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A load of mass M kg is suspended from a steel wire of length 2 m and radius 1.0 mm in Searle's apparatus experiment. The increase in length produced in the wire is 4.0 mm. Now the load is fully immersed in a liquid of relative density 2. The relative density of the material of load is 8. The new value of increase in length of the steel wire is :
...(1)
T = mg
T = mg – f_{B}
From (1)
Formation of real image using a biconvex lens is shown below :
If the whole set up is immersed in water without disturbing the object and the screen position, what will one observe on the screen?
From
Focal length of lens will change hence image disappears from the screen.
A vertical closed cylinder is separated into two parts by a frictionless piston of mass m and of negligible thickness. The piston is free to move along the length of the cylinder. The length of the cylinder above the piston is ℓ_{1}, and that below the piston is ℓ_{2} , such that ℓ_{1} > ℓ_{2}. Each part of the cylinder contains n moles of an ideal gas at equal temperature T. If the piston is stationary, its mass, m, will be given by : (R is universal gas constant and g is the acceleration due to gravity)
A simple harmonic motion is represented by:
The amplitude and time period of the motion are:
In the given circuit diagram, the currents , I_{1} =–0.3A, I_{4} = 0.8 A and I_{5} = 0.4 A, are flowing as shown. The currents I_{2},I_{3} and I_{6},respectively, are :
A particle of mass 20 g is released with an initial velocity 5 m/s along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be : (Take g= 10 m/s^{2})
Work Energy Theorem from A to B
Angular momentum about 0
In the above circuit, Current in LR_{1} path is I_{1}_{ }and in CR_{2} path it is I_{2}. The voltage of A.C source is given by volts. The phase difference between I_{1} and I_{2} is :
So phase difference comes out 90 + 60 = 150.
Therefore Ans. is Bonus If R_{2} is 20 KΩ then phase difference comes out to be 60+30 = 90°
A paramagnetic material has 10^{28}atoms/m^{3}. Its magnetic susceptibility at temperature 350 K is 2.8 ×10^{–4}. Its susceptibility at 300 K is :
curie law for paramagnetic substane
A 10 m long horizontal wire extends from North East to South West. It is falling with a speed of 5.0ms^{–1}, at right angles to the horizontal component of the earth's magnetic field, of 0.3 × l0^{–4}Wb/m^{2}.The value of the induced emf in wire is :
In the figure, given that V_{BB} supply can vary from 0 to 5.0 V, V_{CC} = 5V, β_{dc} = 200, R_{B} = 100 kW, R_{C}=l kΩ and V_{BE}=1.0 V, The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively :
given
In the circuit shown, find C if the effective capacitance of the whole circuit is to be 0.5 μF.
All values in the circuit are in μF.
Two satellites, A and B, have masses m and 2m respectively. A is in a circular orbit of radius R, and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, T_{A}/T_{B}, is:
The moment of inertia of a solid sphere, about an axis parallel to its diameter and at a distance of x from it, is I(x)'. Which one of the graphs represents the variation of I(x) with x correctlv?
When a certain photo sensistive surface is illuminated with monochromatic light of frequency n, the stopping potential for the photo current is  V_{0}/2. When the surface is illuminated by monochromatic light of frequency v/2, the stopping potential is V_{0}. The threshold frequency for photoelectric emission is:
A galvanometer, whose resistance is 50 ohm, has 25 divisions in it. When a current of 4 ×10^{–4} A passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range 2.5 V, it should be connected to a resistance of:
A long cylindrical vessel is half filled with a liquid. When the vessel is rotated about its own vertical axis, the liquid rises up near the wall. If the radius of vessel is 5 cm and its rotational speed is 2 rotations per second, then the difference in the heights between the centre and the sides, in cm, will be:
Two particles A, B are moving on two concentric circles of radii R_{1} and R_{2} with equal angular speed ω. At t = 0, their positions and direction of motion are shown in the figure :
The relative velocity is given by:
A planoconvex lens (focal length f_{2}, refractive index μ_{2}, radius of curvature R) fits exactly into a planoconcave lens (focal length f_{1}, refractive index μ_{1}, radius of curvature R). Their plane surfaces are parallel to each other. Then, the focal length of the combination will be :
Let ℓ, r, c and v represent inductance, resistance, capacitance and voltage, respectively. The dimension of in SI units will be:
In a radioactive decay chain, the initial nucleus is . At the end there are 6 αparticles and 4 βparticles which are emitted. If the end nucleus, If , A and Z are given by :
The mean intensity of radiation on the surface of the Sun is about 108 W/m^{2}. The rms value of the corresponding magnetic field is closest to :
A resonance tube is old and has jagged end. It is still used in the laboratory to determine velocity of sound in air. A tuning fork of frequency 512 Hz produces first resonance when the tube is filled with water to a mark 11 cm below a reference mark, near the open end of the tube. The experiment is repeated with another fork of frequency 256 Hz which produces first resonance when water reaches a mark 27 cm below the reference mark.
