Test: Refraction & Dispersion By Prism - NEET MCQ

# Test: Refraction & Dispersion By Prism - NEET MCQ

Test Description

## 10 Questions MCQ Test Physics Class 12 - Test: Refraction & Dispersion By Prism

Test: Refraction & Dispersion By Prism for NEET 2024 is part of Physics Class 12 preparation. The Test: Refraction & Dispersion By Prism questions and answers have been prepared according to the NEET exam syllabus.The Test: Refraction & Dispersion By Prism MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Refraction & Dispersion By Prism below.
Solutions of Test: Refraction & Dispersion By Prism questions in English are available as part of our Physics Class 12 for NEET & Test: Refraction & Dispersion By Prism solutions in Hindi for Physics Class 12 course. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free. Attempt Test: Refraction & Dispersion By Prism | 10 questions in 10 minutes | Mock test for NEET preparation | Free important questions MCQ to study Physics Class 12 for NEET Exam | Download free PDF with solutions
Test: Refraction & Dispersion By Prism - Question 1

### A mark on the bottom of the liquid appears to rise by 0.1 m. The depth of the liquid is 1 m. The refractive index of the liquid is​

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 1

As per the given condition,
Real depth of the liquid= 1 m
Apparent depth of the liquid =1−0.1=0.9 m
Refractive index of the liquid = Real Depth/Apparent Depth ​=1/0.9​=1.11

Test: Refraction & Dispersion By Prism - Question 2

### Dispersive power is dependent on

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 2

Dispersive power depends on the material of the prism. When light transitions from one medium to another it bends on the basis of the refractive indices of the two media. Dispersive power is a measure of the amount of difference in the refraction of the highest and lowest wavelengths which enter the prism.

 1 Crore+ students have signed up on EduRev. Have you?
Test: Refraction & Dispersion By Prism - Question 3

### Waves on top of spectrum are

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 3

Infrared: Night vision goggles pick up the infrared light emitted by our skin and objects with heat. In space, infrared light helps us map the dust between stars.
Visible: Our eyes detect visible light. Fireflies, light bulbs, and stars all emit visible light.

Ultraviolet: Ultraviolet radiation is emitted by the Sun and are the reason skin tans and burns. "Hot" objects in space emit UV radiation as well.

X-ray: A dentist uses X-rays to image your teeth, and airport security uses them to see through your bag. Hot gases in the Universe also emit X-rays.

Gamma ray: Doctors use gamma-ray imaging to see inside your body. The biggest gamma-ray generator of all is the Universe.

Test: Refraction & Dispersion By Prism - Question 4

Which is the position of minimum deviation in prism?

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 4

The angle of deviation is minimum when the path of light ray through the prism is symmetrical. i.e., angle of incidence = angle of emergence and path of ray within the prism is parallel to the base of the prism.

Test: Refraction & Dispersion By Prism - Question 5

The ratio of angular dispersion of to the angle of deviation for the mean wavelength is called Dispersive Power. Represented by

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 5

The ratio of angular dispersion to the angle of deviation for the mean wavelength is called Dispersive Power. Represented by

where δv − δr is the angular dispersion for violet and red lights and δr the deviation suffered by the mean light.

Test: Refraction & Dispersion By Prism - Question 6

Angle of dispersion depends on

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 6

The dispersion is the difference in refracting of lights with highest and lowest velocities. Dispersion depends upon the refractive indexes of the two mediums. Thus, depending on the material of the prism.

Test: Refraction & Dispersion By Prism - Question 7

Which relation do we use to find the refractive index of material of prism

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 7

is the right answer.

Test: Refraction & Dispersion By Prism - Question 8

A prism of refractive index √2 and refractive angle A produces minimum deviation δm of a ray on one face at an angle of incidence 45°. The values of A and δm are respectively​

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 8

μ=sinisinr

Again for minimum deviation

μ=sin(A+δmin2)sinA2

∴μ=sinisinA2

⇒sinA2=siniμ

⇒sinA2=sin45∘√2=12

⇒A2=30∘

⇒A=60∘

Again i+e=A+δmin

For minimum deviation i=e

∴2i=A+δmin

⇒δmin=2i−A

⇒δmin=2×45∘−60∘=30∘

Test: Refraction & Dispersion By Prism - Question 9

What is dispersive power?

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 9

Dispersive power of a prism is defined as the ratio between angular dispersion to mean deviation produced by the prism.
If dμ denotes the difference between the refractive indices of material of prism for violet and red light,
ω = δμ / μ – 1
Here ‘μ’ is the refractive index of prism for a mean colour. A mean colour is that colour whose wavelength lies in between that of violet and red. For white light, yellow colour is, generally, taken to be the mean colour.
Since μv is always greater than μr, the dispersive power of a prism is always positive. It depends upon the type of glass used. It is different for crown glass and for flint glass.

Test: Refraction & Dispersion By Prism - Question 10

A thin prism P1 with angle 4° and made from glass of refractive index 1.54 is combined with another thin prism P2 made from glass of refractive index 1.72 to produce dispersion without deviation . The angle of prism P2 is:​

Detailed Solution for Test: Refraction & Dispersion By Prism - Question 10

For dispersion without deviation,
1​−1)×A1​=(μ2​−1)×A2​
μ1​=1.54, A1​=4°, μ2​=1.72
(1.54−1)×4=(1.72−1)×A2​
⇒ A2​=3

## Physics Class 12

105 videos|425 docs|114 tests
Information about Test: Refraction & Dispersion By Prism Page
In this test you can find the Exam questions for Test: Refraction & Dispersion By Prism solved & explained in the simplest way possible. Besides giving Questions and answers for Test: Refraction & Dispersion By Prism, EduRev gives you an ample number of Online tests for practice

## Physics Class 12

105 videos|425 docs|114 tests