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Test: Quantitative Aptitude- 4 - GMAT MCQ


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21 Questions MCQ Test Quantitative for GMAT - Test: Quantitative Aptitude- 4

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Test: Quantitative Aptitude- 4 - Question 1

In a Christmas sale, the prices of Dell Laptops were reduced by 10% for public. However, for Dell employees, the price was further reduced by 5%. If the original price of a laptop was $330 before Christmas sale, approximately how much would it cost in a Christmas sale to a Dell employee?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 1
  • Original Price = $330
  • Price after 10% discount= 330 * 0.9 = $297
  • Price after further 5% discount (for Dell employees) = 297* 0.95 = $282.
  • Therefore, Option C.
Test: Quantitative Aptitude- 4 - Question 2

Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. What must he add to make the proportions of the mixture correct?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 2
  • We note that the final ratio must be 3:2 for milk and water respectively.
  • Now, according to given scenario in the question, we have eight liters of solution with 4 liters milk and 4 liters water, which makes it 2:2.
  • In order to make it 3:2, we add 2 liters milk.
  • This would make a total of 6 liters milk and 4 liters water i.e. 6:4
  • which can be simplified to 3:2.
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Test: Quantitative Aptitude- 4 - Question 3

Alan has two more than twice as many chocolates as does Alice, and half as many chocolates as does Nadia. If Alice has ‘a’ number of chocolates, then in terms of ‘a’, how many chocolates do Alan, Alice and Nadia have?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 3
  • We know that Alice has 'a' chocolates.
  • Alan has 2a+2 chocolates from the given statement in the question.
  • Nadia has double the chocolates as Alan has, so she has 4a+4 chocolates.
  • Adding these, we get 4a+4+2a+2+a = 7a +6 .
  • So ,Option (d) is correct.
Test: Quantitative Aptitude- 4 - Question 4

Adam is 2 years older than Mike. The square of Adam’s age is 28 greater than the square of Mike’s age in years. What is the sum of Adam’s age and Mike’s age?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 4
  • Let suppose that Adam's age is 'A', and Mike's age is 'M'.
  • From the statement of the questions, we deduce following two equations.
  • A = 2+M and also A2= M2+28 -> A2 - M2 = 28  
  • (A+M)(A-M)=28 and then putting
  • A-M=2, we get (A+M) = 14.
  • Therefore, the sum of Adam's age and Mike's age is 14.
Test: Quantitative Aptitude- 4 - Question 5

If the product of two integers x and y is less than 82 with y being a multiple of three. What is the highest value that x may have?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 5
  • In order to find the maximum value of x, we need to put the minimum value of y i.e. 3.
  • Now, if we divide 82 by 3, we get 27.33, which means the maximum integer value that x can have must be less than 27.33.
  • From the given options, we choose option C which is 27.
Test: Quantitative Aptitude- 4 - Question 6

A group wanted to renovate their club. Each member contributed an amount equal to twice the number of members in the club. But the government contributed same amount as the number of members. If each member had contributed the same amount as the number of members and the government had given an amount twice the number of members, then they would have Rs. 210 less. How many members are there?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 6

Test: Quantitative Aptitude- 4 - Question 7

If Dave drove one-third of the distance of his trip on the first day, and 60 miles on the second day, he figured out that he still had 1/2 of the trip to drive. What was the total length, in miles, of his trip?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 7

We can model this situation by the equation 1/3x + 60 = 1/2x .

Solving for x, we get x=360 , which is answer A.

 

Test: Quantitative Aptitude- 4 - Question 8

If x2 - y2 = 48, the 2/3(x+y)(x-y) = 

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 8
  • We know that  (x2-y2) = (x+y)(x-y) = 48
  • 2/3(x-y)(x+y) = 2/3 (x2-y2) = 2/3 x 48 = 32
Test: Quantitative Aptitude- 4 - Question 9

Eddie is 7 years older than Brian. If Brian is x years old, then how old was Eddie 11 years ago?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 9

We can model this by getting Eddie’s age now and then figuring out how old he was 11 years ago.
Right now, he is x+7 .
Eleven years ago, Eddie was x + 7 -11 = x - 4 years old.
This is answer B.
 

Test: Quantitative Aptitude- 4 - Question 10

Adam has bought a certain number of apples. Jen has bought 5 times the fruit that Adam has bought. If Jen has bought two and a half dozen apples how many apples does Adam have?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 10

It's a relatively simple question. Jen has five times the number of apples which Adam has. If Jen has 30 apples, Adam has 30/5=6 apples.

Test: Quantitative Aptitude- 4 - Question 11

A house is built by 20 workers in 30 days. How many workers will be needed to complete the work in 15 days?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 11

As stated in the question, the work needs to be completed in half the days as compared to the earlier timeline for completion, therefore, the number the workers needs to be doubled.

Test: Quantitative Aptitude- 4 - Question 12

A code is to be made by arranging 7 letters. Three of the letters used will be the letter A, two of the letters used will be the letter B, one of the letters used will be the letter C, and one of the letters used will be the letter D. If there is only one way to present each letter, how many different codes are possible?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 12

Step 1: Analyze the Question :- We have to make a seven-letter code, but some of our letters are repeated. We have three As two Bs, one C, and one D. We have to calculate the possible number of different codes.

