Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block


25 Questions MCQ Test Mock Test Series for JEE Main & Advanced 2021 | Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block


Description
This mock test of Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block for JEE helps you for every JEE entrance exam. This contains 25 Multiple Choice Questions for JEE Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block (mcq) to study with solutions a complete question bank. The solved questions answers in this Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block quiz give you a good mix of easy questions and tough questions. JEE students definitely take this Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block exercise for a better result in the exam. You can find other Chemistry Test 2 - Equilibrium I And II, Thermodynamics, Hydrogen, Hydrocarbons, Redox, States Of Matter, P-Block extra questions, long questions & short questions for JEE on EduRev as well by searching above.
QUESTION: 1

Which of the following alkenes will react fastest with  under catalytic hydrogenation conditions

Solution:
QUESTION: 2

The heat of hydrogenation of 1-hexene is 126 . When a second double bond is introduced in the molecule, the heat of hydrogenation of the resulting compound is 230  . The resulting compound (diene) is

Solution: The Diene thus formed is more stable than the initial compound (and rest of the options) due to conjugation (a conjugated diene). Hence the heat of hydrogenation is more as the product will be a thermodynamically controlled one ie a TCP.
QUESTION: 3

Heat of hydrogenation of benzene is 51 kcal/mol and its resonance energy is 36 kcal/mol. Then the heats of hydrogenation of cyclohexadiene and cyclohexene per mole respectively are

Solution:
QUESTION: 4
 is adsorbed on palladium surface.It is a case of
Solution:
QUESTION: 5

The enthalpy of fusion of water is 1.435 kcal/mol. The molar entropy change for the melting of ice at 0°C is

Solution:
QUESTION: 6
When 0.532 g of benzene (B.P.  C) is burnt in a constant volume system with an excess of oxygen, 22.3 KJ of heat is given out.  for the combustion process is given by :
Solution:
QUESTION: 7
The heat released when  & HCl neutralize is :
Solution:
QUESTION: 8
The heat of formation of  is 380 kcals/mole and that of  is 195 kcals/mole. The heat (in kcals/mole) of the thermite reaction is
Solution:
QUESTION: 9
Enthalpy of Rhombic sulphur of C is
Solution:
QUESTION: 10
In the gaseous equilibrium

the formation of  will be favored by
Solution:
QUESTION: 11

The  for the decomposition of  (if its degree of dissociation under one atomic pressure is 90%) is

Solution: So2cl2---so2+cl2
1. 0. 0
1-.90. .90. .90
total moles at equill. = 1.90
xso2 =.90/1.90 xcl2=.90/1.90 xso2cl2= .10/1.90

kp = pso2 *pcl2 /pso2cl2
kp = .90*.90/1.90*.10 = 4.26
QUESTION: 12
The pH of  HCl is
Solution:
QUESTION: 13
If the maximum concentration of  in water is 0.01M at 298K, its maximum concentration in 0.1M NaCl will be
Solution:
Pbcl2 = pb +2 + 2 cl - S S 2s 
Ksp = s * (2s)^2 
Ksp = 0.01 * (4 * 10^-4) 
Ksp = 4*10^-6 
Let solubility in Nacl be s’ Pbcl2 = pb + 2cl S’ S’ 2s’ + 0.1 
Neglecting 2s’ Ksp remains same 4*10^-6 = s’ * (0.1) ^2 
By solving this S’ = 4 * 10^-4
QUESTION: 14

In a reversible chemical reaction at equilibrium, if the concentration of any one of the reactants is doubled, then the equilibrium constant will

Solution:
QUESTION: 15
Ammonium hydrogen sulphide is contained in a closed vessel at 313 K when total pressure at equilibrium is found to be 0.8 atm. The value of Kp for the reaction
    
Solution: If dissociation of NH4HS is x then at equilibrium,

2x=0.8 ( Using PV= nRT you can equate partial pressure to total pressure.)
so, x= 0.4 atm.
Then Kp= [P]²= (0.4)²=0.16
QUESTION: 16
Reactivity of hydrogen atoms attached to different carbon atoms in alkanes has the order
Solution:
QUESTION: 17
Reaction of ethene with  in  gives
Solution:
QUESTION: 18
The major product obtained when isobutane is treated with chlorine in the presence of light is
Solution:
QUESTION: 19
The compound contains atoms X,Y,Z. The oxidation number of X is 2, Y is 5 and Z is –2, a possible formula of the compound is
Solution:
QUESTION: 20

 acts as

Solution:
*Answer can only contain numeric values
QUESTION: 21

Enthalpy of neutralization of H3PO3 acid is –106.68 KJ/mole using NaOH. If enthalpy of neutralization of HCl by NaOH is –55.84 KJ/mole. Calculate ΔHionisation of H3PO3 into its ions. (in KJ)


Solution:

H3PO3 → 2H+ + HPO3–2

2H+ + 2OH → 2H2O
ΔH = –55.84 × 2 = –116.68
Now
–106.68 = ΔHion – 55.84 × 2
ΔHion = 5KJ/mol

*Answer can only contain numeric values
QUESTION: 22

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of0.1 N NaOH required to completely neutralise 10 mL of this solution is :


Solution:

*Answer can only contain numeric values
QUESTION: 23

100 mL of 0.6 M acetic acid is shaken with 2 g activated carbon. The final concentration of the solution after adsorption is 0.5 M. What is the amount of acetic acid adsorbed per gram of carbon.


Solution:

*Answer can only contain numeric values
QUESTION: 24

What will be the resultant pH when 150 mL of an aqueous solution of HCl (pH = 2.0) is mixed with 350 mL of an aqueous solution of NaOH (pH = 12.0)?


Solution:

*Answer can only contain numeric values
QUESTION: 25

How many grams of NH4Cl should be dissolved per litre of solution to have a pH of 5.13 ? Kb for NH3 is 1.8 × 10–5.


Solution:

NH4Cl  is a salt of strong acid and weak base for solutions of such salts.
pH = 1/2 [pK– log C – pKb]
⇒ 10.26 = 14 – log C – 4.74
⇒ log C = 9.26 – 10.26 = –1.0
∴ C = 10–1 M
[NH4Cl] = 10–1 M
= 10–1 × 53.5 gL–1
= 5.35 gL–1