + 273)4 K
∝ (1000)4 K

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 25

If the cold junction of a thermo-couple is kept at 0°C and the hot junction is kept at T°C then the relation between neutral temperature (Tn) and temperature of inversion (Ti) is [2007]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 25

Since  = Neutral temperature

[Tc = 0°C = temperature of cold junction]

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 26

Assuming the sun to have a sph erical outer surface of radius r, radiating like a black body at temperature t°C, the power received by a unit surface, (normal to the incident rays) at a distance R from the centre of the sun is [2007]       where σ is the Stefan’s constant.

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 26

Power radiated by the sun at t°C

= σ(t + 273)44πr2

Power received by a unit surface

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 27

On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39° W and 239° W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39° C on the Celsius scale? [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 27

For different temperature scales, we have

= constant

Where L.F.P ⇒  Lower Fixed point
U.H.F. ⇒  Upper fixed point
where x is the measurement at that scale.
Here, if C and W be the measurements on Celsius and W scale then,

= 117° W

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 28

An electric kettle takes 4A current at 220 V. How much time will it take to boil 1 kg of water from temperature 20° C? The temperature of boiling water is 100° C. [2008]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 28

Heat required to raise the temperature of 1kg water from 20°C to 100°C is given by Q = msΔθ = (1× 4200 × 80) J
Power of kettle (P) = VI = (220 × 4)W

∴ Time taken =

= 381.81 sec = 6.36 min

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 29

The two ends of a rod of  length L and a uniform cross-sectional area A are kept at two temperatures T1 and T2 (T1 > T2). The rate of heat transfer, through the rod in a steady state is given by: [2009]

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 29

[(T1–T2) is the temperature difference]

31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 30

A black body at 227°C radiates heat at the r ate of 7 cals/cm2s. At a temperature  of 727°C, the rate of heat radiated in the same units will be:

Detailed Solution for 31 Year NEET Previous Year Questions: Thermal Properties of Matter - Question 30

Accordin g to Stefan’s law E = σT4,
T1 = 500 K
T2 = 1000 K

∴     E2 = 16 × 7 = 112 cal / cm2s

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