NEET Practice Test - 3 - NEET MCQ

# NEET Practice Test - 3 - NEET MCQ

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## 180 Questions MCQ Test NEET Mock Test Series 2025 - NEET Practice Test - 3

NEET Practice Test - 3 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Practice Test - 3 questions and answers have been prepared according to the NEET exam syllabus.The NEET Practice Test - 3 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Practice Test - 3 below.
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NEET Practice Test - 3 - Question 1

### A rigid container with thermally insulated walls contains a coil of resistance 100 Ω, carrying current 1 A. Change in internal energy after 5 min will be

Detailed Solution for NEET Practice Test - 3 - Question 1
W = 0. Therefore, from first law of thermodynamics,

ΔU = ΔQ = i2Rt

= (1)2(100)(5 × 60)J = 30 kJ .

NEET Practice Test - 3 - Question 2

### Two spherical bodies of mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only, then distance covered by the smaller body just before collision is

Detailed Solution for NEET Practice Test - 3 - Question 2
Let the spheres collide after time t, when the smaller sphere covered distance x1 and bigger sphere covered distance x2.

The gravitational force acting between two spheres depends on the

distance which is variable quantity.

The gravitational force,

Acceleration of smaller body,

Acceleration of bigger body,

From equation of motion,

We know that x1 + x2 = 9R

Therefore, the two spheres collide when the smaller sphere covers a distance of 7.5R.

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NEET Practice Test - 3 - Question 3

### Two particles of mass m each are tied at the ends of a light string of length 2a. The whole system is kept on a frictionless horizontal surface with the string held tight so that each mass is at a distance a from the centre P (as shown in the figure). Now, the mid-point of the string is pulled vertically upwards with a small but constant force F. As a result, the particles move towards each other on the surface. The magnitude of acceleration, when the separation between them becomes 2x, is

Detailed Solution for NEET Practice Test - 3 - Question 3
The acceleration of mass m is due to the force T cosθ

∴ T cosθ = ma

Also F = 2T sin θ

From (i) and (ii)

NEET Practice Test - 3 - Question 4

Statement I : The formula connecting u, υ and f for a spherical mirror is valid only for mirrors whose sizes are very small compared to their radii of curvature.

Statement II : Laws of reflections are strictly valid for plane surfaces, but not for large spherical surfaces.

Detailed Solution for NEET Practice Test - 3 - Question 4
Laws of reflection can be applied to any type of surface.
NEET Practice Test - 3 - Question 5

A 3 volt battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be

Detailed Solution for NEET Practice Test - 3 - Question 5
Equivalent resistance

NEET Practice Test - 3 - Question 6

The pressure of a medium is changed from 1.01 × 105 Pa to 1.165 × 105 Pa and change in volume is 10% keeping temperature constant. The bulk modulus of the medium is

Detailed Solution for NEET Practice Test - 3 - Question 6
From the definition of bulk modulus,

Substituting the values, we have

NEET Practice Test - 3 - Question 7

An inductor of inductance 2.0 mH is connected across a charged capacitor of capacitance 5.0 μF and the resulting L-C circuit is set oscillating at its natural frequency. Let Q denote the instantaneous charge on the capacitor and I the current in the circuit. It is found that the maximum value of Q is 200  μC. When Q = 100 μC, what is the value of

Detailed Solution for NEET Practice Test - 3 - Question 7
This is a problem of L - C oscillations.

Charge stored in the capacitor oscillates simple harmonically as

Here, Q0 = maximum value of Q = 200  μC = 2 × 10−4 C

NEET Practice Test - 3 - Question 8

A simple pendulum is oscillating without damping. When the displacement of the bob is less than maximum, its acceleration vector is correctly shown in

Detailed Solution for NEET Practice Test - 3 - Question 8

NEET Practice Test - 3 - Question 9

A charge +q is fixed at each of the points x = x0, x = 3x0, x = 5x0 ........∞ on the x−axis and a charge −q is fixed at each of the points x = 2x0, x = 4x0, x = 6x0 .........,∞. Here, x0 is a positive constant. Take the electric potential at a point due to a charge Q at a distance r from it to be Then the potential at the origin due to the above system of charges is

Detailed Solution for NEET Practice Test - 3 - Question 9
Potential at origin will be given by

NEET Practice Test - 3 - Question 10

The earth radiates in the infra-red region of the spectrum. The wavelength of the maximum intensity of the spectrum is correctly given by

Detailed Solution for NEET Practice Test - 3 - Question 10
When the temperature of a black body radiator rises, the overall radiated energy rises, and the peak of the radiation curve moves to shorter wavelengths, in accordance to Wien's law. It is given by λT = b, where T is the temperature and λ corresponds to the wavelength around which maximum energy radiated.
NEET Practice Test - 3 - Question 11

The dimensional formula for magnetic flux is

Detailed Solution for NEET Practice Test - 3 - Question 11
According to Faraday’s law of electromagnetic induction, E.M.F.

