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Test: Alkenes Electrophilic Addition Reaction - NEET MCQ


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Test: Alkenes Electrophilic Addition Reaction - Question 1

Direction (Q. Nos. 1 - 7) This section contains 7 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.

Q. What is the major addition product in the following reactions?

Test: Alkenes Electrophilic Addition Reaction - Question 2

What is the major product in the following reaction?

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Test: Alkenes Electrophilic Addition Reaction - Question 3

Consider the following reaction.​

Molecular formula of both P and Q are C6H13l
tetra substituted alkene isom er of A. Hence, P is most likely

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 3

Molecular formula of P and Q is C6H13I and this 3 degree reaction mechanism is SN1 mechanism so by that I molecules from HI attack as nucleophile to compound and when the reaction with KOH and C2H5OH rearrangement of I take place and the molecule formed is 2 iodo-2, 3- dimethyl butane.

Test: Alkenes Electrophilic Addition Reaction - Question 4

If trans-2-pentene is treated with Br2 in CCI4 in presence of Lewis acid FeBr3

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 4

Trans-2-pentene on reaction with Br2 in CCl4 produces mainly (±) 2,3dibromopentene. A molecule of bromine is added across C=C double bond. A racemic mixture is obtained as the product.

Test: Alkenes Electrophilic Addition Reaction - Question 5

3-methyl-1-pentene has a chiral carbon. If a pure enantiomer of 3-methyl-1-pentene is treated with HBr, the correct statement regarding major bromoalkane formed is

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 5

The correct answer is Option A.

3−Methyl−pent−2−ene in reaction with HBr forms an additional product. 

A molecule of HBr is added to C=C double bond. 
The addition follows anti-Markovnikov's rule. Br is added to less substituted C atoms. 
The number of possible stereoisomers for the products is four.  The product has 2 chiral C atoms and is unsymmetrical.
 
An enantiomer will rotate the  plane of polarization the equal angle  but opposite direction. A racemic mixture will not rotate the plane of polarization.
 

Test: Alkenes Electrophilic Addition Reaction - Question 6

Consider the following reaction.

Which of the following would not be formed in the above reaction?

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 6

Therefore , correct answer is :

Test: Alkenes Electrophilic Addition Reaction - Question 7

HBr reacts with CH2 = CH – OCH3 under anhydrous conditions at room temperature to give 

[AlEEE 2006]

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 7

Methyl vinyl ether is a very reactive gas. It is hydrolysed rapidly by dilute acids at room temperature to give methanol and aldehyde. However, under anhydrous conditions at room temperature, it undergoes many addition reactions at the double bond.

Electrophilic addition reaction more favourable.

*Multiple options can be correct
Test: Alkenes Electrophilic Addition Reaction - Question 8

Direction (Q. Nos. 8 - 13) This section contains 6 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. In which of the following reaction(s), major product is formed by the rearrangement of reactive intermediate?

*Multiple options can be correct
Test: Alkenes Electrophilic Addition Reaction - Question 9

Consider the following reaction.

The correct statement(s) is/are

*Multiple options can be correct
Test: Alkenes Electrophilic Addition Reaction - Question 10

In which of the following reactions, reactants and products are correctly matched ?

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 10

The correct answer is option A,B
With H2​/Pd−BaSO4​, cis hydrogenation will take place at both triple bonds.
With NaNH2​, Sytzeff's elimination product will be the major one

(A) Cis addition of hydrogen
(B) Carbanion is more stable at secondary carbon so Saytzeff's elimination product will form.
(C) Carbanion should form at secondary carbon but given product is formed from tertiary unstable carbanion carbon so this is not possible.
(D) Complete reduction of alkyne to alkane in Pt reduction

*Multiple options can be correct
Test: Alkenes Electrophilic Addition Reaction - Question 11

Which is the important reactive in termediate in the following reaction ?

*Multiple options can be correct
Test: Alkenes Electrophilic Addition Reaction - Question 12

In which of the following halogen addition reactions, racemic mixture of products is formed?

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 12

*Multiple options can be correct
Test: Alkenes Electrophilic Addition Reaction - Question 13

Consider the following addition reaction on a pure enantiomer of the shown bromoalkene.

Q. What is/are true regarding products of the above reaction ?

Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 13

The correct answer is Option C and D.
One of the product is a meso dibromide

 

Test: Alkenes Electrophilic Addition Reaction - Question 14

Direction (Q. Nos. 14 - 16) This section contains a paragraph, describing theory, experiments, data, etc.
Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.

 

Q. What is P ?

Test: Alkenes Electrophilic Addition Reaction - Question 15

A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.

 

Q. Q and R respectively are

Test: Alkenes Electrophilic Addition Reaction - Question 16

A mixture of hydrocarbons contain three compounds P, Q and R. Q and R are stereoisomers. When this mixture is treated with cold, concentrated H2SO4 , Q and R got a bsorbed while Premained unreacted , forming a separate layer at surface. After separation of P, the acid solution is heated and the hydrocarbons Q and R recovered, containing predominantly Q. When vaporised mixture of P, Q and R is passed over heated Ni containing adsorbed H2 gas, a single alkane of six carbon was obtained. Also, Q on treatment with Br2/CCI4 in the presence of FeBr3, a meso dibromide is formed.

 

Q. If Q and R are treated separately with HBr, the correct statement concerning addition product is

*Answer can only contain numeric values
Test: Alkenes Electrophilic Addition Reaction - Question 17

Direction (Q. No. 17 - 20) This section contains 4 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q. If a pure enantiomer of 5 -bromo -2 -hexene is treated with Br2— CCI4 , how many different tribromides would be formed ?


*Answer can only contain numeric values
Test: Alkenes Electrophilic Addition Reaction - Question 18

If a racemic mixture of 3 -methyl- 1-pentene is treated with HCl, how many different chloropentane (importantproducts only) would be formed?


*Answer can only contain numeric values
Test: Alkenes Electrophilic Addition Reaction - Question 19

Consider the following reaction.

Q. How many different products would be formed?


Detailed Solution for Test: Alkenes Electrophilic Addition Reaction - Question 19

In the reaction shown, where cyclohexene reacts with excess HBr in the presence of H₂O₂, the reaction follows an anti-Markovnikov addition mechanism. This means that HBr adds across the double bond, with the bromine atom attaching to the less substituted carbon of the alkene, and hydrogen adding to the more substituted carbon.

However, due to the excess HBr, the reaction can proceed to form two products:

  1. 1-Bromo-cyclohexene: The major product where the Br atom adds to the carbon that was originally part of the double bond (the less substituted carbon).

  2. 2-Bromo-cyclohexene: If the reaction continues with further additions of HBr, a second bromine can add to the other carbon of the double bond (leading to the 2-bromo isomer).

Thus, the two products are:

  • 1-bromo-cyclohexene (from anti-Markovnikov addition).
  • 2-bromo-cyclohexene (from further addition).

If HBr is in excess, the major product will be 1-bromo-cyclohexene, but there could be a small amount of 2-bromo-cyclohexene as well depending on the reaction conditions. However, since HBr is in excess, the second addition is likely to dominate and result in the formation of a dihalo product.

*Answer can only contain numeric values
Test: Alkenes Electrophilic Addition Reaction - Question 20

Consider the following reaction and the major product.

Q. If energy profile of the above reaction is drawn, how many transition states would be observed?


Test: Alkenes Electrophilic Addition Reaction - Question 21

Direction (Q. No. 21) Choices for the correct combination of elements from Column I and Column lI are given as options (a), (b), (c) and (d), out of which one is correct.

Consider the reactions in Column I and match with the properties of products from Column II.

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