Numerical Ability Test - 3 - Bank Exams MCQ

Follow the BODMAS rule to solve this question, as per the question is given below:

Step 1: Parts of an equation enclosed in ' Brackets ' must be solved first and in the bracket,

Step 2: Any mathematical ' of ' or 'exponent' must be solved next,

Step 3: Next, The part of the equation that contains 'Division' and 'multiplication' are calculated,

Step 4: Last but not least, the parts of the equation that contains 'Addition ' and 'Subtraction' should be calculated

Given :

⇒ (17 × 84 ) + (20% of 960 ) = (16 × 24 ) + (? × 12)

⇒ 1428 + 20 × 960 / 100 = 384 + ? × 12

⇒ 1428 + 192 - 384 = ? × 12

⇒ 1620 - 384 = ? × 12

⇒ 1236 = ? × 12

⇒ ? = 1236 /12

⇒ ? = 103

Hence 103 is the correct answer.

Given:

Follow BODMAS rule to solve this question, as per the order given below:

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.

Now,

Calculation:

√? = 25

? = 25²

? = 625

The correct answer is 625.

Given:

Aditya sells goods at 10% loss

He uses 20% less weight

Formula used:

Gain% = (Gain/C.P) × 100

S.P = C.P × (100 – loss%)/100

Calculation:

Let the cost price of 1000 gm be Rs. 100

Loss% = 10%

S.P = C.P × (100 – loss%)/100

So, S.P = 100 × (90/100)

⇒ S.P = Rs. 90

Now, he is using weight 20% less

So, weight he is using = 1000 × (1000 – 20)/100

⇒ Weight he is using = 800 gm

So, the cost price will be on 800 gm only

So, Total cost price of 800 gm = Rs. 100 × (800/1000)

⇒ Rs. 80

And, total selling price of 1000 gm = Rs. 90 × (1000/1000)

⇒ Rs. 90

Gain = S.P – C.P

⇒ Gain = Rs. 90 – Rs. 80

⇒ Rs. 10

Gain% = (Gain/C.P) × 100

⇒ (Rs. 10/Rs. 80) × 100

⇒ 12.5%

∴ Total Profit percent of Aditya is 12.5%

Given:

I. x² = 361

II. y = √361

Calculation:

I. x² = 361

⇒ x = 19 or x = – 19

II. y = √361

⇒ y = 19

Comparison between x and y (via Tabulation):

∴ We can clearly see that x ≤ y
Confusion Points
Both cases are different :
⇒ x² = 361 → x = 19 & -19 (two values)
⇒ ​ y = √361→ y = 19 (only one value)
Note: Value coming out of perfect square root is always positive.

⇒ 16^(3/2) × (81)^(5/2) ÷ 27² ÷ (8)² = 3^x

⇒ 2^{(4 × (3/2))} × 3^{(4 × (5/2))} ÷ 3^{(3 × 2)} ÷ (2)^{(3 × 2)} = 3^x

⇒ 2⁶ × 3¹⁰ ÷ 3⁶ ÷ 2⁶ = 3^x

⇒ 3^{(10 – 6)} = 3^x

⇒ 3⁴ = 3^x

∴ x = 4

Concept used:
BODMAS rule

Given expression is,
⇒ 40% of 265 + 9³ × 4 – 4848 ÷ 24 × 8 = ?
⇒ 106 + 729 × 4 – 4848 ÷ 24 × 8 = ?
⇒ 106 + 729 × 4 – 202 × 8 = ?
⇒ 106 + 2916 – 1616 = ?
⇒ 3022 – 1616 = ?
∴ ? = 1406

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONENTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒ 410 × ? × 26 = 67250 + 50010

⇒ 10660 × ? = 117260

⇒

Follow BODMAS rule to solve this question, as per the order given below,

Step - 1 - Parts of an equation enclosed in the ‘BRACKETS’ must be solved first

Step - 2 - Any mathematical ‘OF’ or ‘EXPONEMTS’ must be solved next

Step - 3 - Next the part of the equation that contains ‘DIVISION; and ‘MULTIPLICATION’ are calculated

Step - 4 - Last but not least, the parts of the equation that contains ‘ADDITION’ and ‘SUBTRACTION’ should be calculated

Now, the given expression:

⇒

⇒

⇒

⇒

⇒

⇒

⇒ ? = 52

Profit% of Company B in 2008 = 35.
Let the income of Company B in 2008 be Rs. x lakh.
35 = [(x – 220)/220] × 100
∴ x = 297
Income of Company B in 2008 = Rs. 297 lakh.

Let the expenditures of each companies A and B in 2006 be Rs. x lakh.

And let the income of Company A in 2006 be Rs. z lakh.

So that the income of Company B in 2006 = Rs. (342 - z) lakh.