NEET Practice Test - 3 - Question 12

The half-life of 131I is 8 days Given a sample of 131I at time t = 0, we can assert that

Detailed Solution for NEET Practice Test - 3 - Question 12
Number of nuclei decreases exponentially

N = N0e−λt and rate of decay

Therefore, decay process lasts upto t = ∞.

Therefore, a given nucleus may decay at any time after t = 0

NEET Practice Test - 3 - Question 13

Two particles A and B of masses mA and mB respectively and having the same charge are moving in a plane. A uniform magnetic field exists perpendicular to this plane. The speeds of the particles are vA and vB respectively and the trajectories are as shown in the figure. Then

Detailed Solution for NEET Practice Test - 3 - Question 13

or radius ∝ mv if B and q are same.

∴ mA vA > mB vB

NEET Practice Test - 3 - Question 14

In common base mode of a transistor, the collector current is 5.488 mA for an emitter current of 5.60 mA. The value of the base current amplification factor, β will be

Detailed Solution for NEET Practice Test - 3 - Question 14

NEET Practice Test - 3 - Question 15

Two particles A and B initially at rest, move towards each other, under the mutual force of attraction. At an instance when the speed of A is v and the speed of B is 2v, the speed of the centre of mass(CM) is

Detailed Solution for NEET Practice Test - 3 - Question 15
As initially both the particles were at rest, therefore, the velocity of the centre of mass was zero and there is no external force on the system. So, the speed of the centre of mass remains constant, i. e., it should be equal to zero.
NEET Practice Test - 3 - Question 16

The angle between the vector will be

Detailed Solution for NEET Practice Test - 3 - Question 16

NEET Practice Test - 3 - Question 17

A block of mass 5 kg is moving in x-direction with a constant speed 20 m/s. Now it is subjected to a retarding force Fr = – 0.2 x J/m during its travel from x = 10 m to x = 20 m. Its final velocity will be nearly

Detailed Solution for NEET Practice Test - 3 - Question 17
dW = Fdx

NEET Practice Test - 3 - Question 18

When two spheres of equal masses undergo oblique elastic collision with one of them at rest initially, after collision they will move

Detailed Solution for NEET Practice Test - 3 - Question 18
Both sphere after collision will move at 90° to each other in elastic collision.
NEET Practice Test - 3 - Question 19

Two springs of spring constants 500 N m–1 and 500 N m–1 are stretched with force 100 N and 200 N respectively. They have potential energy in the ratio of

Detailed Solution for NEET Practice Test - 3 - Question 19
F = kx

F µ x

= 1/4

NEET Practice Test - 3 - Question 20

Which of the diagram shown in figure represents the variation of total mechanical energy of pendulum oscillating in air as a function of time?

Detailed Solution for NEET Practice Test - 3 - Question 20
When a pendulum is oscillating in air, its total mechanical energy decreases exponentially with time.
NEET Practice Test - 3 - Question 21

An object has displacement from position vector

under the effect of a force The work done by this force will be

Detailed Solution for NEET Practice Test - 3 - Question 21

= 7 J

NEET Practice Test - 3 - Question 22

A bus of mass 5 metric tonne is pulled at a speed of 18 km/h on a smooth inclination 1 in 10. Power of the engine is

Detailed Solution for NEET Practice Test - 3 - Question 22
P = F × v

= mg sinθv

= 2.5 kW

NEET Practice Test - 3 - Question 23

A ball A moving with certain velocity collides head on with another body B of the same mass at rest. If the coefficient of restitution is 3/4. The ratio of velocity A and B after collision is

Detailed Solution for NEET Practice Test - 3 - Question 23

mv = mv1 + mv2

v = v1 + v2

∴ 4v2 – 4v1

= 3v 4v2 – 4v1 = 3(v1 + v2)

v2 = 7v1

NEET Practice Test - 3 - Question 24

A force of 1 N acts on a 1 kg mass for 1 second which is initially at rest. In another case 1 N force acts on 1 kg mass which is initially at rest and moves it through 1 m. The ratio of kinetic energy in the two cases is

Detailed Solution for NEET Practice Test - 3 - Question 24
v1 = u + at

= 1 m/s

= √2

= 1/2

NEET Practice Test - 3 - Question 25

A body is being raised to a height h from the surface of earth. What is the sign of work done by applied force and gravitational force respectively?

