NEET Part Test - 4 - NEET MCQ

so, we see at the top most point the velocity the boy is zero and the earth's pull is acting downwards.
Given, g_m/g_e=1/6
=>g_e=6g_m
So using,
v² = u² - 2gs (where g=acceleration due to gravity, s=total height)
so,
0 = u² - 2gs
⇒ s=u²/2g_e
⇒ 2=u²/2g_e
Putting g_e =6g_m
⇒ 2=u²/g_m
⇒ 12=u²/2g_m
so the boy can jump a height of 12 m on the moon's surface.

Mass of Iron = 100g
Water Eq of caloriemeter = 10g
Mass of water = 240g
Let the Temp. of surface = 0^ºC
S_iron = 470J/kg°C 

Total heat gained = Total heat lost.

So,100/1000× 470 × (θ – 60) = 250/1000 × 4200 × (60 – 20)
⇒ 47θ – 47 × 60 = 25 × 42 × 40
⇒  θ = 4200 + 2820/47= 44820/47 =953.61°C

Displacement of airctaft in time t = horizontal displacement of projectile

As we know,

S=rhdg/2cosθ

⇒ Pressure difference =hdg=2Scosθ/r

When the particle crosses D, its speed is half the maximum speed.

When no beats is listened at the station thus we get the relative frequencies of both the trains are the same.
Hence the relative frequency of the train B is 600 (330/300) = 660
similarly the relative frequency of train A is f(330/315) = 660
Hence we get f = 630Hz

Molecular mass of hydrogen = 1  

Molecular mass of oxygen =16  

Molecular mass of water = 18 gram per mole  

As,

n = m / M

n = 500 / 18

n = 27.8 moles  

For cooling 27.8 moles at 20 = 27.8 x 75.4 x 20 = 41.922 kilo joule

41.922/6  = 6.987 that is approximately equal to 7  

So, the number of ice cubes that are required to cool the water will be 7.

A species which is oxidised (deelectronation) is a reducing agent.

Thus, (ii) and (iv) represent reducing behaviour of H₂O₂.

Ferriferrocyanide is the blue complex formed by sodium ferrocyanide and NaCN.

Step I: Skeleton OCO

Step II: A = 1 x 4 for C + 2 x 6 for O = 4 + 12 = 16 electrons

Step III : Total no. of electrons needed to achieve noble gas configuration (N)
N= 1 x 8 + 2 x 8 = 24

Step IV : Shared electrons, S = N- A = 24-16 = 8 electrons

X has highest IE₁ and IE₂ hence, it is a noble gas. Y has low lE₁, but very high IE₂ hence, it is an alkali metal.
Z has low lE₁ than IE₂ and IE₂ is even lower than IE₂ of alkali metal hence, it is an alkaline earth metal.

When the external intercostal muscles and diaphragm relax, the ribs move downward and inward and diaphragm becomes convex (dome shaped), thus decreasing the volume of thoracic cavity and increasing the pressure inside as compared to the atmospheric pressure outside. This will cause the air to move out (expiration).

Posterior pituitary releases vasopressin which stimulates reabsorption of water in the distal tubules in nephron.

Dicot stem: The outer hypodermis, consists of a few layers of collenchymatous cells just below the epidermis, which provide mechanical strength to the young stem. Cortical layers below hypodermis consist of rounded thin walled parenchymatous cells with conspicuous intercellular spaces.
Monocot stem: The monocot stem has a sclerenchymatous hypodermis, a large number of scattered vascular bundles, each surrounded by a sclerenchymatous bundle sheath, and a large, conspicuous parenchymatous ground tissue

Photophosphorylation is the conversion of ADP to ATP using the energy of sunlight by activation of PSII. This involves the splitting of the water molecule in oxygen and hydrogen protons (H⁺), a process known as photolysis.

Mitosis is the type of cell division that ensures equal distribution of genetic material in daughter cells. Mitosis can occur both in diploid and haploid cells.
The main function of mitosis is to make copies of cells for growth and regeneration.