The velocity of sound in air, obtained in the experiment, is close to:
An ideal gas is enclosed in a cylinder at pressure of 2 atm and temperature, 300 K. The mean time between two successive collisions is 6 × 10^{–8} s.If the pressure is doubled and temperature is increased to 500 K, the mean time between two successive collisions will be close to:
The charge on a capacitor plate in a circuit, as a function of time, is shown in the figure: What is the value of current at t = 4s ?
since
Therefore current = 0
A block kept on a rough inclined plane, as shown in the figure, remaias at rest upto a maximum force 2 N down the inclined plane. The maximum external force up the inclined plane that does not move the block is 10 N. The coefficient of static friction betwreen the block and the plane is : [Take g = 10 m/s^{2}]
2 + mg sin30 = µmg cos30°
10 = mgsin 30 + µ mg cos30°
= 2µmg cos30 –2
6 = µmg cos 30
4 = mg sin 30
An alpha  particle of mass m suffer s 1dimensional elastic coolision with a nucleus at rest of unknown mass. It is scattered directly backwards losing, 64% of its initial kinetic energy.The mass of the nucleus is :
A soap bubble, blown by a mechanical pump at the mouth of a tube, increases in volume, with time, at a constant rate. The graph that correctly depicts the time dependence of pressure inside the bubble is given by :
To double the coverging range of a TV transmittion tower, its height should be multiplied by :
Range
To double the range h have to be made 4 times
A parallel plate capacitor with plates of area 1m^{2} each, are at a separation of 0.1 m. If the electric field between the plates is 100 N/C, the magnitude of charge each plate is :
In a FrankHertz experiment, an electron of energy 5.6 eV passes through mercury vapour and emerges with an energy 0.7 eV. The minimum wavelength of photons emitted by mercury atoms is close to :
An open vessel at 27°C is heated until two fifth of the air (assumed as an ideal gas) in it has escaped from the vessel. Assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is
Initial number of moles of an ideal gas = n_{1}
Find number of moles of the ideal gas
At constant volume and pressure, the number of moles of an ideal gas is inversely proportional to temperature
Given
Based on the above thermochemical equations, find out which one of the following algebraic relationships is correct?
According to Hess’s law, the enthalpy change of a reaction does not depend on the number of steps involved in the reaction.
** in reaction ii, Product should be CO (gas) instead of CO_{2} (gas).
The increasing order of the reactivity of the following with LiAlH_{4} is
The reactivity order of carboxylic acid derivatives depends on the leaving tendency of the leaving group. Higher the leaving tendency of the leaving group, higher will be the reactivity of the compound.
Therefore, reactivity order towards LiAlH_{4} is
Acid halide > Acid anhydride > Ester > Amide
Among the following, the false statement is
Latex is colloidal solution of rubber particles which are negatively charged.
The major product of the following reaction is
High temperature and strong base favours elimination reaction forming more stable alkene according to Saytzeff rule.
The magnetic moment of an octahedral homoleptic Mn(II) complex is 5.9 BM. The suitable ligand for this complex is
Electronic configuration of Mn^{2+} is
Mn^{+2} : 3d^{5}
It has 5 unpaired electrons which corresponds to magnetic moment of This shows that the homoleptic complex of Mn2+ has only weak field ligands and that is NCS^{–}. The remaining three ligands are strong field ligands.
The major product of the following reaction is
NaBH_{4} does not reduces the double bond in β  γ unsaturated aldehydes/ ketones.
Only the keto group will be reduced.
If K_{sp} of Ag_{2}CO_{3} is 8 × 10^{–12}, the molar solubility of Ag_{2}CO_{3} in 0.1 M AgNO_{3} is
for NaCl, HCl and NaA are 126.4, 425.9 and 100.5 S cm^{2}mol^{–1}, respectively. If the conductivity of 0.001 M HA is 5 × 10^{–5} S cm^{–1}, degree of dissociation of HA is
(NaCl) = 126.4 S cm^{2} mol^{–1}
(HCl) = 425.9 S cm^{2} mol^{–1}
(NaA) = 100.5 S cm^{2} mol^{–1}
(HA) = 425.9 – 126.4 + 100.5 = 400 S cm^{2} mol^{–1}
K(HA) = 5 × 10^{–5} S cm^{–1}
The major product of the following reaction is
The aldehydes which will not form Grignard product with one equivalent Grignard reagent are
Grignard reagent will not react with aldehydes if it has a functional group which contains acidic hydrogen. Options (B) and (D) have —COOH and — CH_{2}OH respectively which contan acidic Hatom.
