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NEET Exam  >  NEET Tests  >  NCERTs at Fingertips: Textbooks, Tests & Solutions  >  Test: Temperature Dependence of Resistivity (NCERT) - NEET MCQ

Test: Temperature Dependence of Resistivity (NCERT) - NEET MCQ


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5 Questions MCQ Test NCERTs at Fingertips: Textbooks, Tests & Solutions - Test: Temperature Dependence of Resistivity (NCERT)

Test: Temperature Dependence of Resistivity (NCERT) for NEET 2024 is part of NCERTs at Fingertips: Textbooks, Tests & Solutions preparation. The Test: Temperature Dependence of Resistivity (NCERT) questions and answers have been prepared according to the NEET exam syllabus.The Test: Temperature Dependence of Resistivity (NCERT) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Temperature Dependence of Resistivity (NCERT) below.
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Test: Temperature Dependence of Resistivity (NCERT) - Question 1
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The resistance of a heating element is 99Ω at room temperature. What is the temperature of the element if the resistance is found to be 116Ω? (Temperature coefficient of the material of the resistor is 1.7 × 10−4∘C−1)

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 1

Here, R0 = 99Ω, T0 = 27∘C
RT = 116Ω;
α = 1.710−4∘C−1
∴ RT = R0 [1 + α(T − T0)]
∴ RTR0 − 1 = α(T − T0)
⇒ 11699 − 1= α(T − T0)

= 
∴
⇒ T = 1010.1 + T0 = 1010.1 + 27

= 1037.1∘C

Test: Temperature Dependence of Resistivity (NCERT) - Question 2
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The resistance of the wire in the platinum resistance thermometer at ice point is 5Ω and at steam point is 5.25Ω. When the thermometer is inserted in an unknown hot bath its resistance is found to be 5.5Ω. The temperature of the hot bath is

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 2

Here,R0 = 5Ω, R100 = 5.25Ω, Rt = 5.5Ω
As,R1 = R0(1 + αt)
∴R100 = R0(1 + α100)

Equation (i) and (ii), we get

= 200oC

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Test: Temperature Dependence of Resistivity (NCERT) - Question 3
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The resistance of wire in a heater at room temperature is 65Ω. When the heater is connected to a 220V supply the current settles after a few seconds to 2.8A. What is the steady temperature of the wire. (Temperature coefficient of resistance α = 1.70 × 10−4∘C−1)

Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 3

Here, T1 = 27∘C, R1 = 65Ω
R2
= Supply voltage / Steady current
= 220 / 2.8
= 78.6Ω
Now, using the relation
R2 = R1[1 + α(T2 − T1)]
∴ 

T2 − T1 = 1231
T2 = 1231 + T1 = 1231 + 27
= 1258C∘

Test: Temperature Dependence of Resistivity (NCERT) - Question 4
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A wire has a resistance of 2.5Ω at 28∘C and a resistance of 2.9Ω at 100∘C. The temperature coefficient of resistivity of material of the wire is
Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 4

Here, R1 = 2.5Ω, T1 = 28∘C
R2 = 2.9Ω and T2 = 100∘C
As R2 = R1[1 + α(T2 − T1)]
∴ 2.9 = 2.5[1 + α(100 − 28)]

= 
= 2.22 × 10−3∘C−1

Test: Temperature Dependence of Resistivity (NCERT) - Question 5
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Figure (a) and figure (b) both are showing the variation of resistivity (p) with temperature (T) for some materials. Identify the types of these materials.
Detailed Solution for Test: Temperature Dependence of Resistivity (NCERT) - Question 5

In conductors due to increasein temperature the resistivity increases and in semiconductors if the decreases exponentially.

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