Pipes And Cistern - MCQ 3 - GMAT MCQ

# Pipes And Cistern - MCQ 3 - GMAT MCQ

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## 20 Questions MCQ Test Quantitative for GMAT - Pipes And Cistern - MCQ 3

Pipes And Cistern - MCQ 3 for GMAT 2024 is part of Quantitative for GMAT preparation. The Pipes And Cistern - MCQ 3 questions and answers have been prepared according to the GMAT exam syllabus.The Pipes And Cistern - MCQ 3 MCQs are made for GMAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Pipes And Cistern - MCQ 3 below.
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Pipes And Cistern - MCQ 3 - Question 1

### Two pipes A and B can fill a tank in 10 hours and 15 hours respectively while a third pipe C can empty the full tank in 20 hours. All the pipes are opened for 5 hours and then C is closed. Find the time in which the tank is full?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 1

(1/10 + 1/15 – 1/20)*5 + (1/10 + 1/15)*T = 1. We will get T = 2.5 hrs
so total time = 5 + 2.5 = 7.5 hrs

Pipes And Cistern - MCQ 3 - Question 2

### Three pipe P, Q and R can fill a tank in 12 minutes, 18 minutes and 24 minutes respectively. The pipe R is closed 12 minutes before the tank is filled. In what time the tank is full?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 2

Let T is the time taken by the pipes to fill the tank
(1/12 + 1/18 + 1/24)*(T – 12) + (1/12 + 1/18)*12 = 1
We will get T = 108/13 = 8.(4/13) hrs

Pipes And Cistern - MCQ 3 - Question 3

### On pipe P is 4 times faster than pipe Q and takes 45 minutes less than pipe Q. In what time the cistern is full if both the pipes are opened together?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 3

Let P takes x minutes to fill the tank alone, then Q will take 4x minutes to fill the tank
4x – x = 45, x = 15
So P will take 15 minutes and Q will take 60 minutes to fill the tank. Both will fill the tank in
(60*15)/(75) = 12 minutes

Pipes And Cistern - MCQ 3 - Question 4

Two pipes can fill a tank in 15 and 20 hours respectively. The pipes are opened simultaneously and it is found that due to the leakage in the bottom, 17/7 hours extra are taken extra to fill the tank. If the tank is full, in what approximate time would the leak empty it?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 4

Total time taken by both pipes before the leak was developed = 60/7 hours now, leaks is developed which will take T time to empty the tank so, (1/15 +1/20 – 1/T) = 1/11
solve for T, we will get 660/17 hours = 39 hours (approx.)

Pipes And Cistern - MCQ 3 - Question 5

Two pipes A and B can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are openedsimultaneously, after what time should B be closed so that the tank is full in 6 minutes?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 5

Let after x minutes pipe B is closed
(1/8 + 1/12)*x + (1/8)*(6 -x) = 1
X= 3 minutes

Pipes And Cistern - MCQ 3 - Question 6

In what time would a cistern be filled by three pipes whose diameters are 1cm, 2 cm and 3 cm running together, when the largest pipe alone can fill the tank in 21 minutes? The amount of water flowing through the pipe is directly proportional to the square of its diameter.

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 6

More the diameter more will be the water flowing through it and less will be the time taken.
Means bigger pipe will take less time to fill the tank
So, for 1 cm time, (12)/(32) = 21/t, we get t = 189
For 2 cm time, (22)/(32) = 21/t. We get t = 189/4
So total time = 1/21 + 1/189 + 4/189 = 2/27
So total time = 13.5 minutes

Pipes And Cistern - MCQ 3 - Question 7

Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 7

Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr

Pipes And Cistern - MCQ 3 - Question 8

One pipe fill 1/4 of the tank in 4 minutes and another pipe fills 1/5 of the tank in 4 minutes. Find the time taken by both pipe together to fill half the tank?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 8

First pipe will take 16 minutes to fill the tank alone. Similarly second pipe will take 20 minutes to fill the tank alone. Let T is the time in which both the pipes will fill half the tank
(1/16 + 1/20)*T = 1/2, we get T = 40/9 minutes

Pipes And Cistern - MCQ 3 - Question 9

Two pipes can separately fill the tank in 15hrs and 30hrs respectively. Both the pipe are opened and when the tank is 1/3 full a leak is developed due to which 1/3 water supplied by the pipe leaks out. What is the total time to fill the tank?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 9

(1/15 + 1/30)*T1 = 1/3, T1 = 10/3 hr
Now after leak is developed, [(1/15 + 1/30) – (1/3)*(1/15 + 1/30)]*T2 = 2/3
T2 = 10 hr. So total time = 10 + 10/3 = 40/3 hr

Pipes And Cistern - MCQ 3 - Question 10

Three pipes A, B and C is attached to a cistern. A can fill it in 20 minutes and B can fill it in 30 minutes. C is a waste pipe. After opening both the pipes A and B, Riya leaves the cistern to fill and returns when the cistern is supposed to be filled. But she found that waste pipe C had been left open, she closes it and now the cistern takes 5 minutes more to fill. In how much time the pipe C can empty the full cistern?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 10

The tank supposed to be filled in (30*20)/50 = 12 minutes
so, (1/20 + 1/30)*12 – 12/C + (1/20 + 1/30)*5 = 1 (A and B work for 12 minutes and also C work for 12 minutes and then A and B takes 5 more minutes to fill the tank)
solve for C, we will get C = 144/5 = 28.8

Pipes And Cistern - MCQ 3 - Question 11

A pipe can empty a tank in 60 minutes alone. Another pipe whose diameter is twice the diameter of first pipe is also opened. Now find the time in which both pipe will empty the tank together.

