45 Questions MCQ Test NEET Mock Test Series - Chemistry: Topic-wise Test- 2
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The heat of hydrogenation of 1-hexene is 126 . When a second double bond is introduced in the molecule, the heat of hydrogenation of the resulting compound is 230 . The resulting compound (diene) is
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 2
1,3 -hexadiene is a conjugated diene, hence it is more stable than the first compound. The heat of hydrogenation decreases as the stability of the molecule increases. The stability of 13 hexadiene is more than that of a compound which contain two double bonds.
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 5
H2O2 is the special concentration terms.10 volume of H2O2 means that 1ml of H2O2 gives 10 ml of O2.
For example, if it was mentioned 30 volume of H2O2, then its means that 1ml of H2O2 gives 30ml of O2.
The work done by the system in a cyclic process involving one mole of an ideal monoatomic gas is 50 KJ/cycle, The heat absorbed by the system per cycle is
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 8
According to the first law of thermodynamics,
∆Q=∆U+∆W and for a cyclic process, change in internal energy(∆U) is zero. Hence ∆Q=∆W where ∆Q is the heat absorbed and ∆W is the work done. Therefore heat absorbed is 50 kJ
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 13
A state function is the property of the system whose value depends only on the initial and final state of the system and is independent of the path.Heat (q) and work (W) are not state functions being path dependent.
Which of the following reaction is favored by increase of temperature ?
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 14
In options a,c and d, we can say that energy is also a part of the products which is indicated by the + sign between the product and the energy but in case of reaction B, you can see that with the products energy is taken inside that is it is a negative sign so when we transfer that part of the equation to the product side, we can see that in the product there is a sign of plus along with energy which means that energy is given along with the products to obtain the reactants .you can conclude that option B is the correct answer because it is an endothermic reaction
1c.c. of 0.1N HCl is added to 99 c.c. aqueous solution of sodium chloride.The pH of the resulting solution will be
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 17
Normality volume = (0.1) (0.001)
Normality volume = 0.0001 L
Volume of solution = Volume of NaCl + Volume of HCL
Volume of solution = 1 + 0.001
Volume of solution = 1.001 L
Since NaCl is a salt and is neutral so it does not effect pH of a solution.
Normality of HCL in a resulting solution = 0.0001 / 1.001
Normality of HCL in a resulting solution = 0.0001 N
pH = - log [H⁺]
pH = - log (0.0001)
pH = 4
which shows that the pH of the resulting solution is 4
If the maximum concentration of in water is 0.01M at 298K, its maximum concentration in 0.1M NaCl will be
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 19
Concentrations of the ions:
The dissociation reaction for PbCl2 in water is write as,
The maximum concentration of PbCl2 in water is 0.01 M
We can find concentration of the ions using the stoichiometry from the above reaction.
The concentration of Pb²⁺ ion is 0.01 M and concentration of Cl⁻ ion is 2×0.01=0.02M.
The solubility product of PbCl2 can be written as,
Let us insert in the concentrations of Pb and Cl.
Concentration of Pb2+ using common ion effect:
WhenPbCl2 is dissolved in 1MNaCl, there is a common ion Cl−. This decreases the solubility of PbCl2 due to the common ion effect.
The concentration of Cl− in 0.1MNaCl is 0.1. Let us plug in this value to find the new concentration of Pb2+ ion.
The major product obtained when isobutane is treated with chlorine in the presence of light is
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 25
The major product is tert butyl chloride as firstly isobutylchloride is formed but then hydride shift takes place due to which chlorine shift to more stable tertiary carbocation and hence the product is tert butyl chloride.
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 26
SO2 can act as both oxidizing as well as reducing agent since it has +4 oxidation state which is exactly between
its highest oxidation state +6 and lowest oxidation state +2 ,
Thus it can change its oxidation number either from +4 to-2(reduction) and +4 to+6 (oxidation)
Graphite has a layered structure. The distance between the layers is
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 31
Since the layers are only weakly attracted to each other, they can easily slide past one another. This is why graphite is used in pencil lead. The distance between layers is 335 pm. Carbon atoms in diamond are covalently bonded and are arranged in a three-dimensional tetrahedral structure.
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 32
Coal gas contains a variety of calorific gases including hydrogen, carbon monoxide, methane, ethylene and volatile hydrocarbons together with small quantities of non-calorific gases such as carbon dioxide and nitrogen.
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 35
The elments of the boron family adopts oxidation states +3 or +1. The +3 oxidation states are favorable except for the heavier elements, such as Tl, which prefer the +1 oxidation state due to its stability; this is known as the inert pair effect.
A real gas obeying van der Waals equation will resemble an ideal gas if
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 42
According to van der Waals equation for 1 mole of a real gas
If a and b are small, a/V2 and b can be neglected as compared to P and V and the equation reduces to PV=RT. Hence, a real gas will resemble an ideal gas when constants a and b are small.
In which of the following pairs do the molecules (gaseous) have the same root-mean-square speed
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 43
RMS speed = √(3RT/M) where, T is temperature, R is universal gas constant and M is molecular mass of gas
Here molecular mass is same for N2 (14x2=28) and CO (12+16=28) so rms speed will also b same for them as rest all is constant
According to the kinetic theory of gases, between two successive collisions, an ideal-gas molecule travels
Detailed Solution for Chemistry: Topic-wise Test- 2 - Question 44
According to kinetic theory the gas molecules are in a state of constant rapid motion in all possible directions colloiding in a random manner with one another and with the walls of the container and between two successive collisions molecules travel in a straight line path but show haphazard motion due to collisions.
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