JEE  >  JEE Main & Advanced Mock Test Series  >  JEE Main Chemistry Mock - 1 Download as PDF

JEE Main Chemistry Mock - 1


Test Description

25 Questions MCQ Test JEE Main & Advanced Mock Test Series | JEE Main Chemistry Mock - 1

JEE Main Chemistry Mock - 1 for JEE 2022 is part of JEE Main & Advanced Mock Test Series preparation. The JEE Main Chemistry Mock - 1 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Chemistry Mock - 1 MCQs are made for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Chemistry Mock - 1 below.
Solutions of JEE Main Chemistry Mock - 1 questions in English are available as part of our JEE Main & Advanced Mock Test Series for JEE & JEE Main Chemistry Mock - 1 solutions in Hindi for JEE Main & Advanced Mock Test Series course. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free. Attempt JEE Main Chemistry Mock - 1 | 25 questions in 60 minutes | Mock test for JEE preparation | Free important questions MCQ to study JEE Main & Advanced Mock Test Series for JEE Exam | Download free PDF with solutions
1 Crore+ students have signed up on EduRev. Have you?
JEE Main Chemistry Mock - 1 - Question 1

Alcohols of low molecular weight are

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 1

Alcohols are soluble in water. This is due to the hydroxyl group in the alcohol which is able to form hydrogen bonds with water molecules. Alcohols with a smaller hydrocarbon chain are very soluble. As the length of the hydrocarbon chain increases, the solubility in water decreases.

JEE Main Chemistry Mock - 1 - Question 2

Benzyl alcohol is obtained from benzaldehyde by

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 2

       

JEE Main Chemistry Mock - 1 - Question 3

The main structure features of proteins is

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 3

The chemical bond formed between amino acids, constituting the primary linkagein all protein structures. In a peptide bond, the carboxyl group (COOH) of one amino acid bonds with the amino group (NH2) of another, forming the sequence CONH and releasing water (H2O).

JEE Main Chemistry Mock - 1 - Question 4

Chemical equilibrium is dynamic in nature, because

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 4

A chemical equilibrium is dynamic in nature which in other words means that reactions continue to occur in both forward as well as backward direction with the same speed. As a result, the amount of product formed immediately reacts backward to give reactants and so there is no change in concentration of reactant or product with the passage of time.

JEE Main Chemistry Mock - 1 - Question 5

The indicator that is obtained by coupling the diazonium salt of sulphanilic acid with N,N-dimethylaniline is

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 5

 

JEE Main Chemistry Mock - 1 - Question 6

The standard e.m.f. of a galvanic cell, with standard electrode potentials of zinc equal to -0.76 V and that of copper equal to + 0.34 V, is

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 6

Ecell = E right - E left
= E•Cu2+/Cu - E•Zn2+/Zn
= (+0.34v) - (-0.76v)
=0.34+0.76
=1.1v

JEE Main Chemistry Mock - 1 - Question 7

Which of the following is not true for the order of a reaction?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 7

Correct option is A)

If rate is given by: rate =k[A]x[B]y

then the order =x+y.

This order can be a positive, negative no., zero or even fractional. It can be determined only experimentally and does not depend on stoichiometric coefficients of reactants.

JEE Main Chemistry Mock - 1 - Question 8

When 10gram of methane is completely burnt in oxygen, the heat evolved is 560kJ. What is the heat of combustion (in kJ/mole) of methane?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 8

The chemical formula for methane is CH4 and its molecular mass is calculated as the sum of Mass of the carbon atom and Mass of hydrogen atoms. The molar mass of carbon is 12g/mol and the mass of hydrogen atom is 1g. Therefore, the Molar mass of methane is:
12+4×1=16g/mol
As we know, 10 gram of methane on combustion gives 560 KJ of heat. So 1 gram of methane on combustion gives = 560/10KJ of heat.

Hence, 16 gram of methane on combustion give=560/10×16=896KJ

Thus the heat of combustion of methane is -896KJ/mol. Therefore, the negative sign in the answer.

JEE Main Chemistry Mock - 1 - Question 9

Which of the following is most electronegative?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 9

The electronegativity values for the representative elements decreses down a group because of the increase in atomic radius as well as screening effect. Thus, carbon has highest electronegativity in a group.

JEE Main Chemistry Mock - 1 - Question 10

The catalyst used for the polymerization of olefins is

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 10

A Ziegler–Natta catalyst, named after Karl Ziegler and Giulio Natta, is a catalyst used in the synthesis of polymers of 1-alkenes (alpha-olefins).

JEE Main Chemistry Mock - 1 - Question 11

When one Faraday current is passed which of the following would deposit one gram atomic weight of the metal?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 11

Hint: For Na+, GEW=GAW

JEE Main Chemistry Mock - 1 - Question 12

A white salt is readily solubule in water and gives a colourless solution with a pH of about 9. The salt would be

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 12

CH₃COONa undergoes anionic hydrolysis and gives basic solution (pH ≈ 9

JEE Main Chemistry Mock - 1 - Question 13

The pH of a solution of hydrochloric acid is 4. The molarity of this solution is

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 13

The pH of a solution is equal to the base 10 logarithm of the H+ concentration, multiplied by -1. If you know the pH of a water solution, you can use this formula in reverse to find the antilogarithm and calculate the H+ concentration in that solution.

JEE Main Chemistry Mock - 1 - Question 14

Which of the following is least acidic?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 14

o-cresol (o−(CH3​)C6​H4​−(OH)) is least acidic.  −OH group and C​H3​ groups are electron releasing group. It increases the electron density on a benzene ring and does not delocalize the negative charge of phenoxide ion.

 

Hence, it decreases the acidity of phenol. −Cl and −NO2​ groups are electron-withdrawing groups. They delocalize the electron density of phenoxide ion. It increases the acidity of phenol.