Detailed Solution for NEET Practice Test - 3 - Question 25
Angle between applied force and displacement is 0° and gravitational force and displacement is 180°.
NEET Practice Test - 3 - Question 26

A force acting on a body maintains its velocity If rate of change of kinetic energy of the body is zero, then the value of α will be

Detailed Solution for NEET Practice Test - 3 - Question 26

3α + 2 – 8 = 0

α = 2

NEET Practice Test - 3 - Question 27

A body is initially at rest. It undergoes one dimensional motion with constant acceleration. The power delivered to it at time t is proportional to

Detailed Solution for NEET Practice Test - 3 - Question 27
v = at

P = F × v

P = ma2t

P ∝ t

NEET Practice Test - 3 - Question 28

1 kilowatt hour (kW h) is equal to

Detailed Solution for NEET Practice Test - 3 - Question 28

= 2.25 × 1025 eV

NEET Practice Test - 3 - Question 29

A ball of mass m collides with a wall with speed v and rebounds on the same line with the same speed. If mass of the wall is taken infinite at rest, then work done by the ball on the wall is

Detailed Solution for NEET Practice Test - 3 - Question 29
Wnet = F·Δk But Δx = 0

∴ Wnet = 0 (no work on wall)

NEET Practice Test - 3 - Question 30

Statement-A: Work done by frictional force is always negative.

Statement-B: A body at rest can have mechanical energy.

Detailed Solution for NEET Practice Test - 3 - Question 30
Work done by friction may be zero, positive or negative. Body at rest can have mechanical energy due to its potential energy.
NEET Practice Test - 3 - Question 31

A body of mass 5 kg moves according to the relation x = t2 + 2 t3. The power used by the body at t = 2 s is

Detailed Solution for NEET Practice Test - 3 - Question 31
x = t2 + 2t3

v = 2t + 6t2

a = 2 + 12t

= mav

= 5 × 26 × 28

= 3640 W

NEET Practice Test - 3 - Question 32

A free falling body takes 6 s to reach the ground. Three second after release, the percentage of retained potential energy to its initial potential energy is

Detailed Solution for NEET Practice Test - 3 - Question 32
h1 = 135 m

NEET Practice Test - 3 - Question 33

Two masses of 1 kg each move towards each other with speed 4 m/s and 2 m/s collide and stick together. The final kinetic energy of the system will be

Detailed Solution for NEET Practice Test - 3 - Question 33
By conservation of linear momentum

NEET Practice Test - 3 - Question 34

Directions : Each of these questions contain two statements, Assertion and Reason. Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select one of the codes (a), (b), (c) and (d) given below.

Assertion: If there were no gravitational force, the path of the projected body always be a straight line.

Reason: Gravitational force makes the path of projected body always parabolic.

Detailed Solution for NEET Practice Test - 3 - Question 34
Upto ordinary heights, the gravitational force remains stationary, since the distance from earth's surface is negligible compared to radius of the earth. Thus the path of projectiles is parabolic.

However as the distance increases, the gravitational field decreases inversely as square of distance from earth. Thus the gravitational field is variable. Under such a gravitational field, the path of projectile is elliptical.

NEET Practice Test - 3 - Question 35

Consider the following table:

The above given table is a truth table for

Detailed Solution for NEET Practice Test - 3 - Question 35
The given table is a truth table for NAND gate. In digital electronics, a NAND gate (NOT-AND) is a logic gate which produces an output which is false only if all its inputs are true; thus its output is complement to that of an AND gate. A LOW (0) output results only if all the inputs to the gate are HIGH (1); if any input is LOW (0), a HIGH (1) output results.
NEET Practice Test - 3 - Question 36

The average energy density of magnetic field of an EM wave is given by

Detailed Solution for NEET Practice Test - 3 - Question 36
The average energy density of magnetic field of an EM wave is given by

Here, B is the rms value of the magnetic field and B0 is the peak value of the magnetic field.

