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EmSAT Achieve Exam  >  EmSAT Achieve Tests  >  Mock Tests for EmSAT Achieve 2024  >  EmSAT Chemistry Mock Test- 1 - EmSAT Achieve MCQ

EmSAT Chemistry Mock Test- 1 - EmSAT Achieve MCQ


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30 Questions MCQ Test Mock Tests for EmSAT Achieve 2024 - EmSAT Chemistry Mock Test- 1

EmSAT Chemistry Mock Test- 1 for EmSAT Achieve 2024 is part of Mock Tests for EmSAT Achieve 2024 preparation. The EmSAT Chemistry Mock Test- 1 questions and answers have been prepared according to the EmSAT Achieve exam syllabus.The EmSAT Chemistry Mock Test- 1 MCQs are made for EmSAT Achieve 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for EmSAT Chemistry Mock Test- 1 below.
Solutions of EmSAT Chemistry Mock Test- 1 questions in English are available as part of our Mock Tests for EmSAT Achieve 2024 for EmSAT Achieve & EmSAT Chemistry Mock Test- 1 solutions in Hindi for Mock Tests for EmSAT Achieve 2024 course. Download more important topics, notes, lectures and mock test series for EmSAT Achieve Exam by signing up for free. Attempt EmSAT Chemistry Mock Test- 1 | 50 questions in 120 minutes | Mock test for EmSAT Achieve preparation | Free important questions MCQ to study Mock Tests for EmSAT Achieve 2024 for EmSAT Achieve Exam | Download free PDF with solutions
EmSAT Chemistry Mock Test- 1 - Question 1
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 20 g of an ideal gas contains only atoms of S and O occupies 5.6 L at NPT. What is the mol. wt. of gas ?

Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 1

Given,
Mass of gas = 20 g
Pressure of gas = 1 atm
Volume of gas = 5.6 L
Temperature of gas = 273 K
Using ideal gas law,

where,
P = pressure of the gas
V = volume of the gas
T = temperature of the gas
n = number of moles of the gas
R = gas constant = 0.0821
Latm/moleK
M = molar mass of gas
w = mass of gas
Now put all the given values in the formula, we get
Therefore, the molar mass of the gas is, 80.0475 g/mole

EmSAT Chemistry Mock Test- 1 - Question 2
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5.6 litres of a gas at N.T.P. are found to have a mass of 11 g. The molecular mass of the gas is

Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 2
1 mole or molecular mass of the gas has volume 22.4 L
Given that:
11g of gas has volume 5.6 L

So molecular mass = (11/5.6)×22.4 = 44 u
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EmSAT Chemistry Mock Test- 1 - Question 3
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A crystalline salt Na2SO4.xH2O on heating losses 55.9 per cent of its mass. The formula of crystalline salt is---

Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 3
Na2SO4.xH2O has weight =46+32+64+18x=142+18xg
on heating it will become anhydrous so, I.e. water will be evaporated.
55.9% of(142+18x)=18x=>79.378+10.062x=18x
=>7.938x=79.378=>x~10g
so Na2SO4.10H2O and this amount of water is called
water of crystallisation.
EmSAT Chemistry Mock Test- 1 - Question 4
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Vapour density of a metal chloride is 66. Its oxide contains 53% metal. The atomic weight of the metal is
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 4
Equivalent of metal = Equivalent of chloride

53/n = 47/8 , E = 9.02 , Atomic mass of metal = n X 9.02

Molecular mass of chloride = 2 X 66 = n X 9.02 + n X 35.5

on solving n = 3

Atomic mass of metal = 9.02 X 3 = 27.06
EmSAT Chemistry Mock Test- 1 - Question 5
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When two aqueous solutions react together to give off solid product, this reaction is known as
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 5
Chemical reactions:precipitation. The precipitate forms because the solid (AgCl) is insoluble in water. That is true for all precipitates - the solids are insoluble in aqueous solutions. Precipitation reaction occur all around us.
EmSAT Chemistry Mock Test- 1 - Question 6
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At S.T.P. the density of CCl4 vapour in g/L will be nearest to
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 6
Stp of mole of a gas = 22.4L 1mole --> 154g of CCl4 density=mass/volume =154/22.4 = 6.875
EmSAT Chemistry Mock Test- 1 - Question 7
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Which of the following transitions of electrons in the hydrogen, atom will emit maximum energy ?
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 7

EmSAT Chemistry Mock Test- 1 - Question 8
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The uncertainty found from the uncertainty principle  (Δx.Δp = h/4 π) is
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 8
Heisenberg uncertainty principle states that exact momentum and exact position of matter wave can't be determined simultaneously.
∆P.∆X>equal to h/4π
EmSAT Chemistry Mock Test- 1 - Question 9
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The number of atoms of hydrogen in 2 moles of NH3
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 9

Therefore 2 moles will have 1.204*1024 molecules of NH3.

There are 3 atoms in each molecule, so 2 moles will have 3*(1.204*1024) atoms

which is 3.61 * 1024 atoms.

EmSAT Chemistry Mock Test- 1 - Question 10
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The spectrum of He is expected to be similar to that of
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 10

The spectrum of an atom depends on the number of electrons present in it. Here, helium has two electrons, so the spectrum of Li+ (Z = 3) is similar to that of helium because both He and Li+ have two electrons.

EmSAT Chemistry Mock Test- 1 - Question 11
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The electrons present in K-shell of the atom will differ in
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 11
The electrons present in K-shell of the atom will differ in spin quantum number as the electrons will have opposite spins.
EmSAT Chemistry Mock Test- 1 - Question 12
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Which of the following statements about quantum numbers is wrong?
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 12

If the value of l=0, then electron lies in s-subshell which has spherical shape. So electron distribution is spherical.