Then, for Company A we have:

45 = [(z - x)/x] × 100

45 = z/x – 1

x = z/1.45 ----(1)

Also, for Company B we have :

60 = [(342 – z – x))/x] × 100

1.6x = 342 – z

x = (342 – z)/1.6 ----(2)

Equating (1) and (2), we get :

1.6z = 1.45(342 – z)

1.6z = 495.9 – 1.45z

3.05z = 495.9

z = 162.59

Substitute the value of z in equation (1)

x = 112.13

Total expenditure of Companies A and B in 2006 = 2x = Rs. 224.26 lakh.

Total income of Companies A and B in 2006 = Rs. 342 lakh.

Total profit = Rs. (342 – 224.26) lakh = Rs. 117.74 lakh.

%Profit = [(Income – Expenditure)/Expenditure] × 100

Let the incomes of each of the two Companies A and B in 2009 be Rs.x.

And let the expenditures of Companies A and B in 2009 be E_A and E_B respectively.

Then, for Company A we have :

25 = (x – E_A)/E_A × 100

E_A = x/1.25

, for Company B we have :

30 = (x – E_B)/E_B × 100

E_B = x/1.3

E_A/E_B = 26/25

Percentage profit earned by A in year 2007 = 60%
Percentage profit earned by A in year 2008 = 40%
Decrease in percentage profit earned by A = (60 – 40)/60 = (100/3)%

Given:

Length of the train = 450m

Speed of the train = 50 m/s

Time taken to cross the man = 10 seconds

Formula used:

Speed(S) = Distance(D)/Time(T)

Calculation:

Let the speed of the man be x m/s

Speed at which train crossed the man = 450/10 m/s

⇒ 45m/s

In the same direction, the speed subtracts

⇒ (50 – x) m/s = 45 m/s

⇒ x = 5 m/s

∴ The speed of the man is 5 m/s.

Follow BODMAS rule to solve this question as per order given below,

Step-1 - Parts of an equation enclosed in ‘Brackets’ must be solved first.

Step-2 - Any mathematical ‘Of’ or ‘Exponent’ must be solved next.

Step-3 - Next, the parts of the equation that contain ‘Division’ and ‘Multiplication’ are calculated.

Step-4 - Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.

Given expression:

(2222 ÷ 20) + (645 ÷ 25) + (3991 ÷ 26) = ?

⇒ 111.1 + 25.8 + 153.5

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

182 - 2600 ÷ 52 = ? × 2

⇒ 324 - 2600 ÷ 52 = ? × 2

⇒ 324 - 50 = ? × 2

⇒ 274 = ? × 2

∴ ? = 137

Follow BODMAS rule to solve this question, as per the order given below,

Step-1: Parts of an equation enclosed in 'Brackets' must be solved first, and in the bracket,

Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,

Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,

Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated

689 – [24² – 280 ÷ 5] = ?²

⇒ 689 – [24² – 56] = ?²

⇒ 689 – [576 – 56] = ?²

⇒ 689 – 520 = ?²

∴ 13 = ?

Given:

A sphere is inscribed in a cylinder.

Concept:

When a sphere is inscribed in a cylinder.

Assumption:

Radius of the sphere = radius of the cylinder = r

Height of the cylinder = diameter of the sphere = 2r

Calculation:

∴ Volume of the cylinder

⇒ π × r² × 2r

⇒ 2πr³

∴ Volume of the sphere,

⇒ 4πr³/3

∴ required ratio,

⇒ 2 ∶ (4/3)

⇒ 3 ∶ 2

As per the given data,

From I)

⇒ x² = 784

⇒ x = ± 28

From II)

⇒ y = √(784) = 28

∴ From the above, we can say x ≤ y

⇒ ? = 7 + 1 = 8

B- Bracket

O- Of

D- Division

M- Multiplication

A- Addition

S- Subtraction

According to this rule,

⇒ 69 + 123 × 2 - 4 = ? ÷ 3 + 11

⇒ 69 + 246 - 4 = ? ÷ 3 + 11

⇒ 315 - 4 = ? ÷ 3 + 11

⇒ 311 - 11 = ? ÷ 3

⇒ 300 × 3 = ?

∴ ? = 900

Calculation:

Let's denote the efficiency of X = 3a and the efficiency of Y = 2a

where 'a' = efficiencies.

Since, X complete the task = 12 days

Its total work = 12 × 3a = 36a.

X, Y, and Z together complete the task in 3 days

So their combined efficiency = 36a / 3 days = 12a.

Now, the ratio of the efficiency of X, Y and Z = 3 : 2 : Z

So, Z's efficiency = 12a - (3a + 2a) = 7a.

Now, the total payment is Rs. 4800

Z's share is proportional to his efficiency, which is 7a out of 12a.

Therefore, Z's payment is (7a / 12a) × Rs. 4800 = Rs. 2800.

Hence option number (C) is the right answer.

(9 - Price of mixture per kg)/(Price of mixture per kg - 8.50) = 30/20

⇒ 30x price of mixture per kg - 255 = 180 - 20x price of mix per kg.