NEET Practice Test - 3 - Question 37

A rectangular glass slab ABCD of refractive index n1 is immersed in water of refractive index n2 (n1 > n2). A ray of light is incident at the face AB of the slab as shown in the figure. The maximum value of the angle of incidence such that the ray comes out only from the other side CD is given by

Detailed Solution for NEET Practice Test - 3 - Question 37
The ray will emerge from side CD of the slab if the ray refracted in the slab suffers repeated total internal reflections at faces AD and BC of the slab as shown in Fig. From Snell's law, we have

The critical angle ic is given by

Thus angle i must at least be equal to ic.

Therefore ic = 90° - r or r = 90° - ic.

Hence the correct choice is (1).

NEET Practice Test - 3 - Question 38

An X-ray tube is operated at a constant potential difference and it is required to get X-ray of wave length not less than 0.2 nanometre. Then, the potential difference in kV is (h = 6.63 × 10-34Js, e = 1.6 × 10-19 C, c = 3 × 108 m/s)

Detailed Solution for NEET Practice Test - 3 - Question 38
Given: Minimum wavelength of X-ray

λ = 0.2 x 10-9m and h = 6.63 x 10-34 Js,

e = 1.6 x 10-19 coulomb

and c = 3 x 108 m/s

The minimum wavelength of continuous

X-ray spectrum

NEET Practice Test - 3 - Question 39

A nucleus has mass represented by M(A, Z). If Mp and Mn denote the masses of proton and neutron, respectively, and B.E. the binding energy in MeV, then

Detailed Solution for NEET Practice Test - 3 - Question 39
The difference in mass of nucleons ( mass of protons and neutrons) and the mass of the nucleus is called the mass defect and is given by

ΔM = [ZMp + (A - Z)Mn] - M(A,Z)

And binding energy =Mc2

= [{ZMp + (A - Z)Mn} - M(A,Z)]c2

NEET Practice Test - 3 - Question 40

In the energy band diagram of the material shown below, the open circles and filled circles denote holes and electrons, respectively. The material is

Detailed Solution for NEET Practice Test - 3 - Question 40
For a p-type semiconductor, the acceptor energy level, as shown in the diagram, is slightly above the top Ev of the valence band. With very small supply of energy, an electron from the valence band can jump to the level EA and ionize acceptor negatively.
NEET Practice Test - 3 - Question 41

The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is

Detailed Solution for NEET Practice Test - 3 - Question 41
The wavelength of the first line of Lyman series for hydrogen atom is

The wavelength of the second line of Balmer series for hydrogen like ion is

According to question λ = λ’

or Z2 = 4 or Z = 2

NEET Practice Test - 3 - Question 42

The external and internal radii of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01) cm, respectively. The thickness of the wall of the cylinder is

Detailed Solution for NEET Practice Test - 3 - Question 42
Given,

The external radius(r0) and internal radii(ri) of a hollow cylinder are measured to be (4.23 ± 0.01) cm and (3.89 ± 0.01) cm respectively.

When two quantities are added or subtracted, the absolute error in the final result is the sum of the absolute error in individual quantities.

The thickness(t) of the wall is given as the difference between outer radius r0r0 and inner radius ri.

That is, t = r0 − ri

t = r0 - ri

t = (4.23 ± 0.01) − (3.89 ± 0.01) (The errors for the same quantity measurement can be added directly)

Here, Δt = Δr0 + Δri = 0.01 + 0.01 = 0.02

∴ t = (0.34 ± 0.02) cm

NEET Practice Test - 3 - Question 43

Match the following (Take the relative strength of the strongest fundamental forces in nature as one)

The correct match is

Detailed Solution for NEET Practice Test - 3 - Question 43

NEET Practice Test - 3 - Question 44

Directions: Each of these questions contain two statements, Assertion and Reason. Each of these questions also has four alternative choices, only one of which is the correct answer. You have to select one of the codes (a), (b), (c) and (d) given below.

Assertion: If a body of mass m is projected upwards with a speed V making an angle ? with the vertical, than the change in the momentum of the body along X–axis is zero.

