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NEET Minor Test - 2 - NEET MCQ


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30 Questions MCQ Test NEET Mock Test Series 2025 - NEET Minor Test - 2

NEET Minor Test - 2 for NEET 2024 is part of NEET Mock Test Series 2025 preparation. The NEET Minor Test - 2 questions and answers have been prepared according to the NEET exam syllabus.The NEET Minor Test - 2 MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for NEET Minor Test - 2 below.
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NEET Minor Test - 2 - Question 1

An electric lift with a maximum load of 2000kg (lift + passengers) is moving up with a constant speed of 1.5ms−1. The frictional force opposing the motion is 3000N. The minimum power delivered by the motor to the lift in watts is : (g=10ms−2)

Detailed Solution for NEET Minor Test - 2 - Question 1

Fup =2000g + 3000

= 23000N

Minimum power =

= 34500W

NEET Minor Test - 2 - Question 2

The distance covered by a body of mass 5g having linear momentum 0.3kgm∕s in 5s is:

Detailed Solution for NEET Minor Test - 2 - Question 2
P = mv

0.3 = 5/1000 × v ⇒ v = 60m/s

Distance travelled in 5s = 60 × 5

= 300m

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NEET Minor Test - 2 - Question 3

A particle is released from height S from the surface of the Earth. At a certain height its kinetic energy is three times its potential energy. The height from the surface of earth and the speed of the particle at that instant are respectively

Detailed Solution for NEET Minor Test - 2 - Question 3
Let required height of body is y.

When body from rest falls through height (S – y)

Then under constant acceleration

v2 = 02 + 2g(S − y)

V = √2g(S − y) ......(1)

When body is at height y above ground. Potential energy of body of mass m

U = mgy

As per given condition kinetic energy, K = 3U

1/2m(v)2 = 3 × mg(y)

1/2 × m × 2g(S − y) = 3×mgy (using (1))

S − y = 3y

∴ y = S/4 .......(2)

NEET Minor Test - 2 - Question 4

Body A of mass 4m moving with speed u collides with another body B of mass 2m, at rest. The collision is head on and elastic in nature. After the collision the fraction of energy lost by the colliding body A is

Detailed Solution for NEET Minor Test - 2 - Question 4
Fractional loss of KE of colliding body,

NEET Minor Test - 2 - Question 5

A mass m is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when

Detailed Solution for NEET Minor Test - 2 - Question 5

We know that,

The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.

NEET Minor Test - 2 - Question 6

A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will be

Detailed Solution for NEET Minor Test - 2 - Question 6
Coefficient of Restitution (e) -

Ratio of relative velocity after collision to relative velocity before collision.

Let velocity of 4m mass is v after collision

then mv = 4mv

v = v/4v

= 1/4

= 0.25

NEET Minor Test - 2 - Question 7

Consider a drop of rain water having mass 1 g falling from a height of 1 km. It hits the ground with a speed of 50ms−1. Take 'g' constant with a value 10ms−2. The work done by the

(i) gravitational force and the

(ii) resistive force of air is

Detailed Solution for NEET Minor Test - 2 - Question 7
Here

m = 1g = 10−3kg,h = 1km = 1000m. v = 50ms−1, g = 10ms−2

(i) The work done by the gravitational force

= mgh = 10−3 × 10 × 1000 = 10J

(ii) The total work done by gravitational force and the resistive force of air is equal to change in kinetic energy of rain drop

NEET Minor Test - 2 - Question 8

Two identical balls A and B having velocities of 0.5ms−1 and 0.3ms−1 respectively collide elastically in one dimension. The velocities of B and A after the collision respectively will be

Detailed Solution for NEET Minor Test - 2 - Question 8
Masses of the balls are same and collision is elastic, so their velocity will be interchanged after collision.

∴ va = +uB = −0.3ms−1 and vB = vA = 0.5ms−1

NEET Minor Test - 2 - Question 9

A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8×10−4J by the end of the second revolution after the beginning of the motion?

Detailed Solution for NEET Minor Test - 2 - Question 9

Here,m = 10g = 10−2kg

R = 6.4cm = 6.4 × 10−2m, Kf = 8 × 10−4J

Ki = 0, at = ?

Using work energy theorem,

Work done by all the forces = Change in KE

NEET Minor Test - 2 - Question 10

What is the minimum velocity with which a body of mass m must enter a vertical loop of radius R so that can complete the loop?

Detailed Solution for NEET Minor Test - 2 - Question 10
The minimum velocity with which a body of mass m must enter a vertical loop of radius R so that can complete the loop = √5gR
NEET Minor Test - 2 - Question 11

The heart of a man pump s 5 litres of blood through the arteries per minute at a pressure of 150 mm of mercury. If the density of mercury be 13. × 103kg/m3 and g=10m/s2 then the power of heart in watt is

Detailed Solution for NEET Minor Test - 2 - Question 11
Here, Volume of blood pumped by man’s heart,

V = 5 litres = 5 × 10−3m3 (∵ 1 litre =10−3m3)

Time in which this volume of blood pumps,

t = 1 min = 60 s

Pressure at which the blood pumps,

P = 150mm of Hg = 0.15 m of Hg

=

(∵ P = hρg)

∴ Power of the heart = PV / t

=

= 1.70W

NEET Minor Test - 2 - Question 12

On a frictionless surface, a block of mass M moving at speed v collides elastically with another block of same mass M which is initially at rest. After collision the first block moves at an angle 0 to its initial direction and has a speed v/3. The second block's speed after the collision

Detailed Solution for NEET Minor Test - 2 - Question 12
The situation is shown in the figure.

Let V be speed of second block after the collision.

As the collision is elastic, so kinetic energy is conserved.