⇒ Price of mixture per kg = (180 + 255)/50 = Rs. 8.70

S.P. of the mixture per kg = 8.70 × 80/100

⇒ Rs. 6.96 ≈ Rs. 7.00

∴ The selling price of the mixture is Rs. 7.00

Given

Pramod bought 30 kg rice price at = Rs. 8.50

Pramod bought 20 kg rice price at = Rs. 9.00

Mixture cost price

Cost price 30 kg = 30 × 8.50 = 255

Cost price 20 kg = 20 × 9.00 = 180

Cost price of the mixture = 255 + 180 = Rs. 435

Total bought rice is = 30 + 20 = 50 kg

Mixture per kg price is = 435/50

⇒ Rs. 8.70

S.P. of the mixture per kg = 8.70 × 80/100

⇒ Rs. 6.96 ≈ Rs. 7.00

∴ The selling price of the mixture is Rs. 7.00

Given:

2 candidates in the election

A candidate who got 25% of total votes polled was defeated by 350 votes

Calculation:

Let the total number of votes polled = X

according to question,

75% of X - 25% of X = 350

⇒ 50% of X = 350

⇒ (50/100) × X = 350

⇒ X = 700

∴ Total number of votes polled 700.

From given line graph,

Total Population in 2019 = 120% of Total Population in 2018

= (120/100) *1,00,000 = 1,20,000

Total Population in 2020 = 140% of Total Population in 2019

= (140/100) *1,20,000 = 1,68,000

Total Population in 2021 = 160% of Total Population in 2020

= (160/100) *1,68,000 = 2,68,800

Total Population in 2022 = 180% of Total Population in 2021

= (180/100) *2,68,800 = 4,83,840

From above solution, Total Population in 2018 = 1,00,000

Total Population in 2020 = 1,68,000

ratio of Number of Population in Year 2018 & 2020 = 1,00,000 : 1,68,000 = 25 : 42

From given line graph,

Total Population in 2019 = 120% of Total Population in 2018

= (120/100) *1,00,000 = 1,20,000

Total Population in 2020 = 140% of Total Population in 2019

= (140/100) *1,20,000 = 1,68,000

Total Population in 2021 = 160% of Total Population in 2020

= (160/100) *1,68,000 = 2,68,800

Total Population in 2022 = 180% of Total Population in 2021

= (180/100) *2,68,800 = 4,83,840

From above solution, Total Population in 2021 = 2,68,800

Total Population in 2020 = 1,68,000

difference between population in Year 2021 & 2020 = 2,68,800 - 1,68,000 = 100800

From given line graph,

Total Population in 2019 = 120% of Total Population in 2018

= (120/100) *1,00,000 = 1,20,000

Total Population in 2020 = 140% of Total Population in 2019

= (140/100) *1,20,000 = 1,68,000

Total Population in 2021 = 160% of Total Population in 2020

= (160/100) *1,68,000 = 2,68,800

Total Population in 2022 = 180% of Total Population in 2021

= (180/100) *2,68,800 = 4,83,840

From above solution, Total Population in 2018 = 1,00,000

Total Population in 2019 = 1,20,000

average number of Population in year 2018 & 2019 together = (1,00,000 + 1,20,000)/ 2 = 1,10,000

From given line graph,

Total Population in 2019 = 120% of Total Population in 2018

= (120/100) *1,00,000 = 1,20,000

Total Population in 2020 = 140% of Total Population in 2019

= (140/100) *1,20,000 = 1,68,000

Total Population in 2021 = 160% of Total Population in 2020

= (160/100) *1,68,000 = 2,68,800

Total Population in 2022 = 180% of Total Population in 2021

= (180/100) *2,68,800 = 4,83,840

From above solution, Total Population in 2018 = 1,00,000

Total Population in 2020 = 1,68,000

Percentage increase in Population of year 2020 with respect to total population in 2018 = (1,68,000 - 1,00,000)/1,00,000 = 68%

From given line graph,

Total Population in 2019 = 120% of Total Population in 2018

= (120/100) *1,00,000 = 1,20,000

Total Population in 2020 = 140% of Total Population in 2019

= (140/100) *1,20,000 = 1,68,000

Total Population in 2021 = 160% of Total Population in 2020

= (160/100) *1,68,000 = 2,68,800

Total Population in 2022 = 180% of Total Population in 2021

= (180/100) *2,68,800 = 4,83,840

From above solution, Total Population in 2021 = 2,68,800

Total Population in 2022 = 4,83,840

Total Population in 2021 & 2022 together = 2,68,800 + 4,83,840 = 7,52,640

Given:
37.5% of 120.08 + 56 ÷ 7.99 = ?
Rule:

Calculation:

⇒ 37.5% of 120.08 + 56 ÷ 7.99 = ?

⇒ 45 + 56 ÷ 8 = ?

⇒ 45 + 7 =?

⇒ ? = 52

∴ The required answer is 52

Given:

The sum of the numbers = 100

Calculation:

Let the numbers be 6x, 9x, and 10x respectively

According to the question

⇒ 6x + 9x + 10x = 100

⇒ 25x = 100

⇒ x = 100/25 = 4

The smallest number = 6x = 6 × 4 = 24

∴ The required result will be 24.