At prophase I, DNA replication has already occurred, and the original amount of DNA has been doubled to x. At anaphase I, the amount of DNA in the cell remains the same because no cytokinesis has occurred yet to separate the cytoplasm.

The original statement that neurons regulate endocrine activity is not entirely correct. Both the nervous system and the endocrine system interact with and regulate each other.

• The nervous system can influence endocrine glands through nerves, such as the hypothalamus controlling the pituitary gland.
• Conversely, hormones produced by endocrine glands can affect neural activity, demonstrating a two-way interaction.

Therefore, the idea that only one system regulates the other is inaccurate. The correct statement reflects the mutual regulation between these systems.

Bulliform cells are large, empty, and colourless cells found in the leaves of grasses. These cells help in controlling leaf rolling under water stress.

Given figure represents Z scheme of light reaction. The whole scheme of transfer of electrons, starting from the PS II, uphill to the acceptor, down the electron transport to PS I, excitation of electrons transfer to another acceptor, and finally down hill to NADP⁺ causing it to be reduced to N ADPH + H⁺ is called the Z scheme, due to its characteristic shape.

A-Stele: It is the central core of the stem and root of a vascular plant, consisting of the vascular tissues (xylem and phloem) and associated supporting tissues.
B - Endodermis: It is an inner layer of cells in the cortex of a root and of some stems, surrounding the stele.
C - C asparian strip: It is a band of cell wall material deposited on the radial and transverse walls of the endodermis, and is chemically different from the rest of the cell wall, which is made of lignin and without suberin whereas the casparian strip is made of suberin and sometimes lignin.
D - Bark: It is the outermost layer of stems and roots of woody plants. Plants with bark include trees, woody vines and shrubs.

Sarcomere Components

• A-Band (I): Represents the length of the myosin filaments, including areas where actin and myosin overlap, and appears as the darker region.
• I-Band (II): Contains only actin filaments and is the lighter area that appears to shorten during muscle contraction.
• Sarcomere (III): The entire unit from one Z-line to the next.
• H-Zone (IV): The lighter region in the middle of the A-band where only myosin filaments are present when the muscle is relaxed.
• Myosin (V): The thick filament.
• Actin, Troponin, Tropomyosin (VI): Components of the thin filaments.
• Z-line (VII): The dark line to which actin filaments are attached, marking the boundary of each sarcomere.

Label Correspondence

• A: Appears to be the Z-line, marking the boundary of the sarcomere.
• B: Thick filaments (myosin) as seen in the center part of the sarcomere.
• C: Contains elements of both myosin and actin filaments, typical of the A-band.
• D: Shows the I-band, where only actin filaments are present.
• E: Another part of the A-band with overlapping actin and myosin filaments.
• F: The entire unit from one Z-line to the next Z-line, representing the sarcomere.
• G: The lighter middle region within the A-band where only myosin filaments are visible, representing the H-zone.

An embryo shows geometrical growth initially but later it passes into arithematic phase.

Lyases enzyme catalyses breakdown without addition of water.
Isomerase enzyme catalyses the conversion of an aldose sugar to a ketose sugar.
Oxidoreductase enzyme catalyses the transfer of electrons from one molecule to another molecule.
Ligases enzyme catalyses the bonding of two RNA molecules.

The given molecule is adenylic acid. It is a nucleotide found in RNA. It is an ester of phosphoric acid with the nucleoside adenosine. It consists of a phosphate group, a pentose sugar ribose, and the nucleobase adenine.

• In hypogynous flower, gynoecium occupies the highest position.
• Superior ovary is present in hypogynous flower.
• In epigynous flower, gynoecium is the bottom most whorl. China rose is an example of hypogynous flower.

Grave’s disease is due to excess secretion of thyroid hormones (T₃ & T₄). Diabetes mellitus is due to hyposecretion of insulin from beta-cells of pancreas. Diabetes insipidus is due to hyposecretion of ADH from posterior pituitary. Addison’s disease is due to hyposecretion of hormone from adrenal cortex.