Shape of orbital is given by azimuthal quantum number as it describes the subshell.

Magnetic quantum number determines the shift of atomic orbital due to external magnetic field i.e., zeeman effect.

Spin quantum number describes the spin of electron in particular orbital. Orientations of electron cloud is specified of a magnetic quantum number.

So B option is incorrect.

EmSAT Chemistry Mock Test- 1 - Question 13
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Out of the two compounds shown below, the vapour pressing of B at a particular temperature is expected to be
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 13

Because of intramolecular hydrogen bonding in (B), i.e., ortho nitrophenol, the vapour pressure of ortho nitrophenol is expected to be higher than paranitrophenol.

Therefore, the correct option is A.

EmSAT Chemistry Mock Test- 1 - Question 14
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In which of the following molecules, the central atom does not use sP3-hybrid orbitals in its bonding ?
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 14

In the given options, BeF3−​, Be forms three sigma bonds with three flourines.

So, hybridisation of Be becomes sp2. 

Hence, the correct answer is option A.

EmSAT Chemistry Mock Test- 1 - Question 15
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The correct increasing bond angle among ,  and 
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 15

BF3​is trigonal planar which makes the angle as 120 degree.PF3​ is trigonal bipyramidal making the angle slightly less than 109 degrees ClF3​ is T-shaped making the least angle.

EmSAT Chemistry Mock Test- 1 - Question 16
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Calculated bond order in the superoxide () ion is 
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 16
O2^- (superoxide) = 13 valence e⁻. = σs(2 e⁻) σs*(2e⁻) σp(2e⁻) πp(4e⁻) πp*(3e⁻) σp*(0) . bond order = ½[ σs(2e⁻) σp(2e⁻) πp(4 e⁻) - σs*(2e⁻) πp*(3e⁻) ]. = ½[8-5] = 1.5
EmSAT Chemistry Mock Test- 1 - Question 17
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The ionic species having largest size is
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 17


Li+ ion being smallest in size is heavily hydrated and thus Li+(aq) is largest in size.

EmSAT Chemistry Mock Test- 1 - Question 18
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From which of the following species it is easiest to remove one electron ?
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 18

Energy is released when an electron is added to the atom. Hence 1st electron affinity (EA1​) is always taken as negative. The addition of second electron to the negativity charged ions is opposed by Coulombic repulsion, hence energy has to be supplied for the addition of second electron. Hence (EA2​) is taken as positive. 

 

Addition of an electron to F− and O− ions will involve repulsions, hence their (EA2​) will be positive.
Due to stable fully filled configuration of Na+ (1s2 2s2 2p6) it has lower value of electron affinity than O. Hence O has highest electron affinity.

EmSAT Chemistry Mock Test- 1 - Question 19
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With respect to chlorine, hydrogen will be
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 19
With respect to Chlorine, hydrogen will be electropositive.

Reason:

Chlorine being a strong electronegative element tends to force hydrogen to lose electron and hydrogen acquire electropositive character so that chlorine can complete its octet. 

EmSAT Chemistry Mock Test- 1 - Question 20
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Which element has the greatest tendency to lose electrons ?
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 20
Fe has high electronegativity. it is a metal and it has proper to lose electron
*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 1 - Question 21
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0.01 mole of iodoform (CHI3) reacts with Ag to produce a gas whose volume at NTP in ml is :-
2CHI3 + 6Ag —→ 6AgI(s) + C2H2(g)

Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 21

mol of C2H2 = 1/2 × mol of CHI3
= 1/2 × 0.01 = 0.005
volume at N.T.P. = 0.005 × 22400 = 112 ml

*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 1 - Question 22
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Sum of σ and π bonds are present in CH3COOH?

Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 22

Single bond is σ bond and double bond contains 1σ and 1 π bond. Therefore, it contains 7 σ and 1 π bond. Hence, total is 8

*Answer can only contain numeric values
EmSAT Chemistry Mock Test- 1 - Question 23
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How many maximum electrons can be accomodate in 7th shell of element X?

Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 23

Maximum number of electron in a shell
= 2n2
= 2(7)2
= 98

EmSAT Chemistry Mock Test- 1 - Question 24
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Which of the following alkenes will react fastest with  under catalytic hydrogenation conditions
EmSAT Chemistry Mock Test- 1 - Question 25
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The heat of hydrogenation of 1-hexene is 126 . When a second double bond is introduced in the molecule, the heat of hydrogenation of the resulting compound is 230  . The resulting compound (diene) is
Detailed Solution for EmSAT Chemistry Mock Test- 1 - Question 25
The Diene thus formed is more stable than the initial compound (and rest of the options) due to conjugation (a conjugated diene). Hence the heat of hydrogenation is more as the product will be a thermodynamically controlled one ie a TCP.
EmSAT Chemistry Mock Test- 1 - Question 26
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Heat of hydrogenation of benzene is 51 kcal/mol and its resonance energy is 36 kcal/mol. Then the heats of hydrogenation of cyclohexadiene and cyclohexene per mole respectively are
EmSAT Chemistry Mock Test- 1 - Question 27
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 is adsorbed on palladium surface.It is a case of
EmSAT Chemistry Mock Test- 1 - Question 28
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The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is
EmSAT Chemistry Mock Test- 1 - Question 29
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When 0.532 g of benzene (B.P.  C) is burnt in a constant volume system with an excess of oxygen, 22.3 KJ of heat is given out.  for the combustion process is given by :
EmSAT Chemistry Mock Test- 1 - Question 30
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The heat released when  & HCl neutralize is :
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