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Test: Distance And Speed- 1 - GMAT MCQ


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15 Questions MCQ Test Quantitative for GMAT - Test: Distance And Speed- 1

Test: Distance And Speed- 1 for GMAT 2024 is part of Quantitative for GMAT preparation. The Test: Distance And Speed- 1 questions and answers have been prepared according to the GMAT exam syllabus.The Test: Distance And Speed- 1 MCQs are made for GMAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Distance And Speed- 1 below.
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Test: Distance And Speed- 1 - Question 1

Alice, while driving to her workplace completes an initial distance of 50 miles in 2 hours and remaining 60 miles in 3 hours. What is the average speed in miles per hour for her entire journey?

Detailed Solution for Test: Distance And Speed- 1 - Question 1

Average speed :-

Total distance / Total time

⇒ (50+60) miles / (2+3) hours

⇒ 110/ 5  

⇒ 22 miles / hour

Test: Distance And Speed- 1 - Question 2

Alice travels at an average speed of 60miles per hour from her home to a grocery store. She travels back to her home via same route at an average speed of 80 miles per hour. What is the average speed of her entire journey?

Detailed Solution for Test: Distance And Speed- 1 - Question 2

2xaxb
  a+b
2x60x80
  60+80
2x6x80
    14
480
  7
so (b) option

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Test: Distance And Speed- 1 - Question 3

Alan starts his journey from point A at sharp 10.00am. He drives at an average speed of 30 miles per hour and reaches Point B at 11.00 am. Bob starts his journey 15 mins after Alan started his journey and travels via same route as Alan did. If Alan and Bob both reached point B exactly at the same time, then what is Bob’s average speed (in miles per hour)?

Detailed Solution for Test: Distance And Speed- 1 - Question 3

Solution:

- Alan's Journey:
- Alan started at 10.00am and reached Point B at 11.00am, so the total time taken by Alan = 1 hour.
- Alan's average speed = 30 miles per hour.
- Therefore, the distance between Point A and Point B = 30 miles (as distance = speed * time).

- Bob's Journey:
- Bob started 15 minutes (or 0.25 hours) after Alan started his journey.
- Bob travels the same route as Alan, so the distance between Point A and Point B is the same for Bob.
- Bob reaches Point B at the same time as Alan, so Bob takes 45 minutes (or 0.75 hours) to cover the distance.
- Let Bob's average speed be x miles per hour, then the distance between Point A and Point B = x * 0.75.

- Equating the distances:
- As the distance between Point A and Point B is the same for both Alan and Bob:
- 30 = x * 0.75
- x = 30 / 0.75
- x = 40 miles per hour.

Therefore, Bob's average speed is 40 miles per hour, which matches option E.

Test: Distance And Speed- 1 - Question 4

A speed boat travels at a speed of x miles per hour in still water. With a favourable current, the speed boat travels downstream and reaches its destination in 2.5 hours. The speedboat travels back upstream against the current and covers the same distance in 3.5 hours.  If the speed of the current is 1mph, then what is the value of x?

Detailed Solution for Test: Distance And Speed- 1 - Question 4

Solution:

  • Let the speed of the boat in still water be x mph and the speed of the current be 1 mph.
  • When the boat travels downstream with the current, the effective speed is (x + 1) mph. The time taken to reach the destination is 2.5 hours.
  • When the boat travels upstream against the current, the effective speed is (x - 1) mph. The time taken to cover the same distance is 3.5 hours.

We can use the formula: Distance = Speed * Time

  • Distance downstream = (x + 1) * 2.5 = 2.5x + 2.5
  • Distance upstream = (x - 1) * 3.5 = 3.5x - 3.5
  • Since the distances covered in both directions are the same, we can equate the two expressions:
    2.5x + 2.5 = 3.5x - 3.5

Solving for x:
2.5 + 3.5 = 3.5x - 2.5x
6 = 1.0x
x = 6
Therefore, the speed of the boat in still water is 6 mph, which corresponds to option D.

Test: Distance And Speed- 1 - Question 5

During a trip, Charles covered the first part of a certain distance at an average speed of 30 miles per hour and the remaining part at an average speed of 50 miles per hour. If the ratio of time taken to cover the first part and remaining part is 2: 3, then what is the total distance that Charles travelled?

(1) It took a total of 5 hours to complete the entire distance.

(2) 2/7th of the entire distance was covered during the first part

Detailed Solution for Test: Distance And Speed- 1 - Question 5

Solution:

Statement 1: It took a total of 5 hours to complete the entire distance.

