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Class 9 Exam  >  Class 9 Tests  >  Class 9: Additional Practice  >  Test: Constructions- Case Based Type Questions - Class 9 MCQ

Test: Constructions- Case Based Type Questions - Class 9 MCQ


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5 Questions MCQ Test Class 9: Additional Practice - Test: Constructions- Case Based Type Questions

Test: Constructions- Case Based Type Questions for Class 9 2024 is part of Class 9: Additional Practice preparation. The Test: Constructions- Case Based Type Questions questions and answers have been prepared according to the Class 9 exam syllabus.The Test: Constructions- Case Based Type Questions MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Constructions- Case Based Type Questions below.
Solutions of Test: Constructions- Case Based Type Questions questions in English are available as part of our Class 9: Additional Practice for Class 9 & Test: Constructions- Case Based Type Questions solutions in Hindi for Class 9: Additional Practice course. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free. Attempt Test: Constructions- Case Based Type Questions | 5 questions in 10 minutes | Mock test for Class 9 preparation | Free important questions MCQ to study Class 9: Additional Practice for Class 9 Exam | Download free PDF with solutions
Test: Constructions- Case Based Type Questions - Question 1
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An architect was asked to make a triangular portico with a base 7 m and the angle to its base should be tilted 75° and the sum of other two sides of the portico be 13 m

Q. If the other base angle is 60°, what will be the measure of the third angle :

Detailed Solution for Test: Constructions- Case Based Type Questions - Question 1
Third angle = x

∴ 60° + 75° + x =180° (Angle sum property of triangle)

x = 180 – 135

x = 45°

Test: Constructions- Case Based Type Questions - Question 2
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An architect was asked to make a triangular portico with a base 7 m and the angle to its base should be tilted 75° and the sum of other two sides of the portico be 13 m

Q. Will the architect the able to draw an angle of 75° with ruler and compass only :

Detailed Solution for Test: Constructions- Case Based Type Questions - Question 2
Yes, it is possible to draw an angle of 750 with ruler and compass only.

Step of Construction:

(i) Take a ray OA.

(ii) With O as centre and any convenient radius, draw an arc cutting OA at C.

(iii) With C as centre and the same radius, draw an cutting the first arc at M.

(iv) With M as centre and the same radius, cut off an arc cutting again the first arc at L.

(v) With L and M as centre and radius of more than half of LM, draw two arcs cutting each other at B, join OB which is making 90°.

(vi) Now with N and M as centres again draw two arcs cutting each other at P.

(vii) Join OP.

Then, ∠POA = 75°.

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Test: Constructions- Case Based Type Questions - Question 3
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An architect was asked to make a triangular portico with a base 7 m and the angle to its base should be tilted 75° and the sum of other two sides of the portico be 13 m

Q. What should be known by the architect to justify the construction :

Detailed Solution for Test: Constructions- Case Based Type Questions - Question 3
Properties and theorems should be known by the architect to justify the construction.
Test: Constructions- Case Based Type Questions - Question 4
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An architect was asked to make a triangular portico with a base 7 m and the angle to its base should be tilted 75° and the sum of other two sides of the portico be 13 m

Q. What will be the measure of each angle of 75° angle is bisected once :
Detailed Solution for Test: Constructions- Case Based Type Questions - Question 4

Test: Constructions- Case Based Type Questions - Question 5
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An architect was asked to make a triangular portico with a base 7 m and the angle to its base should be tilted 75° and the sum of other two sides of the portico be 13 m

Q. Which of the following sets of angles can be angle of triangle :
Detailed Solution for Test: Constructions- Case Based Type Questions - Question 5
The sum of all 3 angles of a Δ = 180°

∴ 50° + 30° + 100° = 180°

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