Reason: Mass of the body remains constant along X–axis

Detailed Solution for NEET Practice Test - 3 - Question 44
When a body is projected up making an angle ? the velocity component along-axis remains constant. Therefore, Momentum along x-axis is constant. Along horizontal, mass and velocity both are constant.
NEET Practice Test - 3 - Question 45

The wire shown in the figure below carries a current of 40 A. If r = 3.14 cm, the magnetic field at point P will be

Detailed Solution for NEET Practice Test - 3 - Question 45
The straight portions of the wire do not contribute because the point P is along them. The field at P is due to 3/4th of the loop of radius r. Then,

= 6 × 10-4 T

NEET Practice Test - 3 - Question 46

Given that the abundance of isotopes 54Fe, 56Fe and 57Fe are 5 %, 90 % and 5 % respectively, what is the atomic mass of Fe?

Detailed Solution for NEET Practice Test - 3 - Question 46
From relative abundance,

Atomic mass average

NEET Practice Test - 3 - Question 47

The solubilities of carbonates decrease down the magnesium group due to a decrease in

Detailed Solution for NEET Practice Test - 3 - Question 47
The stability of the carbonates of alkaline earth metals increases, on moving down the group. The solubility of carbonates of metals in water is generally low. However, they dissolve in water containing CO2, yielding bicarbonates and this solubility decreases on going down in a group with an increase in the stability of carbonates of metals and decrease in hydration energy of the cations, due to larger sizes down the group.
NEET Practice Test - 3 - Question 48

Which of the following is a redox reaction?

Detailed Solution for NEET Practice Test - 3 - Question 48
The oxidation states show a change only in reaction (Zn + 2AgCN ⟶ 2Ag + Zn(CN)2).

Here, Zn is oxidised to Zn+2 and silver is reduced.

NEET Practice Test - 3 - Question 49

When 25 g of a non-volatile solute is dissolved in 100 g of water, the vapour pressure is lowered by 2.25 × 10-1 mm of Hg. If the vapour pressure of water at 20oC is 17.5 mm of Hg, what is the molecular weight of the solute?

Detailed Solution for NEET Practice Test - 3 - Question 49
Given,

weight of non-volatile solute,

w = 25 g

Weight of solvent, W = 100 g

Lowering of vapour pressure,

− ps = 0⋅225mm of Hg

Vapour pressure of pure solvent,

= 17⋅5 mm of Hg

Molecular weight of solvent (H2 O) , M = 18 g

Molecular weight of solute, m= ?

According to Raoult's law

= 350 g

NEET Practice Test - 3 - Question 50

A sample of air contains only N2, O2 and H2O. It is saturated with water vapours and the total pressure is 640 torr. The vapour pressure of water is 40 torr and the molar ratio of N2 : O2 is 3 : 1. The partial pressure of N2 in the sample is

Detailed Solution for NEET Practice Test - 3 - Question 50
Pressure of dry air = Pmoist air − Pwater vapours

= 640 - 40 = 600 torr

Partial pressure ∝ mole fraction

∴ Partial pressure of N2 and O2 are also in the ratio of 3 : 1.

Partial pressure of

NEET Practice Test - 3 - Question 51

on mercuration-demercuration produces the major product :

Detailed Solution for NEET Practice Test - 3 - Question 51

Rearrangement of carbocation formed is not possible due to formation of cyclic non-classical carbocation

NEET Practice Test - 3 - Question 52

The chemical formula of feldspar is

Detailed Solution for NEET Practice Test - 3 - Question 52
Feldspar is the name given to a group of naturally occurring alumino-silicate minerals. The chemical formula of feldspar is KAlSi3O8. Most of the products we use on a daily basis are made with feldspar: glass for drinking, glass for protection, fiber glass for insulation.
NEET Practice Test - 3 - Question 53

Which of the following acts as an oxidizing as well as reducing agent?

Detailed Solution for NEET Practice Test - 3 - Question 53
NaNO2NaNO2 (Sodium nitrite) acts both as oxidising as well as reducing agent because in it N-atom is in +3 oxidation state (intermediate oxidation state).