- Let the total distance be D miles.
- Let the time taken to cover the first part be 2x hours and the time taken to cover the remaining part be 3x hours.
- Using the formula Distance = Speed x Time, we can write the equations:
- Distance covered in the first part = 30 * 2x = 60x
- Distance covered in the remaining part = 50 * 3x = 150x
- Total distance = 60x + 150x = 210x

- We are given that the total time taken is 5 hours, so:
- 2x + 3x = 5
- 5x = 5
- x = 1

- Therefore, the total distance D = 210x = 210 * 1 = 210 miles.

Statement 2: 2/7th of the entire distance was covered during the first part.

- Let the total distance be D miles.
- According to the statement, the distance covered in the first part = 2/7 * D
- Therefore, the distance covered in the remaining part = D - 2/7 * D = 5/7 * D

- However, this information alone does not provide us with enough information to determine the total distance that Charles travelled.

Conclusion: Statement (1) alone is sufficient to answer the question, but statement (2) alone is not sufficient. Therefore, the correct answer is A.

Test: Distance And Speed- 1 - Question 6

Two dogs are running towards each other from opposite ends of a two-mile track. Dog 1 has a speed of 12 mph and Dog 2 has a speed of 8 mph. How many miles from Dog 1’s starting position will they meet?

Detailed Solution for Test: Distance And Speed- 1 - Question 6

Step 1: Question statement and Inferences

Let the two dogs meet at a distance of x miles from the Starting position of Dog 1.

So, Dog 1 covers a distance of x miles at a speed of 12 mph to reach the meeting point.

In the same time, Dog 2 covers a distance of (2-x) miles at a speed of 8 mph to reach the meeting point

Step 2: Finding required values

We know that

 

Since the time taken by Dog 1 to reach the meeting point is equal to the time taken by Dog 2 to reach the meeting point, we can write:

 

 

The dogs will meet 6/5 miles from Dog 1’s starting position.

Answer: Option (B)

Test: Distance And Speed- 1 - Question 7

Riding her bicycle downhill, Sam reached the bottom of the 10-mile trail 10 minutes faster than it took her, riding 12 miles per hour, to reach the top of the trail. What was her downhill speed? 

Detailed Solution for Test: Distance And Speed- 1 - Question 7

Step 1: Question statement and Inferences

Riding 10 miles at her new speed took Sam 10 minutes less than riding the same distance at 12 miles per hour. What was this new speed?

Step 2: Finding required values

Start by finding the time it took Sam to reach the top of the hill.

Her uphill speed, u = 12 miles per hour

Distance travelled = 10 miles

Now considering the downhill journey,

Step 3: Calculating the final answer

Answer: Option (B)

Test: Distance And Speed- 1 - Question 8

Johnny drove with an average speed of m miles per hour for h hours, increased his average speed to m + s miles per hour for an additional h hour and then increased his average speed to twice the original speed for a final h hours. Which of the following represents the distance which he drove? 

Detailed Solution for Test: Distance And Speed- 1 - Question 8

Step 1: Question statement and Inferences

Johnny drove three segments for h hours each. His speeds were m, m + s, and 2m. The question asks for the representation of the distance which he drove. 

We know that

 

Step 2: Finding required values

Multiply the time driven, h for each segment, by the speed driven for that segment, to get distances. These are hm, h(m + s), and 2hm, respectively.

Step 3: Calculating the final answer

The total distance traveled is hm + h(m + s) + 2hm, which factors out to h(4m +s). 

Answer: Option (B)

Test: Distance And Speed- 1 - Question 9

Emily rode x miles from her home at a speed of p miles per hour before running out of fuel.  She then walked her motorcycle at 8 meters per minute till a few miles further before she met her friend. Emily’s friend dropped her back home, driving along the same route at a rate that was 50% greater than Emily’s riding speed for x miles. If the total journey took t hours, how many miles did Emily walk her motorcycle for? (Given : 1000 meters = 0.62 miles)

Detailed Solution for Test: Distance And Speed- 1 - Question 9

Given:

Let’s call Emily’s journey from her home till she meets her friend as her “Forward Journey” and her journey from when she meets her friend  till her home as her “Return Journey”

 

Forward Journey

  • Home to “Ran out of fuel” point
    • Distance travelled = x miles
    • Driving speed = p miles per hour
    • Let the time taken be t1 hours.
  • “Ran out of fuel” point till she meets her friend
    • Speed of walking= 8 meters per minute
    • Let the distance covered be y miles
    • Let the time taken while walking = t2 hours.
  • Total distance covered in Forward Journey = (x + y) miles

Return Journey

  • From when Emily meets her friend to Home
    • Total distance travelled = (x + y) miles
      • Distance in forward journey = Distance covered in return journey
    • Speed of driving = 50% more than p miles per hour
    • Let the total time taken for the return journey be t3 hours.

