JEE  >  JEE Main & Advanced Mock Test Series  >  Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block Download as PDF

Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block


Test Description

25 Questions MCQ Test JEE Main & Advanced Mock Test Series | Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block

Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block for JEE 2022 is part of JEE Main & Advanced Mock Test Series preparation. The Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block questions and answers have been prepared according to the JEE exam syllabus.The Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block MCQs are made for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block below.
Solutions of Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block questions in English are available as part of our JEE Main & Advanced Mock Test Series for JEE & Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block solutions in Hindi for JEE Main & Advanced Mock Test Series course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study JEE Main & Advanced Mock Test Series for JEE Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you?
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 1

Which of the following alkenes will react fastest with  under catalytic hydrogenation conditions

Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 2

The heat of hydrogenation of 1-hexene is 126 . When a second double bond is introduced in the molecule, the heat of hydrogenation of the resulting compound is 230  . The resulting compound (diene) is

Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 2 The Diene thus formed is more stable than the initial compound (and rest of the options) due to conjugation (a conjugated diene). Hence the heat of hydrogenation is more as the product will be a thermodynamically controlled one ie a TCP.
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 3

Heat of hydrogenation of benzene is 51 kcal/mol and its resonance energy is 36 kcal/mol. Then the heats of hydrogenation of cyclohexadiene and cyclohexene per mole respectively are

Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 4
 is adsorbed on palladium surface.It is a case of
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 5

The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is

Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 6
When 0.532 g of benzene (B.P.  C) is burnt in a constant volume system with an excess of oxygen, 22.3 KJ of heat is given out.  for the combustion process is given by :
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 7
The heat released when  & HCl neutralize is :
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 8
The heat of formation of  is 380 kcals/mole and that of  is 195 kcals/mole. The heat (in kcals/mole) of the thermite reaction is
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 9
Enthalpy of Rhombic sulphur of C is
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 10
In the gaseous equilibrium

the formation of  will be favored by
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 11

The  for the decomposition of  (if its degree of dissociation under one atomic pressure is 90%) is

Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 11 So2cl2---so2+cl2
1. 0. 0
1-.90. .90. .90
total moles at equill. = 1.90
xso2 =.90/1.90 xcl2=.90/1.90 xso2cl2= .10/1.90

kp = pso2 *pcl2 /pso2cl2
kp = .90*.90/1.90*.10 = 4.26
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 12
The pH of  HCl is
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 13
If the maximum concentration of  in water is 0.01M at 298K, its maximum concentration in 0.1M NaCl will be
Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 13
Pbcl2 = pb +2 + 2 cl - S S 2s 
Ksp = s * (2s)^2 
Ksp = 0.01 * (4 * 10^-4) 
Ksp = 4*10^-6 
Let solubility in Nacl be s’ Pbcl2 = pb + 2cl S’ S’ 2s’ + 0.1 
Neglecting 2s’ Ksp remains same 4*10^-6 = s’ * (0.1) ^2 
By solving this S’ = 4 * 10^-4
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 14

In a reversible chemical reaction at equilibrium, if the concentration of any one of the reactants is doubled, then the equilibrium constant will

Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 15
Ammonium hydrogen sulphide is contained in a closed vessel at 313 K when total pressure at equilibrium is found to be 0.8 atm. The value of Kp for the reaction
    
Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 15 If dissociation of NH4HS is x then at equilibrium,

2x=0.8 ( Using PV= nRT you can equate partial pressure to total pressure.)
so, x= 0.4 atm.
Then Kp= [P]²= (0.4)²=0.16
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 16
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 17
Reaction of ethene with  in  gives
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 18
The major product obtained when isobutane is treated with chlorine in the presence of light is
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 19
The compound contains atoms X,Y,Z. The oxidation number of X is 2, Y is 5 and Z is –2, a possible formula of the compound is
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 20

 acts as

*Answer can only contain numeric values
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 21

Enthalpy of neutralization of H3PO3 acid is –106.68 KJ/mole using NaOH. If enthalpy of neutralization of HCl by NaOH is –55.84 KJ/mole. Calculate ΔHionisation of H3PO3 into its ions. (in KJ)


Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 21

H3PO3 → 2H+ + HPO3–2

2H+ + 2OH → 2H2O
ΔH = –55.84 × 2 = –116.68
Now
–106.68 = ΔHion – 55.84 × 2
ΔHion = 5KJ/mol

*Answer can only contain numeric values
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 22

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :


Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 22

*Answer can only contain numeric values
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 23

100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.


Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 23

*Answer can only contain numeric values
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 24

What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH (pH = 12.0)?


Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 24

*Answer can only contain numeric values
Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 25

How many grams of NH4Cl should be dissolved per litre of solution to have a pH of 5.13 ? Kb for NH3 is 1.8 × 10–5.


Detailed Solution for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block - Question 25

NH4Cl  is a salt of strong acid and weak base for solutions of such salts.
pH = 1/2 [pK– log C – pKb]
⇒ 10.26 = 14 – log C – 4.74
⇒ log C = 9.26 – 10.26 = –1.0
∴ C = 10–1 M
[NH4Cl] = 10–1 M
= 10–1 × 53.5 gL–1
= 5.35 gL–1

Use Code STAYHOME200 and get INR 200 additional OFF
Use Coupon Code
Information about Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block Page
In this test you can find the Exam questions for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block solved & explained in the simplest way possible. Besides giving Questions and answers for Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block, EduRev gives you an ample number of Online tests for practice