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Test: Instantaneous Velocity and Speed - ACT MCQ


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10 Questions MCQ Test Physics for ACT - Test: Instantaneous Velocity and Speed

Test: Instantaneous Velocity and Speed for ACT 2024 is part of Physics for ACT preparation. The Test: Instantaneous Velocity and Speed questions and answers have been prepared according to the ACT exam syllabus.The Test: Instantaneous Velocity and Speed MCQs are made for ACT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Instantaneous Velocity and Speed below.
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Test: Instantaneous Velocity and Speed - Question 1

What is the velocity for a body following the graph below at 10s?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 1

At time = 10s, the distance covered is 5m. Velocity = distance/time. Hence, velocity v at 10s = 5/10 = 0.5 m/s.

Test: Instantaneous Velocity and Speed - Question 2

A car is moving in a spiral starting from the origin with uniform angular velocity. What can be said about the instantaneous velocity?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 2

This type of motion can be called circular motion with increasing radius. As the radius increases, the tangential velocity increases (v = rw). Now, as there is only one velocity present, the speed will be equal to the magnitude of the tangential velocity.

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Test: Instantaneous Velocity and Speed - Question 3

The trajectory of an object is defined as x = (t - 4)2, what is the velocity at t = 5?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 3

The function for velocity can be derived by differentiating the equation with respect to t. v = 2(t - 4) is the required function. When t = 5, v = 2(5 - 4) = 2.

Test: Instantaneous Velocity and Speed - Question 4

Which of the following can be used to describe how fast an object is moving along with the direction of motion at a given instant of time?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 4

Instantaneous velocity describes the velocity of an object at a given time instant. Average speed is the speed at which the object travels throughout the time period and not an instant. Speed is a scalar quantity; hence it cannot show the direction of motion.

Test: Instantaneous Velocity and Speed - Question 5

What happen to the instantaneous velocity in a non-uniformly accelerated motion?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 5

The instantaneous velocity will increase with time. If the motion is accelerated, no matter if the acceleration is constant, or variable, the instantaneous velocity will increase. Variation of acceleration describes how to change in velocity is changing.

Test: Instantaneous Velocity and Speed - Question 6

A ball is thrown up in the sky, at what position will the instantaneous speed be minimum?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 6

When the ball rises up, there will be a point where it will be in the state of instantaneous rest. At the this position the speed of the ball will be 0. Speed is maximum at the initial and final points.

Test: Instantaneous Velocity and Speed - Question 7

Which of the following is the correct formula for instantaneous velocity?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 7

The correct formula is v = dx/dt. Instantaneous velocity is the velocity of the object at a given time instant. v = x/t is the formula for average velocity.

Test: Instantaneous Velocity and Speed - Question 8

A point is moving with uniform acceleration, in the eleventh and fifteenth seconds from the commencement it moves through 640 and 840 cms respectively, find its initial velocity, and the acceleration with which it moves?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 8

Given:

Acceleration is uniform.

S11 = 640 cm 

S15 = 840 cm

Formula:

Distance traveled in nth second  

where u is the initial velocity and a is the acceleration.

Calculations:

S11 = u + a/2(2 × 11 - 1)

⇒ 640 = u + 21a/2   ---   (i)

S15 = u + a/2(2 × 15 - 1)

⇒ 840 = u + 29a/2   ---  (ii)

Subtracting (i) from (ii) :

⇒ 200 = 4a

⇒ a = 50 cm/s2

Putting a = 50 in (i) -

u = 115 cm/s

Test: Instantaneous Velocity and Speed - Question 9

In which of the following motion the net force on the body will be zero?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 9

Concept

  • Uniform Linear motion: The motion of an object in which the object travels in a straight line and its velocity remains constant along that line as it covers equal distances in equal intervals of time, irrespective of the duration of the time.
    • Example: Ball moving on a frictionless surface with constant velocity.
    • In this type of motion, the net force on the body will be zero.
  • Non-uniform motion: The motion of an object in which the object travels with varied speed and it does not cover the same distance in equal time intervals, irrespective of the time interval duration.
    • Example: The motion of a train
    • There is some net force acting on the body in non-uniform motion.
    • It is also called the accelerated motion.

Explanation

  • In the case of the uniform linear motion, there is no change in the velocity of the body. So the net force on the body will be zero.
  • Hence option 1 is correct.
  • In the case of circular motion, there will be a centripetal force always acting on the body even if it is a uniform circular motion. 
Test: Instantaneous Velocity and Speed - Question 10

The position of a particle is given by x = -2t2 + 4t. How much time the particle will take to come in rest?

Detailed Solution for Test: Instantaneous Velocity and Speed - Question 10

Concept:

Velocity: The displacement per unit time is called velocity.

where v is the velocity, Δx is the change in displacement, Δt is the change in time.

A body comes to rest when the velocity is zero.

Calculation:
Given that position of a particle is given by: x = -2t2 + 4t

A body comes to rest when the velocity is zero.

v = −4t + 4 = 0

t = 1 sec

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