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 11

Time taken by pipe to empty the tank is inversely proportional to cross- sectional area.
So, time taken by second pipe will be = 60/4 = 15 min (πr2 = 1/60 and for second pipe 4πr2 = 1/T so we get T = 15 min)
Time taken by both to empty the pipe = (60*15)/75 = 12

Pipes And Cistern - MCQ 3 - Question 12

Two pipes P and Q can fill a tank in 10 min and 12 min respectively and a waste pipe can carry off 12 litres of water per minute. If all the pipes are opened when the tank is full and it takes one hour to empty the tank. Find the capacity of the tank.

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 12

Let the waste pipe take ‘T’ time to empty the tank.
(1/10 + 1/12 – 1/T)*60 = -1
We will get T = 5 min
So capacity = 5*12 = 60ltr

Pipes And Cistern - MCQ 3 - Question 13

Two pipes P and Q can fill a tank in 36 and 24 minutes respectively. If both the pipes are opened simultaneously, after how much time pipe Q should be closed so that tank is full in 30 minutes.

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 13

Let after T time, Q is closed, (1/36 + 1/24)*T + (1/36)*(30 – T) = 1

Pipes And Cistern - MCQ 3 - Question 14

Two pipes A and B can fill a tank in 20 and 30 minutes respectively. Both the pipes are opened together but after 5 minutes pipe B is closed. What is the total time required to fill the tank

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 14

(1/20 + 1/30)*5 + (1/20)*T = 1
total time = T + 5 min

Pipes And Cistern - MCQ 3 - Question 15

Three pipes P, Q and R can fill a tank in 12, 15 and 20 minutes respectively. If pipe P is opened all the time and pipe Q and R are opened for one hour alternatively. The tank will be full in

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 15

(1/12 + 1/15) + (1/12 + 1/20) = 17/60 (in 2 hrs this much tank is filled)
so in 6 hrs 51/60 is filled. Remaining, 9/60 = (1/12 + 1/15)*t,
so T = 1hr so total = 6 + 1 = 7 hr

Pipes And Cistern - MCQ 3 - Question 16

A cistern can be filled by a pipe in 6 hours. A leak is developed at the bottom due to which it takes 2 hours more to fill the cistern. Find the time taken by the leak to empty the cistern when the cistern is full.

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 16

1/6 – 1/T = 1/8, solve for T

Pipes And Cistern - MCQ 3 - Question 17

A pipe can fill a tank in 20 minutes and another pipe can fill the tank in 40 minutes. There is a waste pipe which can empty the tank in 15 minutes. First two pipes are opened for 5 minutes and then the third pipe is also opened. In what time the cistern is emptied after the third pipe also opened

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 17

(1/20 + 1/40)*5 + (1/20 + 1/40 – 1/15)*T = 1

Pipes And Cistern - MCQ 3 - Question 18

Two pipes can separately fill the tank in 15hrs and 30hrs respectively. Both the pipe are opened and when the tank is 1/3 full a leak is developed due to which 1/3 water supplied by the pipe leaks out. What is the total time to fill the tank?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 18

(1/15 + 1/30)*T1 = 1/3, T1 = 10/3 hr
now after leak is developed, [(1/15 + 1/30) – (1/3)*(1/15 + 1/30)]*T2 = 2/3
T2 = 10 hr. So total time = 10 + 10/3 = 40/3 hr

Pipes And Cistern - MCQ 3 - Question 19

Pipe P is 4 times as fast as Q in filling a tank. If P takes 20 minutes to fill a tank, then what is the time taken by both the pipe P and Q to fill the tank?

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 19

P takes 20 minutes and it is 4 times faster than Q, it means Q will take 80 minutes to fill the tank.
(1/20 + 1/80)*t = 1. We get t = 16

Pipes And Cistern - MCQ 3 - Question 20

In what time a cistern is filled by three pipes of diameter 2cm, 4cm and 6cm respectively. If the time taken by largest pipe to fill the tank is 40 minutes. Amount of water flowing through the pipe is proportional to the diameter of the pipe

Detailed Solution for Pipes And Cistern - MCQ 3 - Question 20

Larger the cross-section area less will be time taken by pipe to fill the tank. 36/16 = T/40, T = 90min (for 4 cm pipe)
similarly for 2 cm pipe time taken will be = 360min
Total time = (1/360 + 1/90 + 1/40) = 1/p, so we get P = 25.5/7 minutes

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