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EmSAT Physics Mock Test- 5 - EmSAT Achieve MCQ


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30 Questions MCQ Test Mock Tests for EmSAT Achieve 2024 - EmSAT Physics Mock Test- 5

EmSAT Physics Mock Test- 5 for EmSAT Achieve 2024 is part of Mock Tests for EmSAT Achieve 2024 preparation. The EmSAT Physics Mock Test- 5 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The EmSAT Physics Mock Test- 5 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EmSAT Physics Mock Test- 5 below.
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EmSAT Physics Mock Test- 5 - Question 1

The sun subtends an angle of half a degree at the pole of a concave mirror which has a radius of curvature of 15 metres. Then the size (disameter) of the image of the sun formed by the concave mirror is

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 1
See , in this case , 
u = ∞ , Let x be the diameter , 
using mirror formula , 
1/u + 1/v = 1/f 
v = f , 
let ∆ be the angle , 
∆ = x/f 
x = ∆f , 
Multiply these two u will get diameter , or u can change your angle to radian.
EmSAT Physics Mock Test- 5 - Question 2

A convex lens of focal length 24 cms is placed 12 cms in front of a convex mirror. It is found that when a pin is placed 36 cms in front of the lens, it coincides with its own inverted image formed by the lens and the mirror.Then the focal length of the mirror is

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 2
A convex lens of focal length 24 cm is placed 12 cm in front of a convex mirror. It is found that when a pin is placed 36 cm in front of the lens, it coincides with its own inverted image formed by the lens and the mirror. Then the focal length of the mirror is 30 cm. 
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EmSAT Physics Mock Test- 5 - Question 3

A ray of light makes an angles of with the horizontal and strikes a plane mirror which is inclined
at an angle to the horizontal.The angle  for which the reflected ray becomes vertical, is

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 3
Draw a ray-diagram,
Angle between the reflected and incident ray = 80degree (Final ray is vertical and incidence is 10 wrt horizontal)
Angle of incidence = angle of reflected ray = 40degree
Angle of reflected ray with mirror = 90degree – 40degree = 50degree
So, angle with horizontal = 90degree – 50degree = 40degree
EmSAT Physics Mock Test- 5 - Question 4

The refractive index of a given piece of transparent quartz if greatest for

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 4
 CORRECT OPTION IS (B). 
EmSAT Physics Mock Test- 5 - Question 5

If the critical angle for total internal reflection from a medium to vacuum is the velocity of light in
the medium is
 

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 5
We should know Snell's law
n1 sin I = n2 sin r
for critical angle the value of r becomes 90 degree
n1 / n2 = sin 90 / sin 30 = 2
also
n1/n2 = v2/v1
2 = 3 * 10^8 / velocity in medium
v= 1.5 * 10^8
EmSAT Physics Mock Test- 5 - Question 6
Two immiscible liquids are in a cylindrical vessel of depths of 8.4 cm and 7.8 cm, their refractive indices being 1.2 and 1.3 respectively. An object O at the bottom isseen from vertically
above the liquids. The upward displacement in cm in its apparant position is

EmSAT Physics Mock Test- 5 - Question 7

X is a small angled prism of angle made of a material of refractive index 1.5. A ray of light is made incident as shown in figure. M is a plane mirror.The angle of deviation for the ray reflected from the mirror. M with respect to incident ray is

EmSAT Physics Mock Test- 5 - Question 8
The face AC of a prism ABC of refracting angle is silvered. A ray is incident on face AB at an angle of as shown in figure. The refracted ray undergoes reflection on face AC and retraces its path. The refractive index of the prisms is

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 8
Use triangle property180 - (90 + 30 ) = 60r = (90 - 60) = 30sin i/sin r = Refractive Index (R I)R I = sin 45/sin 30 = √2
EmSAT Physics Mock Test- 5 - Question 9
If half the body of a lens is covered with black paper the image produced by the lens will
EmSAT Physics Mock Test- 5 - Question 10
The distance between the object and the screen is D (greater than 4 times the focal length of a convex lens). Real images of the object are obtained on the screen for two positions of the lens that are separated by distance d apart. The ratio of size of the images in the two positions of the lens are
EmSAT Physics Mock Test- 5 - Question 11
An object 20 cm high produces using a lens a real image of 80cm.When an object is shifted by 5 cm a real image 40 cm high is produced.The power of the lens is
EmSAT Physics Mock Test- 5 - Question 12
When the object is at a distance x1 and x2, a real and a virtual image of the same size are formed
respectively. The focal length of the convex lens is
EmSAT Physics Mock Test- 5 - Question 13
An isotropic source of 2 candela  produces a light flux equal to
EmSAT Physics Mock Test- 5 - Question 14
A lamp is hanging at a height 40 cm from the center of a table. If its height is increased by 10 cm, the illuminance on the table will decrease by
EmSAT Physics Mock Test- 5 - Question 15
The intensity of light at a distance r from the axis of a long cylindrical source is proportional to
EmSAT Physics Mock Test- 5 - Question 16
Rainbows are produced when sunlight
EmSAT Physics Mock Test- 5 - Question 17
The magnifying power of telescope can be increased by
EmSAT Physics Mock Test- 5 - Question 18
A movie projector projects an image of length 3.5 m of a 35 mm. movie film on a screen. Neglecting
absorption of light by the film and the air, the ratio of the illumination on the screen is
EmSAT Physics Mock Test- 5 - Question 19
The focal length of a simple convex lens used as a magnifier is 10 cm. For the image to be formed at a distance of distinct vision (D = 25 cm), the object
must be placed away from the lens at a distance of
Detailed Solution for EmSAT Physics Mock Test- 5 - Question 19
EmSAT Physics Mock Test- 5 - Question 20
A person can see objects only at distance greater than 40 cm. He is advised to use lens of power
Detailed Solution for EmSAT Physics Mock Test- 5 - Question 20
*Answer can only contain numeric values
EmSAT Physics Mock Test- 5 - Question 21