JEE Main Chemistry Mock - 1 - Question 15

Which one of the following can be considered as weak electrolyte ?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 15

 CH3COOH does not ionise or dissociate completely and hence it is a weak electrolyte.

JEE Main Chemistry Mock - 1 - Question 16

Which of the following is not a Lewis acid ?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 16

Lewis Acid is one that accepts electrons. So, usually a compound with positive charge would be acid. Also, a compound with empty orbitals. 


 

Lewis Base is one that donates electrons. So, usually a compound with negative charge would be considered base. Also, a compound with lone pairs. 
 

SiF4​,FeCl3​ and BF3​ are lewis acids becuase all these compounds are having vacant orbitals to accept electon pairs
 

C2​H2​ is not a lewis acid.It's a Lewis base, as it can use a pair of electrons from the pi bond to donate to a Lewis acid.
 

Hence option A is correct.

JEE Main Chemistry Mock - 1 - Question 17

Which is not true about polymers?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 17

A polymer sample contains chains of varying lengths and therefore molecular mass is always expressed as an average.The molecular weight of polymers are very high,due to which they are expressed in two ways:-

Number average molecular mass and weight average molecular mass.

JEE Main Chemistry Mock - 1 - Question 18

A solid cube has CsCl type structure. If the edge length of the unit cell is 404 pm, what is the distance between A⁺ and B⁻ ions?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 18

In CsCl structure the distance the closest approach between the cation and anion is equal to half of the body of the diagonal of a cube.
Body diagonal = 3–√×3× Edge Length

=3–√×404

=699.74pm
The distance of the closest approach = 1/2× Body diagonal
=1/2×699.74 = 349.87 pm = 349.9pm

JEE Main Chemistry Mock - 1 - Question 19

Which of the following has maximum Schottky defect?

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 19

More comparable the size of anion and cation, more is the chance of Schottky defect and Naand Cl- ions are almost comparable in size hence m ore probability to show  Schottky defect.

JEE Main Chemistry Mock - 1 - Question 20

 Select the correct statement regarding the aromatic nitrogen molecule

Detailed Solution for JEE Main Chemistry Mock - 1 - Question 20

In pyrrole, the lone pair of electrons belonging to the nitrogen is part of the aromatic ring. However, in pyridine it is part of an sp2-hybridized orbital.

*Answer can only contain numeric values
JEE Main Chemistry Mock - 1 - Question 21


Number of possible self aldol condensation product on heating with NaOH?


Detailed Solution for JEE Main Chemistry Mock - 1 - Question 21


*Answer can only contain numeric values
JEE Main Chemistry Mock - 1 - Question 22

 

Among the following the total number of elements which produce H2 gas with NaOH is Zn, Al, Sn, Pb, P, S


Detailed Solution for JEE Main Chemistry Mock - 1 - Question 22

Zn + 2NaOH → Na2ZnO2 + H
2AI + 2NaOH + H2O → 2NaAlO2 + 3H
Sn + 2NaOH + H2O → NaSnO3 + 2H2­ 
Pb + 2NaOH + H2O → Na2SiO3 + 2H2 ↑
S8 + 12NaOH — → 4Na2S + 4Na2S2O3 + 6H2O ↑
P4 + 3NaOH + 3H2O → PH3­↑ + 3NaH2PO2­

*Answer can only contain numeric values
JEE Main Chemistry Mock - 1 - Question 23

An organic compound P contains 62.07% carbon and 10.34% hydrogen and rest oxygen. Its vapour density is 29. This compound does not react with sodium metal, but its 2.9 g combines with X g of bromine (to give dibromo addition product). Find out value of (Y–X). (Where Y is total number of possible isomers of given organic compound P) 
[Atomic mass : Br = 80]


Detailed Solution for JEE Main Chemistry Mock - 1 - Question 23

Molecular formula from calculation comes to be C3H6O i.e., it stands for the following compounds.

VD × 2 = MM
= 29 × 2 = 58
∴ 58 g of ether combines with 2 × 80g Br2
∴  2.9 g of ether will combines with 

Y = 9 and X = 8
Y – X = 9 – 8 = 1

*Answer can only contain numeric values
JEE Main Chemistry Mock - 1 - Question 24

 

How many of the following reagent/s will liberate at least one oxide of nitrogen as a product ?
(i) Ag + conc. HNO3
(ii) Sn + dil., HNO3 (20%)
(iii) Cu + conc. HNO3 
(iv) C + conc. HNO3
(v) Zn + conc, HNO3
(vi) Zn + dil. HNO3 (20%)
(vii) P4 + conc. HNO3
(viii) S8 + conc. HNO3
(ix) Cu + dil. HNO3 (20%)


Detailed Solution for JEE Main Chemistry Mock - 1 - Question 24

(i) give NO2        (ii) NH4NO3
(iii) gives NO2     (iv) Give NO2
(v) give NO2          (vi) Given N2O    
(vii) Gives NO2     (viii) Gives NO2    
(ix) Gives NO

*Answer can only contain numeric values
JEE Main Chemistry Mock - 1 - Question 25

 

In white phosphorous (P4) if
x is total number of triangle
y is total number of plane of symmetry z is total number of P–P bond
then calculate value of (y + z)/x.


Detailed Solution for JEE Main Chemistry Mock - 1 - Question 25

x = 4
y = 6
z = 6
Ans. (3)

Use Code STAYHOME200 and get INR 200 additional OFF
Use Coupon Code
Information about JEE Main Chemistry Mock - 1 Page
In this test you can find the Exam questions for JEE Main Chemistry Mock - 1 solved & explained in the simplest way possible. Besides giving Questions and answers for JEE Main Chemistry Mock - 1, EduRev gives you an ample number of Online tests for practice