First Law Of Thermodynamics MCQ Level – 1 (part - 2) - Physics MCQ

If W is work done by the system then –W would be the work done on the system by its surroundings.
The correct answer is: Work done on the system by its surroundings

For an ideal gas, internal energy depends only on temperature. Thus, there is no change in the internal energy of an ideal gas in an isothermal process.

Correct Answer :- a

Explanation : In a cyclic process, the system starts and returns to the same thermodynamic state.

Thus, change in internal energy in a cyclic process  ΔU=0

From !st law of thermodynamics,  ΔQ = ΔU + ΔW

⟹ ΔQ = 0 + ΔW

ΔQ = ΔW

Heat is thermal energy transferred from a hotter body to a cooler body that arein contact. Hence, it is not a property of the system.
The correct answer is: Heat

The above statement is nothing but zeroth law of thermodynamics.
The correct answer is: Zeroth law of thermodynamics

In adiabatic processes, dQ = 0 heat remains fixed in the process, hence adiabatic processes do not involve heat.
The correct answer is: Adiabatic processes

dU = dQ – dW
⇒ ΔU = ΔQ – ΔW

ΔW, work done by gas when compressed isothermally is positive.


The correct answer is:  

dθ = dU + dW
The correct answer is: energy

Since work done = Area between p-V curve and volume axis

Hence, work in positive direction is clockwise
W_xy = Area xyBA
Wyx = Area yBAx
and 
The correct answer is: clockwise

In a cyclic process as shown above, the area enclosed by the curve gives the work done by the system.
The correct answer is: The area abcda represents the work done by the system for the process