A compound microscope has an eyepiece of focal length 10 cm and an objective of focal length 4 cm. Calculate the magnification, if an object is kept at a distance of 5 cm from the objective so that final image is formed at the least distance of distinct vision (20 cm) :-


*Answer can only contain numeric values
EmSAT Physics Mock Test- 5 - Question 22

An object is placed on the axis of a convex lens. Its image is formed 80 cm from the object. The magnification is 3. The focal length of the lens (in cm) is:-


*Answer can only contain numeric values
EmSAT Physics Mock Test- 5 - Question 23

A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aperture is illuminated normally by a parallel beam of wavelength 5 × 10–5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is :-


Detailed Solution for EmSAT Physics Mock Test- 5 - Question 23

f = D = 60 cm
For first minima,

*Answer can only contain numeric values
EmSAT Physics Mock Test- 5 - Question 24

Young's double slit experment is first performed in air and then in a medium other than air. It is found that 8th bright fringe in the medium lies where 5th dark fringe lies in air. The refractive index of the medium is nearly :-


Detailed Solution for EmSAT Physics Mock Test- 5 - Question 24

*Answer can only contain numeric values
EmSAT Physics Mock Test- 5 - Question 25

Find the ratio of refractive index of transmitted medium with that of incident medium when the Brewster angle is 60 degree.


Detailed Solution for EmSAT Physics Mock Test- 5 - Question 25

EmSAT Physics Mock Test- 5 - Question 26

Which among the following arrangements can be used to verify Ohm's law? It is given that Rs is shunt resistance, RL is a high resistive wire and RT is a test resistance wire.

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 26

We require a voltmeter, an ammeter and resistance wires to verify Ohm's law. A voltmeter can be formed by connecting a high resistance RL in series with the galvanometer. An ammeter can be formed by connecting a small resistance RS in parallel with a galvanometer. The configuration of ammeter and voltmeter should be connected with the test resistance in series and parallel connections, respectively. The battery should be connected in series with the test resistance. Therefore, it is the correct option.

EmSAT Physics Mock Test- 5 - Question 27

Find the angle between the magnetic field and the direction of current. if a wire of 1.5 m length and carrying current of 5 ampere, when it is placed in a uniform magnetic field of 2 Tesla a force of 7.5 newton act on it.

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 27


Hence θ = 30°
Hence, this is the required solution.

EmSAT Physics Mock Test- 5 - Question 28

To increase the sensitivity of a moving coil galvanometer, the correct treatments are:
I. Place magnetic core in the coil
II. Increase the number of turns
III. Decrease the area of the coil

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 28

For a moving coil galvanometer, 
C = Restoring force
B = Magnetic field strength
N = Number of turns in coil
A = Area of the coilFor increasing the sensitivity of the galvanometer, θ should be increased. Therefore,N can be increased.A can be increased.B can be increased and can be achieved by using a strong magnet or a magnetised/iron core. Therefore, it is the correct option.

EmSAT Physics Mock Test- 5 - Question 29

In a Young's double slit experiment, the light used has two wavelengths of 300 nm and 540 nm. A pattern of dark and bright fringes is obtained due to the lights of the two wavelengths. If the distance between the slits and the distance between the first two consecutive completely dark fringes respectively are 0.5 mm and 15 mm, what is the distance between the plane of slits and the plane of the screen?

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 29

Let the nth minima of 300 nm wavelength coincide with the mth minima of 540 nm wavelength light.
Therefore,

Therefore, 5th minima of 540 nm wavelength coincides with 3rd minima of 300 nm light.
Location of the minima for 300 nm light,

Next dark fringe of 300 nm wavelength will coincide at n = 8.

Distance between two minima = 15 mm
Therefore,

This is the required solution.

EmSAT Physics Mock Test- 5 - Question 30

The wavelength of radiation emitted is λ0 when an electron jumps from the third to the second orbit of a hydrogen atom. For the electron jump from the fourth to the second orbit of the hydrogen atom, find the wavelength of the emitted radiation.

Detailed Solution for EmSAT Physics Mock Test- 5 - Question 30

Wavelength of the emitted radiation is given by:

From 3rd to 2nd

From 4th to 2nd

Hence, this is the required solution.

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