Oxidising property

2NaNO2 + 2KI + 2H2SO4 ⟶ Na2SO4 + K2SO4 + 2NO + 2H2O + I2

Reducing property

H2O2 + NaNO2 ⟶ NaNO3 + H2O

NEET Practice Test - 3 - Question 54

A metallic element has a cubic lattice. Each edge of the unit cell is 2Å. The density of the metal is 2.5 g cm−3. The unit cells in 200 g of the metal are

Detailed Solution for NEET Practice Test - 3 - Question 54
Edge length of the unit cell = 2 Å = 2 × 10−8cm

Volume of the unit cell =(2 × 10−8)3 cm3

= 8 × 10−24 cm3

Mass of unit cell = volume × density

= 8 × 10−24 × 2.5 g

No. of unit cells in 200 g of the metal

= 1 × 1025

NEET Practice Test - 3 - Question 55

Distillation of concentrated HNO3 with phosphorus pentoxide produces

Detailed Solution for NEET Practice Test - 3 - Question 55
The reaction occurring is

NEET Practice Test - 3 - Question 56

In the dichromate dianion

Detailed Solution for NEET Practice Test - 3 - Question 56
The structure of dichromate ion is

Since it exhibits resonance phenomena, all Cr-O bonds are equivalent except for the Cr-O-Cr bond which doesn't participate in Resonance.

NEET Practice Test - 3 - Question 57

In a saturated solution of the sparingly soluble electrolyte AgIO3 (molecular mass = 283), the equilibrium which sets in is AgIO3 (s) ⇌ Ag+ (aq)+IO3 (aq).

If the solubility product constant Ksp of AgIO3 at a given temperature is 1.0 × 10−8, what is the mass of AgIO3 in 100 mL of its saturated solution?

Detailed Solution for NEET Practice Test - 3 - Question 57

NEET Practice Test - 3 - Question 58

Copper crystallises into an FCC lattice with edge length 3.61 × 10-8 cm. Its calculated density g cm-3 is?

Detailed Solution for NEET Practice Test - 3 - Question 58

For the FCC lattice of copper, Z = 4.

The atomic mass of copper, M = 63.5 g mol−1.

= 8.97 g cm-3.

The calculated value of density is approximately in agreement with its measured value of 8.97 g cm−3.

NEET Practice Test - 3 - Question 59

Which of the following is correct?

Detailed Solution for NEET Practice Test - 3 - Question 59
Alkali metals are electropositive, hence they can reduce CO2.

4Na + CO2 → 2Na2O + C

NEET Practice Test - 3 - Question 60

The correct order of increasing oxidising power is

Detailed Solution for NEET Practice Test - 3 - Question 60
Metals are good reducing agents, while non-metals are good oxidizing agents. Further among halogens, the metallic character increases as we move from top to bottom in a group.

Based on the reduction potential of halogens Fluorine has a more positive reduction potential and iodine has the least positive reduction potential. So, Fluorine is the most oxidizing agent and Iodine is the least.

Therefore, the correct order of increasing oxidising power is I2 < Br2 < Cl2 < F2.

NEET Practice Test - 3 - Question 61

In mercury cells, cathode used is

Detailed Solution for NEET Practice Test - 3 - Question 61
In mercury cell cathode used is paste of HgO and carbon.
NEET Practice Test - 3 - Question 62

Which of the following graphs represents Henry’s law? (Where x = mole fraction of dissolved gas, KH = 2000 kbar)

Detailed Solution for NEET Practice Test - 3 - Question 62
Henry law, is p = KHx

x = mole fraction of dissolved gas

p = Partial pressure of gas

∴ log p = log KH + log x

log x = log p - log KH

NEET Practice Test - 3 - Question 63

Resistance of a 0.1 M KCI solution in a conductance cell is 200 ohm and conductivity is 0.015 S cm-1. The value of cell constant is

Detailed Solution for NEET Practice Test - 3 - Question 63
Conductance (G) = 1/R = 1/200

NEET Practice Test - 3 - Question 64

Which of the following is a zero order reaction?

Detailed Solution for NEET Practice Test - 3 - Question 64
(a) Zero order

(b) First order

(c) First order

(d) Pseudo First order

NEET Practice Test - 3 - Question 65

How many half lives are required to complete 93.75% of a first order reaction?

Detailed Solution for NEET Practice Test - 3 - Question 65

NEET Practice Test - 3 - Question 66

A cube of 1 m edge length is crushed in order to get small cubes of edge length 1 mm. By which factor does the surface area increase?

Detailed Solution for NEET Practice Test - 3 - Question 66
Edge Length of original cube = 1 m = 103 mm

Total surface area of cube = 6 x (103)2 = 6 * 106 mm2

When cube is Broken into cubes of edge length 1 mm then 109 cubes will be obtained due to constant volume.

Total surface area = 109 x 6 x (1)2 = 6 x 109 mm2

Increase in surface area = 6 x 109/ 6 x 106 = 103

NEET Practice Test - 3 - Question 67