Step 2: State the Task :- We'll calculate the number of permutations, remembering to take the repeated letters into account.

Step 3: Approach Strategically :- To calculate the number of permutations where some of the elements are indistinguishable, we'll divide the total number of permutations by the factorial of the number of indistinguishable elements.

So we have :- 

Test: Quantitative Aptitude- 4 - Question 13

If x is an integer and 2.134 x 10x is less than 210,000, what is the greatest possible value for x?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 13

Step 1: Analyze the Question
We know two things about x: it's an integer, and 2.134 x 10% < 210,000. 

Step 2: State the Task
Find the greatest possible value for X. 

Step 3: Approach Strategically
To multiply a decimal quantity by 10%, move the decimal point x places to the right. For 2.134, moving the decimal point 5 places to the right results in the number 213,400. That's just over the limit of 210,000, so the maximum value of x is 4. The correct answer is (D). 

Step 4: Confirm Your Answer
A great way to confirm the answer on this type of question is to write the number down on your noteboard before counting the number of decimal places to move.

Test: Quantitative Aptitude- 4 - Question 14

John spent 40 percent of his earnings last month on rent and 30 percent less than what he spent on rent to purchase a new dishwasher. What percent of last month's earnings did John have left over?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 14

Step 1: Analyze the Question 
John spends 40% on one thing and 30% less than that on another. Since the answer choices are percents, picking 100 is a good idea. Some answer choices are widely spread out. When choices are spread out, estimation and logic are also great approaches. 

Step 2: State the Task 
What percent of last month's earnings did John have left over? We now know that we'd pick $100 as his earnings. (We care much more about picking manageable numbers than about giving imaginary people a living wage.) It's also important to focus on the fact that we are solving for what he has left after paying for rent and the dishwasher, not what he spent on those things. 

Step 3: Approach Strategically 
Some answer choices could be logically eliminated right away. After spending 40% of his earnings on rent, he'd have 60% left. Then he spends some more. Therefore, no answer 60% or greater could be possible. That eliminates (D) and (E) very quickly. And since simple combinations of percents are rarely the right answer, the odds of the right answer being “subtract 40% and then subtract 30%" are very small. That makes 100% - 40% - 30% = 30%, choice (A), a safe elimination as well. We could make a 50/50 guess very quickly on this problem, which is sometimes a good thing to do if you are falling behind pace. But let's say that you had the time to solve. Picking $100 for his earnings, we see that John spends $40 on rent. He spends 30% less than $40 on a dishwasher; “30% less than something” is the same as “90% of that something." So John spent 0.7($40), or $28, on a dishwasher. Taking $40 and $28, or $68 away from $100, John is left with $32. That's 32% of his original earnings, so choice (B) is correct. 

Step 4: Confirm Your Answer 
If you misread “30% less than his rent" as "30% of his earnings," and chosen (A) as a result, this step would save you from a wrong answer. Also, (D) is another trap answer that represents the total percentage of this earnings that John spent.

Test: Quantitative Aptitude- 4 - Question 15

If negative integers k and p are NOT both even, which of the following must be odd?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 15

Step 1: Analyze the Question 
For this abstract number properties question, we can either apply the rules for odd and even numbers directly or simply pick some numbers to solve the question. 

Step 2: State the Task 
We must determine which answer choice must always be odd or, in other words, eliminate any answer choices that can be even. 

Step 3: Approach Strategically 
For some number properties questions, using rules (if you are certain of them) is faster than Picking Numbers. In this question, the condition that k and p are negative and are "not both even" complicates Picking Numbers but not applying rules. Since we have rules for odd and even numbers, we can apply them directly to the answer choices. We start with (E), since this is a "which of the following" question. (E): Because 2 times any value is even, 2(k + p) will always be even. Subtracting one from an even number will always result in an odd number. Therefore, (E) is always odd and must be the correct answer. 

Step 4: Confirm Your Answer
You can confirm your answer by noting that (A) through (D) could be even, judging by odd and even rules. (B) is always even, for example. (A) is odd when k and p are both odd, but the question stem allows for the possibility that one of them is even, and in such a case kp is even.

Test: Quantitative Aptitude- 4 - Question 16

Peter read P books last year, and Nikki read N books last year. If Peter read 35 more books than Nikki last year, which of the following reflects the relationship?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 16

Step 1: Analyze the Question
The sentences in this word problem need to be translated into algebraic statements so that we can determine the relationship between the number of books that Peter and Nikki have read. 

Step 2: State the Task
Once the word problem has been translated, we will apply basic algebra to simplify the statement to match the correct answer choice.

Step 3: Approach Strategically
Translating the phrase "Peter read 35 more books than Nikki," we have P = N + 35.

Step 4: Confirm Your Answer
This translation directly matches (E), but be careful to check that the variables are in the correct order.