According to conservation of kinetic energy,

NEET Minor Test - 2 - Question 13

Two particles of masses m1,m2 move with initial velocities u1 and u2.On collision, one of the particles get excited to higher level, after absorbing energy e. If final velocities of particles be v1 and v2 then we must have

Detailed Solution for NEET Minor Test - 2 - Question 13

Using energy conservation principle:

Initial energy is only in form of kinetic energy

final energy is in form of kinetic energy and potential energy ( excitation energy)

equation (i) and (ii)

Hence correct answer is option A.

NEET Minor Test - 2 - Question 14

A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three pieces. Two pieces, each of mass (m) move perpendicular to each other with equal speeds (v). The total kinetic energy generated due to explosion is

Detailed Solution for NEET Minor Test - 2 - Question 14
pi = pf

NEET Minor Test - 2 - Question 15

A particle with total energy E is moving in a potential energy region U(x). Motion of the particle is restricted to the region when

Detailed Solution for NEET Minor Test - 2 - Question 15

As the particle is moving in a potential energy region.

∴ Kinetic energy > 0

And, total energy E = K.E. + P.E

⇒ U(x) < E

NEET Minor Test - 2 - Question 16

The potential energy of a particle in a force field is

where A and B are positive constants and r is the distance of particle from the center of the field. For stable equilibrium, the distance of the particle is

Detailed Solution for NEET Minor Test - 2 - Question 16
here,

For equilibrium, dU/dr = 0

For stable equilibrium, d2U/dr2 > 0

So for stable equilibrium, the distance of the particle is = 2A/B

NEET Minor Test - 2 - Question 17

Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v and along x-axis. After collision B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction

Detailed Solution for NEET Minor Test - 2 - Question 17

According to law of conservation of linear momentum along x-axis, we get

m1 × 0 + m2 × v = m1v′cosθ

m2v = m1v′cosθ ......(i)

According to law of conservation of linear momentum long y-axis, we get

Divide (ii) by (i), we get

tanθ = −1/2 or θ = tan−1(−1/2) to the x-axis

NEET Minor Test - 2 - Question 18

The potential energy of a system increases if work is done

Detailed Solution for NEET Minor Test - 2 - Question 18
When work is done upon a system by a conservative force then its potential energy increases.
NEET Minor Test - 2 - Question 19

A particle of mass m is released from rest and follows a parabolic path as shown. Assuming that the displacement of the mass from the origin is small, which graph correctly depicts the position of the particle as a function of time?

Detailed Solution for NEET Minor Test - 2 - Question 19
When the displacement of the mass from the origin is small, this

graph correctly depicts the position of the particle as a function of time.

NEET Minor Test - 2 - Question 20

A mass m moving horizontally (along the x-axis) with velocity v collides and sticks to a mass of 3m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is

Detailed Solution for NEET Minor Test - 2 - Question 20

According to conservation of momentum, we get

where v′ is the final velocity after collision

NEET Minor Test - 2 - Question 21

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness t/4. The relation between the moments of inertia IA and IB is

Detailed Solution for NEET Minor Test - 2 - Question 21

NEET Minor Test - 2 - Question 22

A solid homogeneous sphere is moving on a rough horizontal surface, partly rolling and partly sliding. During this kind of motion of the sphere

Detailed Solution for NEET Minor Test - 2 - Question 22
Angular momentum about point of contact is conserved because torque due to friction about point of contact will be zero.
NEET Minor Test - 2 - Question 23

A sphere of mass m and radius r rolls on a horizontal plane without slipping with the speed u. Now, if it rolls up vertically, the maximum height it would attain will be

Detailed Solution for NEET Minor Test - 2 - Question 23
The rolling sphere has rotational as well as translational kinetic energy.

∴ Kinetic energy =

From conservation of energy

NEET Minor Test - 2 - Question 24

The wheels on the old-time bicycle shown in the diagram have radii of 60.0 cm. and 10.0 cm. If the larger wheel is rotating at 12.0 rad s-1, what is the angular speed of the smaller wheel?

Detailed Solution for NEET Minor Test - 2 - Question 24
The linear velocity of both wheels will be the same

60 × 12 = 10×ω

ω = 72 rad s−1

NEET Minor Test - 2 - Question 25

Angular momentum is conserved

Detailed Solution for NEET Minor Test - 2 - Question 25
According to the law of conservation of angular momentum, if there is no external torque on the system, then the angular momentum remains constant.
NEET Minor Test - 2 - Question 26

If the earth shrinks such that its mass does not change but radius decreases to one-quarter of its original value then one complete day will take

Detailed Solution for NEET Minor Test - 2 - Question 26
We know that angular momentum of the spin = Iω

By the conservation of angular momentum

NEET Minor Test - 2 - Question 27

A solid sphere rolls down two different inclined planes of same height, but of different inclinations. In both cases,

Detailed Solution for NEET Minor Test - 2 - Question 27
In pure rolling, mechanical energy remains conserved. Therefore, when heights of inclines are equal, speed of sphere will be same in both the cases. But as acceleration down the plane, a ∝ sinθ therefore, acceleration and time of descent will be different
NEET Minor Test - 2 - Question 28

The angular speed of rotating rigid body is increased from 4ω to 5ω keeping moment of inertia constant. The percentage increase in its K.E is -

Detailed Solution for NEET Minor Test - 2 - Question 28

% increase K.E. =

NEET Minor Test - 2 - Question 29

The radius of a solid sphere is R and its density D. When it is made to rotate about an axis passing through any diameter of sphere, expression for its moment of inertia is

Detailed Solution for NEET Minor Test - 2 - Question 29

NEET Minor Test - 2 - Question 30

The equation τ = Iα is valid about which of the following?

Detailed Solution for NEET Minor Test - 2 - Question 30
The equation τ = Iα is valid about COM or axis of rotation but not about any other point.
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