Test: Quantitative Aptitude- 1 - GMAT MCQ

15 Java programmer complete a work in 3 days ..
1 Java programmer complete the work in 45 days..

Amount of work completed by 1 Java programmer in 1 day = 1/45

So, on 1st day amount of work completed = 1/45 * 15 = 1/3
Amount of work left at the end of the 1st day = 2/3
No. of programmers left after 1st day = 6

No. of extra days = (2/3)/(1/45* 6 ) = 5 days.

⇒ 2 carpenters build 2 desks in 2.5 hours

⇒ 4 carpenters build 4 desks in 2.5 hours

⇒ In 4 hours there are (4/2.5 = 1.6) time units. And (4 x 1.6) is 6.4 desks.

Given that there are 18 boys (9/20*40=18) and 22 girls in the class. Also we know that out of 40 students 32 are right-handed (4/5*40=32).

Maximum number of right-handed boys possible is if ALL 18 boys are right-handed;
Minimum number of right-handed boys possible is if ALL 22 girls are right-handed, so in this case 32-22=10 boys would be right-handed.

There are (5/6 x 300 = 250) white sheep’s.
There are (2/3 x 300 = 200) soft woolen sheep’s.
The maximum overlap is the size of the smallest among the groups, thus 200. The minimum overlap is (250 + 200 – 300 = 150).
Therefore the number of sheep’s can be somewhere between 150 and 200.

Notice that the groups that we are looking for a overlapping are the not-green shirts and the buttoned ones. The not-green shirts are a quarter of 40, 10 shirts.
The shirts with buttons are (9/10 x 40 = 36).
The maximum overlapping is the size of the smallest group: 10.
The minimum overlapping is: 36 + 10 – 40 = 6.
Therefore A is the answer.

There were (3/5 x 50 = 30) action movies.
There were (4/5 x 50 = 40) science fiction movies.
Exact overlapping is calculated by minimum overlapping method.
Therefore there are (40 + 30 – 50 = 20) movies that belong to both categories.

Out of 200 cats, 130 are domestic ones. Out of 110 gray cats, 30 are street cats therefore 80 are grey and domestic ones.
Altogether there are 130 domestic cats, 80 are grey so (130 – 80) = 50 are not grey.

From the grade 40 at the end of the first year we learn that his age is 20.
At the end of the second year, he will be 21 and his grade will be
 (21 x 2 + ½ x 40 = 62).
At the end of the third year, he will be 22 and his grade will be (22 x 2 + ½ x 62 = 75).

This is a series of numbers with a constant spacing between them.
The first number is (-8) and the last is (10), there are 10 numbers altogether.
The formula for such a series is: ((-8 + 10) x 10)/2 = 10.
The second way to answer such a question is to write the numbers and add them

At the end of January her value is 2A – 10.
At the end of February her value is (2 x (2A – 10) – 10 = 4A – 30).

Let’s find the number of Amebas in the first hours.
After one hour (N=1) there will be 4 Amebas.
After two hours (N=2) there will be 8 Amebas.
After three hours (N=3) there will be 16 amebas.
Therefore the formula that fits this series is 2^N+1.

If Beta is 90 degrees than Alfa is bigger than 90 and the sum of the angles in the triangle will be bigger than 180 degrees.

This problem has been circulating in the official practice tests for over a decade. It is amazing how many smart, high-scoring students miss it! There is no hard math present and you just need to follow specific instructions, but people are far too casual on these types of “reading comprehension” math questions. When you are performing well on this exam, there is something hard about every question, so always try to identify where that difficulty is coming from. In this example, the key is to carefully note that the question says, “40 were revised only once.” The “sucker” incorrect answer on this question is calculated as follows:

100 x $5 = $500
40 x $3 = $120
10 x $3 = $30 (incorrectly assuming that you have accounted for the first charge of $3 in the first revision category)

The last calculation is wrong because the ones revised “only once” and “twice” are two completely separate categories—there is no overlap. So, the pages revised twice will cost $6 for each page and the correct charge for those is $6 x 10 = $60. Correct answer is thus $680, not $650. 
When I review an official practice test with a student who misses this question, I literally yell: “You cannot miss this question!” Never be casual with any question regardless of how simple it seems and always find the trap; otherwise, you are surely falling for it. I always emphasize that the “soft skills” on the quant side—reading carefully, critical thinking, strategy—are just as important as hard quant skills, if not more.

The overwhelming majority of our clients are admitted to one of their target schools. We help applicants to select schools that are in line with their qualifications and don’t hesitate to recommend against particular schools (or even against an MBA). We’re happy to help you apply to a stretch school if you understand the odds and do so in the context of a balanced list of schools.

Having said that, we recommend against using success rate as the main way to select a consultant because this metric is easily manipulated by either a) taking only perfect candidates, or b) convincing applicants to apply to easy schools. Furthermore, there is no satisfying way for applicants to verify claimed success rates.

The best answer is B.-1 ~ 2 = (-1)² + (-1)² = -1.

The best answer is A.

 [6.5] x [2/3] + [2] x 7.2 + [8.4] – 6.6 = 6 x 0 + 2 x 7.2 + 8 - 6.6 = 15.8.

The best answer is A.
Try some numbers and check the answers. A=2, B=4.
(a) 6/1 = 6
(b) 2/3
(c) 1/2
(d) 2
(e) 2

The best answer is A
.Compare all of the answers to
(a) 3/10.
(b) 3/10 x 2 = 6/20 which is smaller than 6/19.
(c) 3/10 is smaller.
(d) 3/10 = 9/30, and this is smaller than 11/30.
(e) 3/10 = 12/40 and that is smaller than 12/31.
The smallest fraction is A.

The best answer is C.
Lets compare all the answers to 2/7, unless we find a larger fraction.
(b) 2/3 is larger than 2/7. For now, this is the right answer.
(c)  2/3 is also 6/9 and that is smaller than 7/9. For now this is the right answer.
(d) 7/9 is bigger than 7/12
​(e) Bring this answer and (c) to a common denominator.7/9 = 35/45  and  3/5 = 27/45.
7/9 is the largest fraction.

The best answer is C.
(A – B)²  + (A + B)² = A² – 2AB + B² + A² + 2AB + B² = 2(A² + B²) =  30.

The best answer is D.
All the answers besides D are numbers after some simplification.Answer D = (A + B)/(A+B)² = 1/(A+B), and this is a fraction of a number.