Test: Quantitative Aptitude- 4 - Question 17

If 2 is the remainder when m is divided by 5, what is the remainder when 3m is divided by 5?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 17

Step 1: Analyze the Question
This question tests our ability to think critically about the characteristics of remainders in division We are told that some number, m, has a remainder of 2 when divided by 5. 

Step 2: State the Task
We can use our knowledge of number properties to take a particularly strategic approach to this problem. The key will be to pick simple, permissible numbers and apply them to the problem in the question stem. 

Step 3: Approach Strategically
Ask yourself what numbers would be permissible for m. Since m has a remainder of 2 when divided by 5, m could be any number 2 greater than a multiple of 5. The simplest number to substitute for m is 7. We know that 5 goes into 7 one time with a remainder of 2. Now, apply 7 to the rest of the question stem: 3 m divided by 5. Well, 3 x 7 = 21, and 21 divided by 5 would leave a remainder of 1. That's (B). Picking Numbers is the most efficient approach to this common GMAT question type.

Step 4: Confirm Your Answer
To double-check your work, you could test any other permissible number for m: 12, 17, 22, etc. If you tried 12, you would find that 3 x 12 = 36 and 36 divided by 5 leaves a remainder of 1. This confirms that (B) is the correct choice.

Test: Quantitative Aptitude- 4 - Question 18

If 2 + 2/x = 3 - 3/x , then x =

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 18

Step 1: Analyze the Question
This question gives us a complicated-looking equation with one variable. The answer choices are just numbers. 

Step 2: State the Task
Our task is to solve for the value of x

Step 3: Approach Strategically
Since the answer choices are potential values for the variable in the equation, we could just plug those values back in to see which value makes the equation true. Backsolving is an option whenever you can manageably plug an answer choice into the question stem. Let's say that you started with (D), x = 3/2 That makes the equation:

That's not a true statement. So we need to try other values. It's very hard to see whether you needed a larger or smaller x, so it's perfectly fine to try different answer choices. (C) is a sensible choice to test next, as it's the most manageable. It would leave you with 2 + 2 = 3 - 3, which is also false. (E) is the next most manageable. Plugging 5 in for x makes the equation

Step 4: Confirm Your Answer 
Reread the original equation, making sure you didn't make a careless error such as switching the plus and minus signs

Test: Quantitative Aptitude- 4 - Question 19

To fill and art exhibit, the students in an art course are assigned to create one epiece of artwork each in the following distribution: 1⁄3 are sculptures, 1⁄8 are oil paintings, 1⁄2 are watercolors and the remaining 10 pieces are mosaics. How many students are in the art class?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 19

Step 1: Analyze the Question
In this question, we are presented with a series of parts that make up the whole- in this case, the number of students in an art class. Notice that most of the whole is identified as fractions of the whole, while one part is identified as a specific quantity. We can use this to our advantage.

Step 2: State the Task
Determine the sum of the fractions in the question stem (sculptures, oil paintings, watercolors), since this makes up all but one part of the whole number of students. Subtracting this fraction from 1 will provide the fraction of the whole that is the remaining part (mosaics). Finally, we will solve for the number of students in the class. Note that this question can also be solved by Backsolving, since all of the answer choices are numbers and we can test out the answer choices to see if 10 pieces remain after calculating the number of other pieces of artwork.

Step 3: Approach Strategically
We are told that 1/3 of the students create sculptures, 1/8 create oil paintings, 1/2 create watercolors, and the remaining 10 pieces are mosaics. Let's assume that the total number of students in the class is x. Then the sum of the sculptures, oil paintings, and watercolors is as follows: 

(1/3)x + (1/8)x + (1/2)x = x(1/3 + 1/8 + 1/2) = x(8/24 + 3/24 + 12/24) = x(23/24

So the sum of the sculptures, oil paintings, and watercolors is 23/24 of the art in the exhibit. Therefore. the remaining 10 pieces must be 1-23/24 = 1/24 of the total pieces. We can set up the equation: 

(1/24)x = 10; x= 240

Choice (C) is correct.

Step 4: Confirm Your Answer
Plug your value for x into the original equation to confirm your calculations are correct.

Test: Quantitative Aptitude- 4 - Question 20

A computer company's featured laptop cost $800 last year. This year, the laptop sold for 15% less than it did last year. Next year, after updates are made to the model, there will be a 25% price increase over this year's price. What will be the price next year?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 20

First, calculate the price of the laptop this year. Then, use that price to determine what the price will be next year. After a 15% decrease in price, the system would sell for 85% of $800: 0.85 x $800 = $680. If there is a 25% increase next year, the system would sell for 125% of this year's price. That would be 125% of $680: 1.25 x $680 = $850 (D).

Test: Quantitative Aptitude- 4 - Question 21

Master Chef Alan makes a dish every day from one of his recipe books. He has written 3 books and each book contains 15 different recipes. What is the probability that he will cook 4th dish from 3rd book today?

Detailed Solution for Test: Quantitative Aptitude- 4 - Question 21

We note that there are three books and each book contains 15 recipes so there are a total of 45 recipes. The probability that he will cook 4th dish from 3rd book today is 1/45. It's important that you must not get distracted by irrelevant information. All the recipes are different from each other.

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