For a reaction, consider the plot of In k versus 1/T given in the figure. If the rate constant of this reaction at 400 K is 10^{–5} s^{–1}, then the rate constant at 500 K is
⇒ K_{2} = 10K_{1} = 10^{–5} × 10 = 10^{–4} S^{–1}
The major product of the following reaction is
The compound that is NOT a common component of photochemical smog is:
CF_{2}Cl_{2} is not a common component of photochemical smog.
The major product in the following conversion is
The major product of the following reaction is
Molecules of benzoic acid (C_{6}H_{5}COOH) dimerise in benzene. ‘w’ g of the acid dissolved in 30 g of benzene shows a depression in freezing point equal to 2 K. If the percentage association of the acid to form dimer in the solution is 80, then w is
(Given that K_{f} = 5 K kg mol^{–1}, Molar mass of benzoic acid = 122 g mol^{–1})
Moles at equilibrium = 1 – 2α + α = 1  α
2α = 0.8, α = 0.4
Moles at equilibrium = 0.6
i = 0.6
Chlorine on reaction with hot and concentrated sodium hydroxide gives
3Cl_{2} + 6NaOH → 5NaCl + NaClO_{3} + 3H_{2}O
The correct statement(s) among I to III with respect to potassium ions that are abundant within the cell fluids is/are I. They activate many enzymes
II. They participate in the oxidation of glucose to produce ATP
III. Along with sodium ions, they are responsible for the transmission of nerve signals
K^{+} ions act as carriers for nerve signals, are activators for many enzymes and participate in the oxidation of glucose to form ATP.
If the de Broglie wavelength of the electron in nth Bohr orbit in a hydrogenic atom is equal to 1.5 pa0 (a_{0} is Bohr radius), then the value of n/z is
The volume strength of 1M H_{2}O_{2} is (Molar mass of H_{2}O_{2} = 34 g mol^{–1})
Volume strength ≈ 11.2 × M
≈ 11.2
The correct order of atomic radii is
Atomic radii follows the order
The element that does NOT show catenation is
Lead Pb
The two monomers for the synthesis of nylon 6, 6 are
Monomer of Nylon–6, 6 are adipic acid and hexamethylene diammine.
The pair that does NOT require calcination is
ZnO and MgO
They are oxides while other are carbonates or hydrated oxides which require calcination.
The upper stratosphere consisting of the ozone layer protects us from the sun’s radiation that falls in the wavelength region of
Ozone layer protects from ultra violet radiation.
∴ Wavelength range lies in 200 – 315 nm
The combination of plots which does not represent isothermal expansion of an ideal gas is
(B) and (D) are not correct representation for isothermal expansion of ideal gas.
8 g of NaOH is dissolved in 18 g of H_{2}O. Mole fraction of NaOH in solution and molality (in mol kg^{–1}) of the solution respectively are
The element that shows greater ability to form pπ – pπ multiple bonds, is
Carbon has small size so effective, lateral overlapping between 2p and 2p.
The correct structure of histidine in a strongly acidic solution (pH = 2) is
Histidine (in strongly acidic solution)
Let Z be the set of integers. If and , then the number of subsets of the set A × B, is :
A × B has is 15 elements so number of subsets of A × B is 2^{15}.
If ; is equal to :
given that
If an angle between the line, and the plane, x – 2y – kz = 3 is then a value of k is:
DR's of line are 2, 1, –2
normal vector of plane is
...1
... 2
If a straight line passing thourgh the point P(–3, 4) is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is :
equation of line is 4x – 3y + 24 = 0
The integral is equal to :
(where C is a constant of integration)
There are m men and two women participating in a chess tournament. Each participant plays two games with every other participant. If the number of games played by the men between themselves exceeds the number of games played between the men and the women by 84, then the value of m is :
Let mmen, 2women
m^{2} – 5m – 84 = 0 ⇒ (m – 12) (m + 7) = 0 m = 12
If the function f given by f(x) = x^{3} –3(a – 2)x^{2} + 3ax + 7, for some a∈R is increasing in (0, 1] and decreasing in [1, 5), then a root of the equation,
Let f be a differentiable function such that f(1) = 2 and f'(x) = f(x) for all x∈ R. If h(x) = f(f(x)),then h'(1) is equal to :
Intergrate & use f(1) = 2
The tangent to the curve y = x2 – 5x + 5, parallel to the line 2y = 4x + 1, also passes through the point.