 

So our DST table would look like this:

*(t+ t+ t3) = t hours

To Find: How many miles she has walked her motorcycle = y = ?

Linkages

  1. To find the value of y, let’s focus on the Home to “Ran out of fuel” point row of the DST table.
    1. To calculate the value of y from here, we need to know the speed and the time, but t2 is unknown to us.
  2. We observe that t2 is also present in the equation of time (t+ t+ t3) = t hours
    1. To calculate t2 we need the value of t1 and t3.
  3. We observe that t3 is present in the “Emily meets her friend to home row” of the DST table.
    1. From here we can express t3 in terms of x, y and p.
  4. We observe that t1 is present in the Home to “Ran out of fuel” point row of the DST table.
    1. From here we can express t1 in terms of x and p.
  5. So we will have 4 equations and 4 variables, and thus we will be able to find the value of y.

Approach

  1. From the “Emily meets her friend to home” row of the DST table, we will get t3
  •  in terms of x , y and p.
  • From home to “Ran out of fuel” point row of the DST table, we will get t1
  •  in terms of x and p.
  • From “Ran out of fuel point to Emily meets her friend” row of the DST table, we will get t2
  •  in terms of y.
  • Putting values of t1, t2 and t3 in the equation (t+ t+ t3) = t hours, we will be able to find the value of unknown i.e. p.

Calculation

  1. From the “Emily meets her friend to home” row of the DST table, we will get t3  in terms of x , y and p.

2. From home to “Ran out of fuel” point row of the DST table, we will get t1 in terms of x and p.

3. From “Emily “meets her friend” to home  row of the DST table, we will get t2 in terms of y.

  1. Speed = 8 meters per minute
    1. Here speed is given to us in different units
    2. Making the units consistent
    3. Speed =

4. (t+ t+ t3) = t hours

  1. Putting values of t1, t2 and t3, we have

  • To get rid of  the variable 'p' in the denominator multiply both sides of the equation with 'p'
  • So, we get :

To get rid of the decimal in the denominator multiply both sides of the equation by 1/10

  • LCM (15,10, 3) = 30
  • Multiplying both sides of the equation by 30, we get :

Correct Answer: Option D

Test: Distance And Speed- 1 - Question 10

To reach her office from her home, Karen traveled x miles at a speed of y miles per hour. On her way back, via the same route, she travels for ten miles before stopping for an hour. If Karen drove at y miles per hour till she stopped, by what percentage should she increase her speed so that the overall time taken to reach back home from the office is the same as that taken to reach the office from home?

Detailed Solution for Test: Distance And Speed- 1 - Question 10

In GMAT questions like this one, relying solely on an algebraic approach can slow you down. The most efficient method to solve this within 2 minutes is to use simple values for the unknowns.

Let's assume x=100x = 100x=100 miles and y=10y = 10y=10 miles per hour. This means Karen takes 10 hours to travel from her home to her office.

For her return trip, she travels 10 miles at the same speed, taking 1 hour. After stopping for an hour, she has 8 hours left to travel the remaining 90 miles (since the total travel time needs to match the 10 hours taken to reach the office). Therefore, she must travel the remaining 90 miles at an average speed of 90/8= 11.25 miles per hour.

Comparing this new speed to her original speed of 10 miles per hour, the percentage increase in speed is 
(11.25−10​)/10 * 100 =12.5%
 Now, we need to find the option that matches this percentage increase.

Looking at the options, we notice that the denominator is either x−y−10 or y−x−10. Since y is less than x, y−x−10 would be negative. Since we need a percentage increase (a positive value), we can eliminate options with y−x−10 as the denominator. Thus, options C, D, and E are eliminated, leaving us with A and B.

Option A has a much larger numerator, making it an unlikely percentage increase. Substituting x=100 and y=10 into option B:

100y/ (x-y-10) = 100 *10 /100-10-10 = 1000/80 =12.5 

This matches our required percentage increase, allowing us to rule out option A. Therefore, the correct answer is B.

Test: Distance And Speed- 1 - Question 11

Jonathan drove from City A to City B at a rate of 1.2 minutes per kilometer. He then drove back to City A from City B , along the same route, at 1 minute per kilometer. If he took anywhere between 3 hours to 5 hours to travel from City A to City B and between 2 hours to 3 hours on his way back, what could be the distance between the two cities?

