JEE Main Chemistry Mock Test- 2 - JEE MCQ

Salicylic acid gives wintergreen smell with methyl alcohol and H₂SO₄ to form Methyl salicylate.

Benzyl alcohol does not have the CH₃CO- group or CH₃CH₂O^- so it will not give the positive iodoform test.

Phospholipids are esters of glycerol with two carboxylic acid residue and one phosphate group. Hence, phospholipids may be regarded as derivative of glycerol in which two hydroxyl group are esterified with a fatty acid, while third is esterified with phosphoric acid.

• Splitting of spectral lines under the influence of magnetic field is called Zeeman effect.
• In stark effect spectral lines split due to electricity.
• In photoelectric effect the splitting of spectral line takes place as the light falls on the metal.

Fe⁺³ has 5 unpaired electrons, more than other ones.

Hyperconjugation effect in Alkyl group:

In graphite, each carbon atom uses only 3 of its 4 outer energy level electron in covalently bonding to there other carbon atoms in a place. In graphite, electrons are spread out between the structure.

It has got sp2 hybridization, giving it a planar structure.Further backbonding from flouine makes the B-F bonds stronger than normal single bonds.

• XeF2 contains sp3d hybridized Xe atom with three lone pairs of electrons.
• Fluorine atoms occupy axial positions while three lone pairs of electrons occupy equatorial positions in trigonal bipyramid.
• Since the lone pair of electrons does not consider for the shape of the molecule, thus, the shape of XeF2 comes out to be linear.
• While C -atom of CO2 is sp hybridised and thus, possesses a linear shape.

Optical isomers of cis-[Co(en)₂Cl₂] :

Applying sum of individual charge = charge on molecule
x+(0)×4 + (-1)×2 = +1
x=3

The Mond process, sometimes known as the carbonyl process, is a technique created by Ludwig Mond in 1890, to extract and purify nickel. The process was used commercially before the end of the 19th century. This process converts nickel oxides into pure nickel.

Helium is the least polarizable noble gas due to presence of weakest Van der Waal's forces.

The longest chain has 7 carbons, making it a hept- root.

The chain contains a double bond (ene) and a triple bond (yne).

Number the chain to give the double and triple bonds the lowest possible locants. In this case, numbering from the left gives the double bond at carbon 5 and the triple bond at carbon 1.

So, we have a hept-5-en-1-yne backbone.

Chloro group at carbon 6.

Ethyl group at carbon 4.

Methyl group at carbon 5.

Assemble the name with the substituents in alphabetical order, followed by the main chain name

6-Chloro-4-ethyl-5-methyl hept-1-yn-5-ene

When hydrogen chloride gas (HCl) is circulated through the saturated solution.
HCl and NaCl dissociate into their respective ions as:

NaCl → Na⁺ + Cl^-

HCl → H⁺ + Cl^-

The concentration of Cl− ions increases considerably in solution due to ionization HCl. 

Hence, the ionic product [Na+][Cl−] exceeds the solubility product of sodium chloride and, therefore, pure sodium chloride precipitates out from the solution.

• Optical isomerism (such as enantiomers and diastereoisomers) and geometric isomerism (cis trans isomerism) represents stereoisomerism.
• Stereoisomers have the same molecular formula and same connectivity of atoms, but differ in the orientations of atoms.
• Chain isomerism, position isomerism and functional group isomerism represents structural isomerism. 

Calcium and zinc both belong to the same period, i.e Period 4

Natural rubber is from the monomer cis-isoprene (2-methyl-1,3-butadiene).
It is an addition polymer that is obtained as a milky white fluid known as latex from a tropical rubber tree. 

Alkali metals can readily lose their lone electron to form +1 oxidation state and can easily ionize this electron and this ns1 configuration results in alkali metals to have large ionic and atomic radii and they have high second ionization energy. This ionization energy decreases down the group and act as strong reducing agent.

For non-ideal solution, ΔV_mix ​< 0.

Final volume decreases due to negative deviation from original volume 125 ml.
Hence, total volume will be little less than (100 + 25 = 125 mL).

N₂O, C₂H₂, CO₂, C₃O₂, BeF₂

• The compound shows several carbon atoms attached to various groups.
• To be a chiral center, a carbon must have four different groups attached to it.

Upon re-inspection of the structure, there are 3 chiral centers in this compound.

So, the correct number of chiral centers is 3.