Equation of tangent at
Now check options
Let S be the set of all real values of λ such that a plane passing through the points (–λ^{2}, 1, 1), (1, –λ^{2}, 1) and (1, 1, –λ^{2}) also passes through the point (–1, –1, 1). Then S is equal to :
All four points are coplaner so
If a circle of radius R passes through the origin O and intersects the coordinate axes at A and B, then the locus of the foot of perpendicular from O on AB is :
Slope of AB = h/k
Equation of AB is hx + ky = h^{2} + k^{2}
AB = 2R
⇒ (h^{2} + k^{2})^{3} = 4R^{2}h^{2}k^{2}
⇒ (x^{2} + y^{2})^{3} = 4R^{2}x^{2}y^{2}
The equeation of a tangent to the parabola , x^{2} = 8y, which makes an angle θ with the positive direction of xaxis, is :
Equation of tangent :
y – 2tan^{2}θ = tan θ (x – 4tan θ)
⇒ x = y cot θ + 2 tan θ
If the angle of elevation of a cloud from a point P which is 25 m above a lake be 30º and the angle of depression of reflection of the cloud in the lake from P be 60º, then the height of the cloud (in meters) from the surface of the lake is :
..(1)
∴ Height of cloud from surface = 25+25 = 50m
The integral is equal to :
is equal to :
The set of all values of λ for which the system of linear equations.
x – 2y – 2z = λx
x + 2y + z = λy
–x – y = λz
has a nontrivial solution.
If ^{n}C_{4}, ^{n}C_{5} and ^{n}C_{6} are in A.P., then n can be :
Let be three unit vectors, out of which vectors are nonparallel. If α and β are the angles which vector makes with vectors respectively and then α  β is equal to :
(All given vectors are unit vectors)
If then for all lies in the interval :
The expression is logically equvalent to :
The total number of irrational terms in the binomial expansion of (7^{1/ 5}  3^{1/10} )^{60} is:
General term
∴ for rational term, r = 0, 10, 20, 30, 40, 50, 60
⇒ no of rational terms = 7
∴ number of irrational terms = 54
The mean and the variance of five observation are 4 and 5.20, respectively. If three of the observations are 3, 4 and 4; then then absolute value of the difference of the other two observations, is :
Using (i) and (ii) (x_{4} – x_{5})^{2} = 49
x_{4} – x_{5} = 7
If the sum of the first 15 tems of the series is equal to 225 k, then k is equal to :
Let S and S' be the foci of the ellipse and B be any one of the extremities of its minor axis. If ΔS'BS is a right angled triangle with right angle at B and area (ΔS'BS) = 8 sq. units, then the length of a latus rectum of the ellipse is :
m_{SB} . m_{S'B} = –1
In a class of 60 students, 40 opted for NCC, 30 opted for NSS and 20 opted for both NCC and NSS. If one of these students is selected at random, then the probability that the student selected has opted neither for NCC nor for NSS is :
A →opted NCC
B →opted NSS
The number of integral values of m for which the quadratic expression. (1 + 2m)x^{2} – 2(1 + 3m)x + 4(1 + m), x∈R, is always positive, is :
Exprsssion is always positve it
∴ Common interval is
∴ Intgral value of m {0,1,2,3,4,5,6}
In a game, a man wins Rs. 100 if he gets 5 of 6 on a throw of a fair die and loses Rs. 50 for getting any other number on the die. If he decides to throw the die either till he gets a five or a six or to a maximum of three throws, then his expected gain/ loss (in rupees) is :
Expected Gain/ Loss =
= w × 100 + Lw (–50 + 100) + L^{2}w (–50 –50 + 100) + L^{3} (–150)
here w denotes probability that outcome 5 or 6 (w = 2/6 = 1/3)
here L denotes probability that outcome
If a curve passes through the point (1, –2) and has slope of the tangent at any point (x, y) on it as then the curve also passes through the point :
hence bpasses through (1, –2) ⇒C = 9/4
Now check option(s) , Which is satisly by option (ii)
Let Z_{1} and Z_{2} be two complex numbers satisfying Z_{1} = 9 and Z_{2}–3–4i=4 . Then the minimum value of Z_{1}–Z_{2} is :
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