Detailed Solution for Test: Distance And Speed- 1 - Question 11

Explanation:
A to B

  • Speed = 1.2 min/km (note that the speed is not in usual distance/time format)
  • Time = 3hrs to 5hrs = 180mins to 300mins
  • Therefore, Distance =Time/Speed =180/1.2 to 300/1.2=150km to 250km

B to A

  • Speed = 1 min/km (note that the speed is not in usual distance/time format)
  • Time = 2hrs to 3hrs = 120mins to 180mins
  • Therefore, Distance =Time/Speed =120/1to180/1=120km to 180km

    Based on both the above ranges, the only possible distance, among the options, is 160km
Test: Distance And Speed- 1 - Question 12

Phil drives east from his home for 2 hours before realizing that he will run out of fuel in another 70 miles. Nevertheless, he drives for another 10 miles east before returning back home via the same route. If he drives at a constant speed throughout his journey and returns home with fuel left for another 10 miles, how much time does he take for his journey eastwards?

Detailed Solution for Test: Distance And Speed- 1 - Question 12

Solution:

Given:
- Phil drives east from his home for 2 hours before realizing he will run out of fuel in another 70 miles.
- He drives for another 10 miles east before returning back home via the same route.
- Phil returns home with fuel left for another 10 miles.

To find:
- The total time Phil takes for his journey eastwards.

Explanation:
- When Phil realizes he will run out of fuel in 70 miles, he has already driven for 2 hours.
- This means that he can drive for another 70 miles in 2 hours.
- After driving another 10 miles east, he returns home with fuel left for another 10 miles.
- Therefore, the total distance Phil covered in one direction is 70 + 10 = 80 miles.
- Since Phil drives at a constant speed throughout his journey, we can assume that his speed is constant.
- Time = Distance / Speed
- Time taken to cover 80 miles = 2 hours
- Therefore, the time Phil takes for his journey eastwards is 2 hours to drive 80 miles.

Conclusion:
- Phil takes 2.5 hours for his journey eastwards. (Option B)

Test: Distance And Speed- 1 - Question 13

Every day, Tom walks from his home to his office, via the same route, covering s feet at a speed of x feet per minute. Today he took a different route and ended up walking 10% more than he usually does, at a speed that was 100 meters per minute faster than his usual speed. What is the percentage change in the time he took today compared to the time he takes on a usual day? (1 feet =0.3 meter)  

Detailed Solution for Test: Distance And Speed- 1 - Question 13

Let’s let m = the time, in minutes, that it takes Tom to walk s feet at a rate of x ft/min. Thus, we have the following distance equation for Tom’s usual day:
x * m = s
m = s/x
Tom’s rate today - x meters/min - is equivalent to x/0.3 ft/min, and we use this value in his distance equation for today. Letting n = the time, in minutes, that it takes him to walk 10% more distance than normal (1.1s feet) at a rate of x/0.3 ft/min, we have today’s equation as:
x/0.3 * n = 1.1s
n = 1.1s / (x/0.3)
n = 0.33s/x
To determine the percent change in the time it takes him today, compared to his usual time, we use the percent change formula (New - Old)/Old * 100:
(0.33s/x - s/x) / (s/x) *100
(0.33s - s)/s *100
(0.33 - 1)/1 *100 = - 67 percent
Thus, today, Tom took 67% less time than on a usual day.

Test: Distance And Speed- 1 - Question 14

A train takes two hours to travel from one station to the other. What is the distance between the two stations?

    (1) The train covers one third of the total distance in the first hour at an average speed of 80 mph.

    (2) The average speed during the second hour is 160 mph. 

Detailed Solution for Test: Distance And Speed- 1 - Question 14

Analysis:

- From the question, we know that the train takes 2 hours to travel from one station to the other.
- We need to find the distance between the two stations.

Statement 1:
- The train covers one third of the total distance in the first hour at an average speed of 80 mph.
- Since the train covers one third of the total distance in the first hour, it covers the remaining two thirds of the distance in the second hour.
- Therefore, using the information from statement 1 alone, we can calculate the total distance.
- This statement alone is sufficient to answer the question.

Statement 2:
- The average speed during the second hour is 160 mph.
- This statement alone does not provide information on the distance or the time taken in the first hour.
- Therefore, statement 2 alone is not sufficient to answer the question.

Conclusion:
- Statement 1 alone is sufficient to answer the question.
- The correct answer is option A: Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Test: Distance And Speed- 1 - Question 15

A man rows at the rate of 5 mph in still water. If the river runs at the rate of 1 mph, it takes him 1 hour to row to a place and come back. What is the total distance covered by him in miles?

Detailed Solution for Test: Distance And Speed- 1 - Question 15

Correct Answer :- e

Explanation : Speed downstream = (5 + 1) kmph = 6 mph.

Speed upstream = (5 - 1) kmph = 4 mph.

Let the required distance be x m.

Then,   x/6 + x/4 = 1

 2x + 3x = 12

 5x = 12

 x = 2.4 

Therefore, the total distance covered is 2 * 2.4 = 4.8 miles.

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