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Test: Construction Of Triangles - Class 9 MCQ


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10 Questions MCQ Test Online MCQ Tests for Class 9 - Test: Construction Of Triangles

Test: Construction Of Triangles for Class 9 2024 is part of Online MCQ Tests for Class 9 preparation. The Test: Construction Of Triangles questions and answers have been prepared according to the Class 9 exam syllabus.The Test: Construction Of Triangles MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Construction Of Triangles below.
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Test: Construction Of Triangles - Question 1

In triangle ABC, altitude BE = altitude CF. Then triangle ABC is

Test: Construction Of Triangles - Question 2

To construct a ΔABC in which BC = 10 cm and ∠B= 60 degrees and AB + AC = 14 cm, then the length of BD used for construction.

Test: Construction Of Triangles - Question 3

Which of these triangles are possible to construct by knowing only its altitude?

Test: Construction Of Triangles - Question 4

The construction of a triangle ABC, given that BC = 6 cm, B = ∠45° is not possible when difference of AB and AC is equal to :​

Detailed Solution for Test: Construction Of Triangles - Question 4

Given, BC = 6 cm and ∠B= 45°
We know that, the construction of a triangle is not possible, if sum of two sides is less than or equal to the third side of the triangle.
i.e., AB + BC < AC
⇒ BC < AC – AB
⇒  6 < AC-AB
So, if AC – AB= 6.9 cm, then construction of ΔABC with given conditions is not possible.

Test: Construction Of Triangles - Question 5

Choose the correct statement

Test: Construction Of Triangles - Question 6

The point of concurrence of the three angle bisectors of a triangle, is called

Detailed Solution for Test: Construction Of Triangles - Question 6
The point of interection of
medians - centroid
altitude - orthocentre
angle bisector - incentre
perpendicular bisectors - circumcentre
Test: Construction Of Triangles - Question 7

In triangle ABC, side AB is produced to D so that BD = BC. If angle B = 60° and angle A = 70°, then

Detailed Solution for Test: Construction Of Triangles - Question 7
in this particular given problem angle 
corresponding to the sides 
ad : angle A
CDcd : angle CAB
as, angle ACD > angle CAB, So
ad>cd
Test: Construction Of Triangles - Question 8

The point of intersection of the perpendicular bisectors of the sides of a triangle is called

Detailed Solution for Test: Construction Of Triangles - Question 8
The perpendicular bisectors of the sides of a triangle intersect at a point called the circumcenter of the triangle, which is equidistant from the vertices of the triangle.
Test: Construction Of Triangles - Question 9

To construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm. We draw line segment AB of 12 cm. Draw a ray AX making 90° with AB. The next step is:

Detailed Solution for Test: Construction Of Triangles - Question 9

The below given steps will be followed to construct the required triangle.

Step I:
Draw line segment AB of 12 cm. Draw a ray AX making 90deg with AB.
Step II:
Cut a line segment AD of 18 cm (as the sum of the other two sides is 18) from ray AX.
Step III:
Join DB and make an angle DBY equal to ADB.
Step IV:
Let BY intersect AX at C. Join AC, BC.

ΔABC is the required triangle.

Test: Construction Of Triangles - Question 10

The lengths of the sides of some triangles are given, which of them is not a right angled triangle?

Detailed Solution for Test: Construction Of Triangles - Question 10
If a triangle is right angle then it must satisfy Pythagoras theorem

Now let us check whether all options satisfy it or not....

a) 5^2+12^2=169

5^2+12^2=13^2


b) 5^2+8^2 is not equal to 10^2


c) 3^2+4^2=5^2

d) 7^2+24^2=25^2


It is clear that 2nd option doesn't satisfy Pythagoras theorem...soo option 2 is the answer
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